Metamath Proof Explorer


Theorem osumcllem10N

Description: Lemma for osumclN . Contradict osumcllem9N . (Contributed by NM, 25-Mar-2012) (New usage is discouraged.)

Ref Expression
Hypotheses osumcllem.l ⊢ ≤ ˙ = ≤ K
osumcllem.j ⊢ ∨ ˙ = join ⁡ K
osumcllem.a ⊢ A = Atoms ⁡ K
osumcllem.p ⊢ + ˙ = + 𝑃 ⁡ K
osumcllem.o ⊢ ⊥ ˙ = ⊥ 𝑃 ⁡ K
osumcllem.c ⊢ C = PSubCl ⁡ K
osumcllem.m ⊢ M = X + ˙ p
osumcllem.u ⊢ U = ⊥ ˙ ⁡ ⊥ ˙ ⁡ X + ˙ Y
Assertion osumcllem10N ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → M ≠ X

Proof

Step Hyp Ref Expression
1 osumcllem.l ⊢ ≤ ˙ = ≤ K
2 osumcllem.j ⊢ ∨ ˙ = join ⁡ K
3 osumcllem.a ⊢ A = Atoms ⁡ K
4 osumcllem.p ⊢ + ˙ = + 𝑃 ⁡ K
5 osumcllem.o ⊢ ⊥ ˙ = ⊥ 𝑃 ⁡ K
6 osumcllem.c ⊢ C = PSubCl ⁡ K
7 osumcllem.m ⊢ M = X + ˙ p
8 osumcllem.u ⊢ U = ⊥ ˙ ⁡ ⊥ ˙ ⁡ X + ˙ Y
9 simp11 ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → K ∈ HL
10 simp2 ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → p ∈ A
11 10 snssd ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → p ⊆ A
12 simp12 ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → X ⊆ A
13 3 4 sspadd2 ⊢ K ∈ HL ∧ p ⊆ A ∧ X ⊆ A → p ⊆ X + ˙ p
14 9 11 12 13 syl3anc ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → p ⊆ X + ˙ p
15 vex ⊢ p ∈ V
16 15 snss ⊢ p ∈ X + ˙ p ↔ p ⊆ X + ˙ p
17 14 16 sylibr ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → p ∈ X + ˙ p
18 17 7 eleqtrrdi ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → p ∈ M
19 3 4 sspadd1 ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A → X ⊆ X + ˙ Y
20 19 3ad2ant1 ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → X ⊆ X + ˙ Y
21 simp3 ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → ¬ p ∈ X + ˙ Y
22 20 21 ssneldd ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → ¬ p ∈ X
23 nelne1 ⊢ p ∈ M ∧ ¬ p ∈ X → M ≠ X
24 18 22 23 syl2anc ⊢ K ∈ HL ∧ X ⊆ A ∧ Y ⊆ A ∧ p ∈ A ∧ ¬ p ∈ X + ˙ Y → M ≠ X