Metamath Proof Explorer


Theorem ovolge0

Description: The volume of a set is always nonnegative. (Contributed by Mario Carneiro, 16-Mar-2014)

Ref Expression
Assertion ovolge0 ⊢ A ⊆ ℝ → 0 ≤ vol * ⁡ A

Proof

Step Hyp Ref Expression
1 ssrab2 ⊢ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ⊆ ℝ *
2 0xr ⊢ 0 ∈ ℝ *
3 infxrgelb ⊢ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ⊆ ℝ * ∧ 0 ∈ ℝ * → 0 ≤ inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * < ↔ ∀ x ∈ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < 0 ≤ x
4 1 2 3 mp2an ⊢ 0 ≤ inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * < ↔ ∀ x ∈ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < 0 ≤ x
5 eqid ⊢ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < = y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * <
6 5 ovolmge0 ⊢ x ∈ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < → 0 ≤ x
7 4 6 mprgbir ⊢ 0 ≤ inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * <
8 5 ovolval ⊢ A ⊆ ℝ → vol * ⁡ A = inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * <
9 7 8 breqtrrid ⊢ A ⊆ ℝ → 0 ≤ vol * ⁡ A