Metamath Proof Explorer


Theorem odadd

Description: The order of a product is the product of the orders, if the factors have coprime order. (Contributed by Mario Carneiro, 20-Oct-2015)

Ref Expression
Hypotheses odadd1.1 ⊢ O = od ⁡ G
odadd1.2 ⊢ X = Base G
odadd1.3 ⊢ + ˙ = + G
Assertion odadd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B = O ⁡ A ⁢ O ⁡ B

Proof

Step Hyp Ref Expression
1 odadd1.1 ⊢ O = od ⁡ G
2 odadd1.2 ⊢ X = Base G
3 odadd1.3 ⊢ + ˙ = + G
4 simpl1 ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → G ∈ Abel
5 ablgrp ⊢ G ∈ Abel → G ∈ Grp
6 4 5 syl ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → G ∈ Grp
7 simpl2 ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → A ∈ X
8 simpl3 ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → B ∈ X
9 2 3 grpcl ⊢ G ∈ Grp ∧ A ∈ X ∧ B ∈ X → A + ˙ B ∈ X
10 6 7 8 9 syl3anc ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → A + ˙ B ∈ X
11 2 1 odcl ⊢ A + ˙ B ∈ X → O ⁡ A + ˙ B ∈ ℕ 0
12 10 11 syl ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ∈ ℕ 0
13 2 1 odcl ⊢ A ∈ X → O ⁡ A ∈ ℕ 0
14 7 13 syl ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A ∈ ℕ 0
15 2 1 odcl ⊢ B ∈ X → O ⁡ B ∈ ℕ 0
16 8 15 syl ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ B ∈ ℕ 0
17 14 16 nn0mulcld ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A ⁢ O ⁡ B ∈ ℕ 0
18 simpr ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A gcd O ⁡ B = 1
19 18 oveq2d ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B = O ⁡ A + ˙ B ⋅ 1
20 12 nn0cnd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ∈ ℂ
21 20 mulridd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ⋅ 1 = O ⁡ A + ˙ B
22 19 21 eqtrd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B = O ⁡ A + ˙ B
23 1 2 3 odadd1 ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X → O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B ∥ O ⁡ A ⁢ O ⁡ B
24 23 adantr ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B ∥ O ⁡ A ⁢ O ⁡ B
25 22 24 eqbrtrrd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ∥ O ⁡ A ⁢ O ⁡ B
26 1 2 3 odadd2 ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X → O ⁡ A ⁢ O ⁡ B ∥ O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B 2
27 26 adantr ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A ⁢ O ⁡ B ∥ O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B 2
28 18 oveq1d ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A gcd O ⁡ B 2 = 1 2
29 sq1 ⊢ 1 2 = 1
30 28 29 eqtrdi ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A gcd O ⁡ B 2 = 1
31 30 oveq2d ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B 2 = O ⁡ A + ˙ B ⋅ 1
32 31 21 eqtrd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B ⁢ O ⁡ A gcd O ⁡ B 2 = O ⁡ A + ˙ B
33 27 32 breqtrd ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A ⁢ O ⁡ B ∥ O ⁡ A + ˙ B
34 dvdseq ⊢ O ⁡ A + ˙ B ∈ ℕ 0 ∧ O ⁡ A ⁢ O ⁡ B ∈ ℕ 0 ∧ O ⁡ A + ˙ B ∥ O ⁡ A ⁢ O ⁡ B ∧ O ⁡ A ⁢ O ⁡ B ∥ O ⁡ A + ˙ B → O ⁡ A + ˙ B = O ⁡ A ⁢ O ⁡ B
35 12 17 25 33 34 syl22anc ⊢ G ∈ Abel ∧ A ∈ X ∧ B ∈ X ∧ O ⁡ A gcd O ⁡ B = 1 → O ⁡ A + ˙ B = O ⁡ A ⁢ O ⁡ B