Metamath Proof Explorer


Theorem ovolshft

Description: The Lebesgue outer measure function is shift-invariant. (Contributed by Mario Carneiro, 22-Mar-2014) (Proof shortened by AV, 17-Sep-2020)

Ref Expression
Hypotheses ovolshft.1 ⊢ φ → A ⊆ ℝ
ovolshft.2 ⊢ φ → C ∈ ℝ
ovolshft.3 ⊢ φ → B = x ∈ ℝ | x − C ∈ A
Assertion ovolshft ⊢ φ → vol * ⁡ A = vol * ⁡ B

Proof

Step Hyp Ref Expression
1 ovolshft.1 ⊢ φ → A ⊆ ℝ
2 ovolshft.2 ⊢ φ → C ∈ ℝ
3 ovolshft.3 ⊢ φ → B = x ∈ ℝ | x − C ∈ A
4 eqid ⊢ z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * < = z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * <
5 1 2 3 4 ovolshftlem2 ⊢ φ → y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ⊆ z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * <
6 ssrab2 ⊢ x ∈ ℝ | x − C ∈ A ⊆ ℝ
7 3 6 eqsstrdi ⊢ φ → B ⊆ ℝ
8 2 renegcld ⊢ φ → − C ∈ ℝ
9 1 2 3 shft2rab ⊢ φ → A = w ∈ ℝ | w − − C ∈ B
10 eqid ⊢ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < = y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * <
11 7 8 9 10 ovolshftlem2 ⊢ φ → z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * < ⊆ y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * <
12 5 11 eqssd ⊢ φ → y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < = z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * <
13 12 infeq1d ⊢ φ → inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * < = inf z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * < ℝ * <
14 10 ovolval ⊢ A ⊆ ℝ → vol * ⁡ A = inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * <
15 1 14 syl ⊢ φ → vol * ⁡ A = inf y ∈ ℝ * | ∃ f ∈ ≤ ∩ ℝ 2 ℕ A ⊆ ⋃ ran ⁡ . ∘ f ∧ y = sup ran ⁡ seq 1 + abs ∘ − ∘ f ℝ * < ℝ * <
16 4 ovolval ⊢ B ⊆ ℝ → vol * ⁡ B = inf z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * < ℝ * <
17 7 16 syl ⊢ φ → vol * ⁡ B = inf z ∈ ℝ * | ∃ g ∈ ≤ ∩ ℝ 2 ℕ B ⊆ ⋃ ran ⁡ . ∘ g ∧ z = sup ran ⁡ seq 1 + abs ∘ − ∘ g ℝ * < ℝ * <
18 13 15 17 3eqtr4d ⊢ φ → vol * ⁡ A = vol * ⁡ B