Metamath Proof Explorer


Theorem pellexlem2

Description: Lemma for pellex . Arithmetical core of pellexlem3, norm upper bound. (Contributed by Stefan O'Rear, 14-Sep-2014)

Ref Expression
Assertion pellexlem2 ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 < 1 + 2 ⁢ D

Proof

Step Hyp Ref Expression
1 simpl3 ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B ∈ ℕ
2 1 nnred ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B ∈ ℝ
3 2 resqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ∈ ℝ
4 2 sqge0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 ≤ B 2
5 3 4 absidd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 = B 2
6 5 eqcomd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 = B 2
7 6 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 B 2 = A 2 − D ⁢ B 2 B 2
8 simpl2 ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A ∈ ℕ
9 8 nncnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A ∈ ℂ
10 9 sqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 ∈ ℂ
11 simpl1 ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ∈ ℕ
12 11 nncnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ∈ ℂ
13 1 nncnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B ∈ ℂ
14 13 sqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ∈ ℂ
15 12 14 mulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ⁢ B 2 ∈ ℂ
16 10 15 subcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 ∈ ℂ
17 1 nnne0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B ≠ 0
18 sqne0 ⊢ B ∈ ℂ → B 2 ≠ 0 ↔ B ≠ 0
19 18 biimpar ⊢ B ∈ ℂ ∧ B ≠ 0 → B 2 ≠ 0
20 13 17 19 syl2anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ≠ 0
21 16 14 20 absdivd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 B 2 = A 2 − D ⁢ B 2 B 2
22 7 21 eqtr4d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 B 2 = A 2 − D ⁢ B 2 B 2
23 22 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A 2 − D ⁢ B 2 B 2 = B 2 ⁢ A 2 − D ⁢ B 2 B 2
24 16 abscld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 ∈ ℝ
25 24 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 ∈ ℂ
26 25 14 20 divcan2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A 2 − D ⁢ B 2 B 2 = A 2 − D ⁢ B 2
27 10 15 14 20 divsubdird ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 B 2 = A 2 B 2 − D ⁢ B 2 B 2
28 9 13 17 sqdivd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B 2 = A 2 B 2
29 28 eqcomd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 B 2 = A B 2
30 11 nnred ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ∈ ℝ
31 11 nnnn0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ∈ ℕ 0
32 31 nn0ge0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 ≤ D
33 remsqsqrt ⊢ D ∈ ℝ ∧ 0 ≤ D → D ⁢ D = D
34 30 32 33 syl2anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ⁢ D = D
35 30 32 resqrtcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ∈ ℝ
36 35 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ∈ ℂ
37 36 sqvald ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D 2 = D ⁢ D
38 12 14 20 divcan4d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ⁢ B 2 B 2 = D
39 34 37 38 3eqtr4rd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D ⁢ B 2 B 2 = D 2
40 29 39 oveq12d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 B 2 − D ⁢ B 2 B 2 = A B 2 − D 2
41 9 13 17 divcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B ∈ ℂ
42 subsq ⊢ A B ∈ ℂ ∧ D ∈ ℂ → A B 2 − D 2 = A B + D ⁢ A B − D
43 41 36 42 syl2anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B 2 − D 2 = A B + D ⁢ A B − D
44 41 36 addcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D ∈ ℂ
45 8 nnred ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A ∈ ℝ
46 45 1 nndivred ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B ∈ ℝ
47 46 35 resubcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ∈ ℝ
48 47 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ∈ ℂ
49 44 48 mulcomd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D ⁢ A B − D = A B − D ⁢ A B + D
50 43 49 eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B 2 − D 2 = A B − D ⁢ A B + D
51 27 40 50 3eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 B 2 = A B − D ⁢ A B + D
52 51 fveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 B 2 = A B − D ⁢ A B + D
53 52 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A 2 − D ⁢ B 2 B 2 = B 2 ⁢ A B − D ⁢ A B + D
54 23 26 53 3eqtr3d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 = B 2 ⁢ A B − D ⁢ A B + D
55 48 44 absmuld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ⁢ A B + D = A B − D ⁢ A B + D
56 55 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A B − D ⁢ A B + D = B 2 ⁢ A B − D ⁢ A B + D
57 48 abscld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ∈ ℝ
58 44 abscld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D ∈ ℝ
59 57 58 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ⁢ A B + D ∈ ℝ
60 3 59 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A B − D ⁢ A B + D ∈ ℝ
61 2nn0 ⊢ 2 ∈ ℕ 0
62 61 nn0negzi ⊢ − 2 ∈ ℤ
63 62 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → − 2 ∈ ℤ
64 2 17 63 reexpclzd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B − 2 ∈ ℝ
65 64 58 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B − 2 ⁢ A B + D ∈ ℝ
66 3 65 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 ⁢ A B + D ∈ ℝ
67 1red ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 ∈ ℝ
68 2re ⊢ 2 ∈ ℝ
69 68 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 2 ∈ ℝ
70 69 35 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 2 ⁢ D ∈ ℝ
71 67 70 readdcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 + 2 ⁢ D ∈ ℝ
72 simpr ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D < B − 2
73 8 nngt0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < A
74 1 nngt0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < B
75 45 2 73 74 divgt0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < A B
76 11 nngt0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < D
77 sqrtgt0 ⊢ D ∈ ℝ ∧ 0 < D → 0 < D
78 30 76 77 syl2anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < D
79 46 35 75 78 addgt0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < A B + D
80 79 gt0ne0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D ≠ 0
81 absgt0 ⊢ A B + D ∈ ℂ → A B + D ≠ 0 ↔ 0 < A B + D
82 81 biimpa ⊢ A B + D ∈ ℂ ∧ A B + D ≠ 0 → 0 < A B + D
83 44 80 82 syl2anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < A B + D
84 ltmul1 ⊢ A B − D ∈ ℝ ∧ B − 2 ∈ ℝ ∧ A B + D ∈ ℝ ∧ 0 < A B + D → A B − D < B − 2 ↔ A B − D ⁢ A B + D < B − 2 ⁢ A B + D
85 57 64 58 83 84 syl112anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D < B − 2 ↔ A B − D ⁢ A B + D < B − 2 ⁢ A B + D
86 72 85 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ⁢ A B + D < B − 2 ⁢ A B + D
87 2 17 sqgt0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < B 2
88 ltmul2 ⊢ A B − D ⁢ A B + D ∈ ℝ ∧ B − 2 ⁢ A B + D ∈ ℝ ∧ B 2 ∈ ℝ ∧ 0 < B 2 → A B − D ⁢ A B + D < B − 2 ⁢ A B + D ↔ B 2 ⁢ A B − D ⁢ A B + D < B 2 ⁢ B − 2 ⁢ A B + D
89 59 65 3 87 88 syl112anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ⁢ A B + D < B − 2 ⁢ A B + D ↔ B 2 ⁢ A B − D ⁢ A B + D < B 2 ⁢ B − 2 ⁢ A B + D
90 86 89 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A B − D ⁢ A B + D < B 2 ⁢ B − 2 ⁢ A B + D
91 13 17 63 expclzd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B − 2 ∈ ℂ
92 58 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D ∈ ℂ
93 mulass ⊢ B 2 ∈ ℂ ∧ B − 2 ∈ ℂ ∧ A B + D ∈ ℂ → B 2 ⁢ B − 2 ⁢ A B + D = B 2 ⁢ B − 2 ⁢ A B + D
94 93 eqcomd ⊢ B 2 ∈ ℂ ∧ B − 2 ∈ ℂ ∧ A B + D ∈ ℂ → B 2 ⁢ B − 2 ⁢ A B + D = B 2 ⁢ B − 2 ⁢ A B + D
95 14 91 92 94 syl3anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 ⁢ A B + D = B 2 ⁢ B − 2 ⁢ A B + D
96 expneg ⊢ B ∈ ℂ ∧ 2 ∈ ℕ 0 → B − 2 = 1 B 2
97 13 61 96 sylancl ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B − 2 = 1 B 2
98 97 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 = B 2 ⁢ 1 B 2
99 14 20 recidd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ 1 B 2 = 1
100 98 99 eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 = 1
101 100 oveq1d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 ⁢ A B + D = 1 ⁢ A B + D
102 92 mullidd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 ⁢ A B + D = A B + D
103 95 101 102 3eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 ⁢ A B + D = A B + D
104 41 36 addcomd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D = D + A B
105 ppncan ⊢ D ∈ ℂ ∧ D ∈ ℂ ∧ A B ∈ ℂ → D + D + A B − D = D + A B
106 105 eqcomd ⊢ D ∈ ℂ ∧ D ∈ ℂ ∧ A B ∈ ℂ → D + A B = D + D + A B − D
107 36 36 41 106 syl3anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D + A B = D + D + A B − D
108 36 36 addcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D + D ∈ ℂ
109 108 48 addcomd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D + D + A B − D = A B − D + D + D
110 2times ⊢ D ∈ ℂ → 2 ⁢ D = D + D
111 110 eqcomd ⊢ D ∈ ℂ → D + D = 2 ⁢ D
112 36 111 syl ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D + D = 2 ⁢ D
113 112 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D + D + D = A B - D + 2 ⁢ D
114 109 113 eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → D + D + A B − D = A B - D + 2 ⁢ D
115 104 107 114 3eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D = A B - D + 2 ⁢ D
116 115 fveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D = A B - D + 2 ⁢ D
117 47 70 readdcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B - D + 2 ⁢ D ∈ ℝ
118 117 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B - D + 2 ⁢ D ∈ ℂ
119 118 abscld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B - D + 2 ⁢ D ∈ ℝ
120 70 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 2 ⁢ D ∈ ℂ
121 120 abscld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 2 ⁢ D ∈ ℝ
122 57 121 readdcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D + 2 ⁢ D ∈ ℝ
123 48 120 abstrid ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B - D + 2 ⁢ D ≤ A B − D + 2 ⁢ D
124 0le2 ⊢ 0 ≤ 2
125 124 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 ≤ 2
126 30 32 sqrtge0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 ≤ D
127 69 35 125 126 mulge0d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 ≤ 2 ⁢ D
128 70 127 absidd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 2 ⁢ D = 2 ⁢ D
129 128 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D + 2 ⁢ D = A B − D + 2 ⁢ D
130 1 nnsqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ∈ ℕ
131 130 nnge1d ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 ≤ B 2
132 0lt1 ⊢ 0 < 1
133 132 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 0 < 1
134 lerec ⊢ 1 ∈ ℝ ∧ 0 < 1 ∧ B 2 ∈ ℝ ∧ 0 < B 2 → 1 ≤ B 2 ↔ 1 B 2 ≤ 1 1
135 67 133 3 87 134 syl22anc ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 ≤ B 2 ↔ 1 B 2 ≤ 1 1
136 131 135 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 B 2 ≤ 1 1
137 1div1e1 ⊢ 1 1 = 1
138 136 137 breqtrdi ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → 1 B 2 ≤ 1
139 97 138 eqbrtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B − 2 ≤ 1
140 57 64 67 72 139 ltletrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D < 1
141 57 67 140 ltled ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D ≤ 1
142 57 67 70 141 leadd1dd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D + 2 ⁢ D ≤ 1 + 2 ⁢ D
143 129 142 eqbrtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B − D + 2 ⁢ D ≤ 1 + 2 ⁢ D
144 119 122 71 123 143 letrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B - D + 2 ⁢ D ≤ 1 + 2 ⁢ D
145 116 144 eqbrtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A B + D ≤ 1 + 2 ⁢ D
146 103 145 eqbrtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ B − 2 ⁢ A B + D ≤ 1 + 2 ⁢ D
147 60 66 71 90 146 ltletrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A B − D ⁢ A B + D < 1 + 2 ⁢ D
148 56 147 eqbrtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → B 2 ⁢ A B − D ⁢ A B + D < 1 + 2 ⁢ D
149 54 148 eqbrtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ ∧ B ∈ ℕ ∧ A B − D < B − 2 → A 2 − D ⁢ B 2 < 1 + 2 ⁢ D