Metamath Proof Explorer


Theorem oexpneg

Description: The exponential of the negative of a number, when the exponent is odd. (Contributed by Mario Carneiro, 25-Apr-2015) (Proof shortened by AV, 10-Jul-2022)

Ref Expression
Assertion oexpneg ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N → − A N = − A N

Proof

Step Hyp Ref Expression
1 nnz ⊢ N ∈ ℕ → N ∈ ℤ
2 odd2np1 ⊢ N ∈ ℤ → ¬ 2 ∥ N ↔ ∃ n ∈ ℤ 2 ⁢ n + 1 = N
3 1 2 syl ⊢ N ∈ ℕ → ¬ 2 ∥ N ↔ ∃ n ∈ ℤ 2 ⁢ n + 1 = N
4 3 biimpa ⊢ N ∈ ℕ ∧ ¬ 2 ∥ N → ∃ n ∈ ℤ 2 ⁢ n + 1 = N
5 4 3adant1 ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N → ∃ n ∈ ℤ 2 ⁢ n + 1 = N
6 simpl1 ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A ∈ ℂ
7 simprr ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 2 ⁢ n + 1 = N
8 simpl2 ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → N ∈ ℕ
9 8 nncnd ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → N ∈ ℂ
10 1cnd ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 1 ∈ ℂ
11 2z ⊢ 2 ∈ ℤ
12 simprl ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → n ∈ ℤ
13 zmulcl ⊢ 2 ∈ ℤ ∧ n ∈ ℤ → 2 ⁢ n ∈ ℤ
14 11 12 13 sylancr ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 2 ⁢ n ∈ ℤ
15 14 zcnd ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 2 ⁢ n ∈ ℂ
16 9 10 15 subadd2d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → N − 1 = 2 ⁢ n ↔ 2 ⁢ n + 1 = N
17 7 16 mpbird ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → N − 1 = 2 ⁢ n
18 nnm1nn0 ⊢ N ∈ ℕ → N − 1 ∈ ℕ 0
19 8 18 syl ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → N − 1 ∈ ℕ 0
20 17 19 eqeltrrd ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 2 ⁢ n ∈ ℕ 0
21 6 20 expcld ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n ∈ ℂ
22 21 6 mulneg2d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n ⁢ − A = − A 2 ⁢ n ⁢ A
23 sqneg ⊢ A ∈ ℂ → − A 2 = A 2
24 6 23 syl ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 = A 2
25 24 oveq1d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 n = A 2 n
26 6 negcld ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A ∈ ℂ
27 2rp ⊢ 2 ∈ ℝ +
28 27 a1i ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 2 ∈ ℝ +
29 12 zred ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → n ∈ ℝ
30 20 nn0ge0d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 0 ≤ 2 ⁢ n
31 28 29 30 prodge0rd ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 0 ≤ n
32 elnn0z ⊢ n ∈ ℕ 0 ↔ n ∈ ℤ ∧ 0 ≤ n
33 12 31 32 sylanbrc ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → n ∈ ℕ 0
34 2nn0 ⊢ 2 ∈ ℕ 0
35 34 a1i ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → 2 ∈ ℕ 0
36 26 33 35 expmuld ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n = − A 2 n
37 6 33 35 expmuld ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n = A 2 n
38 25 36 37 3eqtr4d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n = A 2 ⁢ n
39 38 oveq1d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n ⁢ − A = A 2 ⁢ n ⁢ − A
40 26 20 expp1d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n + 1 = − A 2 ⁢ n ⁢ − A
41 7 oveq2d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n + 1 = − A N
42 40 41 eqtr3d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n ⁢ − A = − A N
43 39 42 eqtr3d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n ⁢ − A = − A N
44 22 43 eqtr3d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n ⁢ A = − A N
45 6 20 expp1d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n + 1 = A 2 ⁢ n ⁢ A
46 7 oveq2d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n + 1 = A N
47 45 46 eqtr3d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → A 2 ⁢ n ⁢ A = A N
48 47 negeqd ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A 2 ⁢ n ⁢ A = − A N
49 44 48 eqtr3d ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N ∧ n ∈ ℤ ∧ 2 ⁢ n + 1 = N → − A N = − A N
50 5 49 rexlimddv ⊢ A ∈ ℂ ∧ N ∈ ℕ ∧ ¬ 2 ∥ N → − A N = − A N