Metamath Proof Explorer


Theorem oppne3

Description: Points lying on opposite sides of a line cannot be equal. (Contributed by Thierry Arnoux, 3-Aug-2020)

Ref Expression
Hypotheses hpg.p ⊢ P = Base G
hpg.d ⊢ - ˙ = dist ⁡ G
hpg.i ⊢ I = Itv ⁡ G
hpg.o ⊢ O = a b | a ∈ P ∖ D ∧ b ∈ P ∖ D ∧ ∃ t ∈ D t ∈ a I b
opphl.l ⊢ L = Line 𝒢 ⁡ G
opphl.d ⊢ φ → D ∈ ran ⁡ L
opphl.g ⊢ φ → G ∈ 𝒢 Tarski
oppcom.a ⊢ φ → A ∈ P
oppcom.b ⊢ φ → B ∈ P
oppcom.o ⊢ φ → A O B
Assertion oppne3 ⊢ φ → A ≠ B

Proof

Step Hyp Ref Expression
1 hpg.p ⊢ P = Base G
2 hpg.d ⊢ - ˙ = dist ⁡ G
3 hpg.i ⊢ I = Itv ⁡ G
4 hpg.o ⊢ O = a b | a ∈ P ∖ D ∧ b ∈ P ∖ D ∧ ∃ t ∈ D t ∈ a I b
5 opphl.l ⊢ L = Line 𝒢 ⁡ G
6 opphl.d ⊢ φ → D ∈ ran ⁡ L
7 opphl.g ⊢ φ → G ∈ 𝒢 Tarski
8 oppcom.a ⊢ φ → A ∈ P
9 oppcom.b ⊢ φ → B ∈ P
10 oppcom.o ⊢ φ → A O B
11 1 2 3 4 5 6 7 8 9 10 oppne1 ⊢ φ → ¬ A ∈ D
12 7 ad3antrrr ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → G ∈ 𝒢 Tarski
13 8 ad3antrrr ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → A ∈ P
14 6 ad3antrrr ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → D ∈ ran ⁡ L
15 simplr ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → t ∈ D
16 1 5 3 12 14 15 tglnpt ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → t ∈ P
17 simpr ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → t ∈ A I B
18 simpllr ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → A = B
19 18 oveq2d ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → A I A = A I B
20 17 19 eleqtrrd ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → t ∈ A I A
21 1 2 3 12 13 16 20 axtgbtwnid ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → A = t
22 21 15 eqeltrd ⊢ φ ∧ A = B ∧ t ∈ D ∧ t ∈ A I B → A ∈ D
23 1 2 3 4 8 9 islnopp ⊢ φ → A O B ↔ ¬ A ∈ D ∧ ¬ B ∈ D ∧ ∃ t ∈ D t ∈ A I B
24 10 23 mpbid ⊢ φ → ¬ A ∈ D ∧ ¬ B ∈ D ∧ ∃ t ∈ D t ∈ A I B
25 24 simprd ⊢ φ → ∃ t ∈ D t ∈ A I B
26 25 adantr ⊢ φ ∧ A = B → ∃ t ∈ D t ∈ A I B
27 22 26 r19.29a ⊢ φ ∧ A = B → A ∈ D
28 11 27 mtand ⊢ φ → ¬ A = B
29 28 neqned ⊢ φ → A ≠ B