Metamath Proof Explorer


Theorem padd02

Description: Projective subspace sum with an empty set. (Contributed by NM, 11-Jan-2012)

Ref Expression
Hypotheses padd0.a ⊢ A = Atoms ⁡ K
padd0.p ⊢ + ˙ = + 𝑃 ⁡ K
Assertion padd02 ⊢ K ∈ B ∧ X ⊆ A → ∅ + ˙ X = X

Proof

Step Hyp Ref Expression
1 padd0.a ⊢ A = Atoms ⁡ K
2 padd0.p ⊢ + ˙ = + 𝑃 ⁡ K
3 simpl ⊢ K ∈ B ∧ X ⊆ A → K ∈ B
4 0ss ⊢ ∅ ⊆ A
5 4 a1i ⊢ K ∈ B ∧ X ⊆ A → ∅ ⊆ A
6 simpr ⊢ K ∈ B ∧ X ⊆ A → X ⊆ A
7 3 5 6 3jca ⊢ K ∈ B ∧ X ⊆ A → K ∈ B ∧ ∅ ⊆ A ∧ X ⊆ A
8 neirr ⊢ ¬ ∅ ≠ ∅
9 8 intnanr ⊢ ¬ ∅ ≠ ∅ ∧ X ≠ ∅
10 1 2 paddval0 ⊢ K ∈ B ∧ ∅ ⊆ A ∧ X ⊆ A ∧ ¬ ∅ ≠ ∅ ∧ X ≠ ∅ → ∅ + ˙ X = ∅ ∪ X
11 7 9 10 sylancl ⊢ K ∈ B ∧ X ⊆ A → ∅ + ˙ X = ∅ ∪ X
12 uncom ⊢ ∅ ∪ X = X ∪ ∅
13 un0 ⊢ X ∪ ∅ = X
14 12 13 eqtri ⊢ ∅ ∪ X = X
15 11 14 eqtrdi ⊢ K ∈ B ∧ X ⊆ A → ∅ + ˙ X = X