Metamath Proof Explorer


Theorem orrd

Description: Deduce disjunction from implication. (Contributed by NM, 27-Nov-1995)

Ref Expression
Hypothesis orrd.1 φ ¬ ψ χ
Assertion orrd φ ψ χ

Proof

Step Hyp Ref Expression
1 orrd.1 φ ¬ ψ χ
2 pm2.54 ¬ ψ χ ψ χ
3 1 2 syl φ ψ χ