Metamath Proof Explorer


Theorem ople0

Description: An element less than or equal to zero equals zero. ( chle0 analog.) (Contributed by NM, 21-Oct-2011)

Ref Expression
Hypotheses op0le.b ⊢ B = Base K
op0le.l ⊢ ≤ ˙ = ≤ K
op0le.z ⊢ 0 ˙ = 0. ⁡ K
Assertion ople0 ⊢ K ∈ OP ∧ X ∈ B → X ≤ ˙ 0 ˙ ↔ X = 0 ˙

Proof

Step Hyp Ref Expression
1 op0le.b ⊢ B = Base K
2 op0le.l ⊢ ≤ ˙ = ≤ K
3 op0le.z ⊢ 0 ˙ = 0. ⁡ K
4 1 2 3 op0le ⊢ K ∈ OP ∧ X ∈ B → 0 ˙ ≤ ˙ X
5 4 biantrud ⊢ K ∈ OP ∧ X ∈ B → X ≤ ˙ 0 ˙ ↔ X ≤ ˙ 0 ˙ ∧ 0 ˙ ≤ ˙ X
6 opposet ⊢ K ∈ OP → K ∈ Poset
7 6 adantr ⊢ K ∈ OP ∧ X ∈ B → K ∈ Poset
8 simpr ⊢ K ∈ OP ∧ X ∈ B → X ∈ B
9 1 3 op0cl ⊢ K ∈ OP → 0 ˙ ∈ B
10 9 adantr ⊢ K ∈ OP ∧ X ∈ B → 0 ˙ ∈ B
11 1 2 posasymb ⊢ K ∈ Poset ∧ X ∈ B ∧ 0 ˙ ∈ B → X ≤ ˙ 0 ˙ ∧ 0 ˙ ≤ ˙ X ↔ X = 0 ˙
12 7 8 10 11 syl3anc ⊢ K ∈ OP ∧ X ∈ B → X ≤ ˙ 0 ˙ ∧ 0 ˙ ≤ ˙ X ↔ X = 0 ˙
13 5 12 bitrd ⊢ K ∈ OP ∧ X ∈ B → X ≤ ˙ 0 ˙ ↔ X = 0 ˙