Metamath Proof Explorer


Theorem pell14qrdich

Description: A positive Pell solution is either in the first quadrant, or its reciprocal is. (Contributed by Stefan O'Rear, 18-Sep-2014)

Ref Expression
Assertion pell14qrdich ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D

Proof

Step Hyp Ref Expression
1 elpell14qr ⊢ D ∈ ℕ ∖ ◻ ℕ → A ∈ Pell14QR ⁡ D ↔ A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℤ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
2 1 biimpa ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℤ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
3 simplrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → b ∈ ℤ
4 elznn0 ⊢ b ∈ ℤ ↔ b ∈ ℝ ∧ b ∈ ℕ 0 ∨ − b ∈ ℕ 0
5 3 4 sylib ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → b ∈ ℝ ∧ b ∈ ℕ 0 ∨ − b ∈ ℕ 0
6 5 simprd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → b ∈ ℕ 0 ∨ − b ∈ ℕ 0
7 simplr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → A ∈ ℝ
8 7 ad2antrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ b ∈ ℕ 0 → A ∈ ℝ
9 simprl ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a ∈ ℕ 0
10 9 ad2antrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ b ∈ ℕ 0 → a ∈ ℕ 0
11 simpr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ b ∈ ℕ 0 → b ∈ ℕ 0
12 simplr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ b ∈ ℕ 0 → A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
13 rsp2e ⊢ a ∈ ℕ 0 ∧ b ∈ ℕ 0 ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → ∃ a ∈ ℕ 0 ∃ b ∈ ℕ 0 A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
14 10 11 12 13 syl3anc ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ b ∈ ℕ 0 → ∃ a ∈ ℕ 0 ∃ b ∈ ℕ 0 A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
15 8 14 jca ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ b ∈ ℕ 0 → A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℕ 0 A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
16 15 ex ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → b ∈ ℕ 0 → A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℕ 0 A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
17 elpell1qr ⊢ D ∈ ℕ ∖ ◻ ℕ → A ∈ Pell1QR ⁡ D ↔ A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℕ 0 A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
18 17 ad4antr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ∈ Pell1QR ⁡ D ↔ A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℕ 0 A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1
19 16 18 sylibrd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → b ∈ ℕ 0 → A ∈ Pell1QR ⁡ D
20 7 ad2antrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → A ∈ ℝ
21 pell14qrne0 ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ≠ 0
22 21 ad4antr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → A ≠ 0
23 20 22 rereccld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → 1 A ∈ ℝ
24 9 ad2antrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → a ∈ ℕ 0
25 simpr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → − b ∈ ℕ 0
26 pell14qrre ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ∈ ℝ
27 26 recnd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ∈ ℂ
28 27 21 reccld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → 1 A ∈ ℂ
29 28 ad3antrrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → 1 A ∈ ℂ
30 nn0cn ⊢ a ∈ ℕ 0 → a ∈ ℂ
31 30 ad2antrl ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a ∈ ℂ
32 eldifi ⊢ D ∈ ℕ ∖ ◻ ℕ → D ∈ ℕ
33 32 nncnd ⊢ D ∈ ℕ ∖ ◻ ℕ → D ∈ ℂ
34 33 ad3antrrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ∈ ℂ
35 34 sqrtcld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ∈ ℂ
36 zcn ⊢ b ∈ ℤ → b ∈ ℂ
37 36 ad2antll ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → b ∈ ℂ
38 37 negcld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → − b ∈ ℂ
39 35 38 mulcld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ⁢ − b ∈ ℂ
40 31 39 addcld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a + D ⁢ − b ∈ ℂ
41 40 adantr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → a + D ⁢ − b ∈ ℂ
42 27 ad3antrrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ∈ ℂ
43 21 ad3antrrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ≠ 0
44 27 21 recidd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ⁢ 1 A = 1
45 44 ad3antrrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ⁢ 1 A = 1
46 simprr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → a 2 − D ⁢ b 2 = 1
47 45 46 eqtr4d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ⁢ 1 A = a 2 − D ⁢ b 2
48 31 adantr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → a ∈ ℂ
49 35 37 mulcld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ⁢ b ∈ ℂ
50 49 adantr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → D ⁢ b ∈ ℂ
51 subsq ⊢ a ∈ ℂ ∧ D ⁢ b ∈ ℂ → a 2 − D ⁢ b 2 = a + D ⁢ b ⁢ a − D ⁢ b
52 48 50 51 syl2anc ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → a 2 − D ⁢ b 2 = a + D ⁢ b ⁢ a − D ⁢ b
53 35 37 sqmuld ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ⁢ b 2 = D 2 ⁢ b 2
54 34 sqsqrtd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D 2 = D
55 54 oveq1d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D 2 ⁢ b 2 = D ⁢ b 2
56 53 55 eqtr2d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ⁢ b 2 = D ⁢ b 2
57 56 oveq2d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a 2 − D ⁢ b 2 = a 2 − D ⁢ b 2
58 57 adantr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → a 2 − D ⁢ b 2 = a 2 − D ⁢ b 2
59 simpr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → A = a + D ⁢ b
60 35 37 mulneg2d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → D ⁢ − b = − D ⁢ b
61 60 oveq2d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a + D ⁢ − b = a + − D ⁢ b
62 negsub ⊢ a ∈ ℂ ∧ D ⁢ b ∈ ℂ → a + − D ⁢ b = a − D ⁢ b
63 62 eqcomd ⊢ a ∈ ℂ ∧ D ⁢ b ∈ ℂ → a − D ⁢ b = a + − D ⁢ b
64 31 49 63 syl2anc ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a − D ⁢ b = a + − D ⁢ b
65 61 64 eqtr4d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → a + D ⁢ − b = a − D ⁢ b
66 65 adantr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → a + D ⁢ − b = a − D ⁢ b
67 59 66 oveq12d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → A ⁢ a + D ⁢ − b = a + D ⁢ b ⁢ a − D ⁢ b
68 52 58 67 3eqtr4d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b → a 2 − D ⁢ b 2 = A ⁢ a + D ⁢ − b
69 68 adantrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → a 2 − D ⁢ b 2 = A ⁢ a + D ⁢ − b
70 47 69 eqtrd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ⁢ 1 A = A ⁢ a + D ⁢ − b
71 29 41 42 43 70 mulcanad ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → 1 A = a + D ⁢ − b
72 71 adantr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → 1 A = a + D ⁢ − b
73 37 ad2antrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → b ∈ ℂ
74 sqneg ⊢ b ∈ ℂ → − b 2 = b 2
75 73 74 syl ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → − b 2 = b 2
76 75 oveq2d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → D ⁢ − b 2 = D ⁢ b 2
77 76 oveq2d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → a 2 − D ⁢ − b 2 = a 2 − D ⁢ b 2
78 simplrr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → a 2 − D ⁢ b 2 = 1
79 77 78 eqtrd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → a 2 − D ⁢ − b 2 = 1
80 72 79 jca ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → 1 A = a + D ⁢ − b ∧ a 2 − D ⁢ − b 2 = 1
81 oveq2 ⊢ c = − b → D ⁢ c = D ⁢ − b
82 81 oveq2d ⊢ c = − b → a + D ⁢ c = a + D ⁢ − b
83 82 eqeq2d ⊢ c = − b → 1 A = a + D ⁢ c ↔ 1 A = a + D ⁢ − b
84 oveq1 ⊢ c = − b → c 2 = − b 2
85 84 oveq2d ⊢ c = − b → D ⁢ c 2 = D ⁢ − b 2
86 85 oveq2d ⊢ c = − b → a 2 − D ⁢ c 2 = a 2 − D ⁢ − b 2
87 86 eqeq1d ⊢ c = − b → a 2 − D ⁢ c 2 = 1 ↔ a 2 − D ⁢ − b 2 = 1
88 83 87 anbi12d ⊢ c = − b → 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1 ↔ 1 A = a + D ⁢ − b ∧ a 2 − D ⁢ − b 2 = 1
89 88 rspcev ⊢ − b ∈ ℕ 0 ∧ 1 A = a + D ⁢ − b ∧ a 2 − D ⁢ − b 2 = 1 → ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
90 25 80 89 syl2anc ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
91 rspe ⊢ a ∈ ℕ 0 ∧ ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1 → ∃ a ∈ ℕ 0 ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
92 24 90 91 syl2anc ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → ∃ a ∈ ℕ 0 ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
93 23 92 jca ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 ∧ − b ∈ ℕ 0 → 1 A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
94 93 ex ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → − b ∈ ℕ 0 → 1 A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
95 elpell1qr ⊢ D ∈ ℕ ∖ ◻ ℕ → 1 A ∈ Pell1QR ⁡ D ↔ 1 A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
96 95 ad4antr ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → 1 A ∈ Pell1QR ⁡ D ↔ 1 A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ c ∈ ℕ 0 1 A = a + D ⁢ c ∧ a 2 − D ⁢ c 2 = 1
97 94 96 sylibrd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → − b ∈ ℕ 0 → 1 A ∈ Pell1QR ⁡ D
98 19 97 orim12d ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → b ∈ ℕ 0 ∨ − b ∈ ℕ 0 → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D
99 6 98 mpd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ ∧ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D
100 99 ex ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ ∧ a ∈ ℕ 0 ∧ b ∈ ℤ → A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D
101 100 rexlimdvva ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D ∧ A ∈ ℝ → ∃ a ∈ ℕ 0 ∃ b ∈ ℤ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D
102 101 expimpd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ∈ ℝ ∧ ∃ a ∈ ℕ 0 ∃ b ∈ ℤ A = a + D ⁢ b ∧ a 2 − D ⁢ b 2 = 1 → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D
103 2 102 mpd ⊢ D ∈ ℕ ∖ ◻ ℕ ∧ A ∈ Pell14QR ⁡ D → A ∈ Pell1QR ⁡ D ∨ 1 A ∈ Pell1QR ⁡ D