Metamath Proof Explorer


Theorem oveq2d

Description: Equality deduction for operation value. (Contributed by NM, 13-Mar-1995)

Ref Expression
Hypothesis oveq1d.1 φ A = B
Assertion oveq2d φ C F A = C F B

Proof

Step Hyp Ref Expression
1 oveq1d.1 φ A = B
2 oveq2 A = B C F A = C F B
3 1 2 syl φ C F A = C F B