Theorem opabid2ss

Description: One direction of opabid2 which holds without a Rel A requirement. (Contributed by Thierry Arnoux, 18-Feb-2022)

	Ref	Expression
Assertion	opabid2ss	$$⊢\left\{⟨x,y⟩|⟨x,y⟩\in A\right\}\subseteq A$$

Proof

Step	Hyp	Ref	Expression
1		id	$$⊢⟨x,y⟩\in A\to ⟨x,y⟩\in A$$
2	1	opabssi	$$⊢\left\{⟨x,y⟩|⟨x,y⟩\in A\right\}\subseteq A$$