Metamath Proof Explorer


Theorem opswap

Description: Swap the members of an ordered pair. (Contributed by NM, 14-Dec-2008) (Revised by Mario Carneiro, 30-Aug-2015)

Ref Expression
Assertion opswap ⊢ ⋃ A B -1 = B A

Proof

Step Hyp Ref Expression
1 cnvsng ⊢ A ∈ V ∧ B ∈ V → A B -1 = B A
2 1 unieqd ⊢ A ∈ V ∧ B ∈ V → ⋃ A B -1 = ⋃ B A
3 opex ⊢ B A ∈ V
4 3 unisn ⊢ ⋃ B A = B A
5 2 4 eqtrdi ⊢ A ∈ V ∧ B ∈ V → ⋃ A B -1 = B A
6 uni0 ⊢ ⋃ ∅ = ∅
7 opprc ⊢ ¬ A ∈ V ∧ B ∈ V → A B = ∅
8 7 sneqd ⊢ ¬ A ∈ V ∧ B ∈ V → A B = ∅
9 8 cnveqd ⊢ ¬ A ∈ V ∧ B ∈ V → A B -1 = ∅ -1
10 cnvsn0 ⊢ ∅ -1 = ∅
11 9 10 eqtrdi ⊢ ¬ A ∈ V ∧ B ∈ V → A B -1 = ∅
12 11 unieqd ⊢ ¬ A ∈ V ∧ B ∈ V → ⋃ A B -1 = ⋃ ∅
13 ancom ⊢ A ∈ V ∧ B ∈ V ↔ B ∈ V ∧ A ∈ V
14 opprc ⊢ ¬ B ∈ V ∧ A ∈ V → B A = ∅
15 13 14 sylnbi ⊢ ¬ A ∈ V ∧ B ∈ V → B A = ∅
16 6 12 15 3eqtr4a ⊢ ¬ A ∈ V ∧ B ∈ V → ⋃ A B -1 = B A
17 5 16 pm2.61i ⊢ ⋃ A B -1 = B A