Metamath Proof Explorer


Theorem pige3ALT

Description: Alternate proof of pige3 . This proof is based on the geometric observation that a hexagon of unit side length has perimeter 6, which is less than the unit-radius circumcircle, of perimeter 2pi . We translate this to algebra by looking at the function e ^ (i x ) as x goes from 0 to pi / 3 ; it moves at unit speed and travels distance 1 , hence 1 <_ _pi / 3 . (Contributed by Mario Carneiro, 21-May-2016) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Assertion pige3ALT ⊢ 3 ≤ π

Proof

Step Hyp Ref Expression
1 3cn ⊢ 3 ∈ ℂ
2 1 mullidi ⊢ 1 ⋅ 3 = 3
3 tru ⊢ ⊤
4 0xr ⊢ 0 ∈ ℝ *
5 pirp ⊢ π ∈ ℝ +
6 3rp ⊢ 3 ∈ ℝ +
7 rpdivcl ⊢ π ∈ ℝ + ∧ 3 ∈ ℝ + → π 3 ∈ ℝ +
8 5 6 7 mp2an ⊢ π 3 ∈ ℝ +
9 rpxr ⊢ π 3 ∈ ℝ + → π 3 ∈ ℝ *
10 8 9 ax-mp ⊢ π 3 ∈ ℝ *
11 rpge0 ⊢ π 3 ∈ ℝ + → 0 ≤ π 3
12 8 11 ax-mp ⊢ 0 ≤ π 3
13 lbicc2 ⊢ 0 ∈ ℝ * ∧ π 3 ∈ ℝ * ∧ 0 ≤ π 3 → 0 ∈ 0 π 3
14 4 10 12 13 mp3an ⊢ 0 ∈ 0 π 3
15 ubicc2 ⊢ 0 ∈ ℝ * ∧ π 3 ∈ ℝ * ∧ 0 ≤ π 3 → π 3 ∈ 0 π 3
16 4 10 12 15 mp3an ⊢ π 3 ∈ 0 π 3
17 14 16 pm3.2i ⊢ 0 ∈ 0 π 3 ∧ π 3 ∈ 0 π 3
18 0re ⊢ 0 ∈ ℝ
19 18 a1i ⊢ ⊤ → 0 ∈ ℝ
20 pire ⊢ π ∈ ℝ
21 3re ⊢ 3 ∈ ℝ
22 3ne0 ⊢ 3 ≠ 0
23 20 21 22 redivcli ⊢ π 3 ∈ ℝ
24 23 a1i ⊢ ⊤ → π 3 ∈ ℝ
25 efcn ⊢ exp : ℂ ⟶cn ℂ
26 25 a1i ⊢ ⊤ → exp : ℂ ⟶cn ℂ
27 iccssre ⊢ 0 ∈ ℝ ∧ π 3 ∈ ℝ → 0 π 3 ⊆ ℝ
28 18 23 27 mp2an ⊢ 0 π 3 ⊆ ℝ
29 ax-resscn ⊢ ℝ ⊆ ℂ
30 28 29 sstri ⊢ 0 π 3 ⊆ ℂ
31 resmpt ⊢ 0 π 3 ⊆ ℂ → x ∈ ℂ ⟼ i ⁢ x ↾ 0 π 3 = x ∈ 0 π 3 ⟼ i ⁢ x
32 30 31 mp1i ⊢ ⊤ → x ∈ ℂ ⟼ i ⁢ x ↾ 0 π 3 = x ∈ 0 π 3 ⟼ i ⁢ x
33 ssidd ⊢ ⊤ → ℂ ⊆ ℂ
34 ax-icn ⊢ i ∈ ℂ
35 simpr ⊢ ⊤ ∧ x ∈ ℂ → x ∈ ℂ
36 mulcl ⊢ i ∈ ℂ ∧ x ∈ ℂ → i ⁢ x ∈ ℂ
37 34 35 36 sylancr ⊢ ⊤ ∧ x ∈ ℂ → i ⁢ x ∈ ℂ
38 37 fmpttd ⊢ ⊤ → x ∈ ℂ ⟼ i ⁢ x : ℂ ⟶ ℂ
39 cnelprrecn ⊢ ℂ ∈ ℝ ℂ
40 39 a1i ⊢ ⊤ → ℂ ∈ ℝ ℂ
41 ax-1cn ⊢ 1 ∈ ℂ
42 41 a1i ⊢ ⊤ ∧ x ∈ ℂ → 1 ∈ ℂ
43 40 dvmptid ⊢ ⊤ → dx ∈ ℂ x d ℂ x = x ∈ ℂ ⟼ 1
44 34 a1i ⊢ ⊤ → i ∈ ℂ
45 40 35 42 43 44 dvmptcmul ⊢ ⊤ → dx ∈ ℂ i ⁢ x d ℂ x = x ∈ ℂ ⟼ i ⋅ 1
46 34 mulridi ⊢ i ⋅ 1 = i
47 46 mpteq2i ⊢ x ∈ ℂ ⟼ i ⋅ 1 = x ∈ ℂ ⟼ i
48 45 47 eqtrdi ⊢ ⊤ → dx ∈ ℂ i ⁢ x d ℂ x = x ∈ ℂ ⟼ i
49 48 dmeqd ⊢ ⊤ → dom ⁡ dx ∈ ℂ i ⁢ x d ℂ x = dom ⁡ x ∈ ℂ ⟼ i
50 34 elexi ⊢ i ∈ V
51 eqid ⊢ x ∈ ℂ ⟼ i = x ∈ ℂ ⟼ i
52 50 51 dmmpti ⊢ dom ⁡ x ∈ ℂ ⟼ i = ℂ
53 49 52 eqtrdi ⊢ ⊤ → dom ⁡ dx ∈ ℂ i ⁢ x d ℂ x = ℂ
54 dvcn ⊢ ℂ ⊆ ℂ ∧ x ∈ ℂ ⟼ i ⁢ x : ℂ ⟶ ℂ ∧ ℂ ⊆ ℂ ∧ dom ⁡ dx ∈ ℂ i ⁢ x d ℂ x = ℂ → x ∈ ℂ ⟼ i ⁢ x : ℂ ⟶cn ℂ
55 33 38 33 53 54 syl31anc ⊢ ⊤ → x ∈ ℂ ⟼ i ⁢ x : ℂ ⟶cn ℂ
56 rescncf ⊢ 0 π 3 ⊆ ℂ → x ∈ ℂ ⟼ i ⁢ x : ℂ ⟶cn ℂ → x ∈ ℂ ⟼ i ⁢ x ↾ 0 π 3 : 0 π 3 ⟶cn ℂ
57 30 55 56 mpsyl ⊢ ⊤ → x ∈ ℂ ⟼ i ⁢ x ↾ 0 π 3 : 0 π 3 ⟶cn ℂ
58 32 57 eqeltrrd ⊢ ⊤ → x ∈ 0 π 3 ⟼ i ⁢ x : 0 π 3 ⟶cn ℂ
59 26 58 cncfmpt1f ⊢ ⊤ → x ∈ 0 π 3 ⟼ e i ⁢ x : 0 π 3 ⟶cn ℂ
60 reelprrecn ⊢ ℝ ∈ ℝ ℂ
61 60 a1i ⊢ ⊤ → ℝ ∈ ℝ ℂ
62 recn ⊢ x ∈ ℝ → x ∈ ℂ
63 efcl ⊢ i ⁢ x ∈ ℂ → e i ⁢ x ∈ ℂ
64 37 63 syl ⊢ ⊤ ∧ x ∈ ℂ → e i ⁢ x ∈ ℂ
65 62 64 sylan2 ⊢ ⊤ ∧ x ∈ ℝ → e i ⁢ x ∈ ℂ
66 mulcl ⊢ e i ⁢ x ∈ ℂ ∧ i ∈ ℂ → e i ⁢ x ⁢ i ∈ ℂ
67 64 34 66 sylancl ⊢ ⊤ ∧ x ∈ ℂ → e i ⁢ x ⁢ i ∈ ℂ
68 62 67 sylan2 ⊢ ⊤ ∧ x ∈ ℝ → e i ⁢ x ⁢ i ∈ ℂ
69 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
70 69 cnfldtopon ⊢ TopOpen ⁡ ℂ fld ∈ TopOn ⁡ ℂ
71 toponmax ⊢ TopOpen ⁡ ℂ fld ∈ TopOn ⁡ ℂ → ℂ ∈ TopOpen ⁡ ℂ fld
72 70 71 mp1i ⊢ ⊤ → ℂ ∈ TopOpen ⁡ ℂ fld
73 29 a1i ⊢ ⊤ → ℝ ⊆ ℂ
74 dfss2 ⊢ ℝ ⊆ ℂ ↔ ℝ ∩ ℂ = ℝ
75 73 74 sylib ⊢ ⊤ → ℝ ∩ ℂ = ℝ
76 34 a1i ⊢ ⊤ ∧ x ∈ ℂ → i ∈ ℂ
77 efcl ⊢ y ∈ ℂ → e y ∈ ℂ
78 77 adantl ⊢ ⊤ ∧ y ∈ ℂ → e y ∈ ℂ
79 dvef ⊢ ℂ D exp = exp
80 eff ⊢ exp : ℂ ⟶ ℂ
81 80 a1i ⊢ ⊤ → exp : ℂ ⟶ ℂ
82 81 feqmptd ⊢ ⊤ → exp = y ∈ ℂ ⟼ e y
83 82 oveq2d ⊢ ⊤ → ℂ D exp = dy ∈ ℂ e y d ℂ y
84 79 83 82 3eqtr3a ⊢ ⊤ → dy ∈ ℂ e y d ℂ y = y ∈ ℂ ⟼ e y
85 fveq2 ⊢ y = i ⁢ x → e y = e i ⁢ x
86 40 40 37 76 78 78 48 84 85 85 dvmptco ⊢ ⊤ → dx ∈ ℂ e i ⁢ x d ℂ x = x ∈ ℂ ⟼ e i ⁢ x ⁢ i
87 69 61 72 75 64 67 86 dvmptres3 ⊢ ⊤ → dx ∈ ℝ e i ⁢ x d ℝ x = x ∈ ℝ ⟼ e i ⁢ x ⁢ i
88 28 a1i ⊢ ⊤ → 0 π 3 ⊆ ℝ
89 69 tgioo2 ⊢ topGen ⁡ ran ⁡ . = TopOpen ⁡ ℂ fld ↾ 𝑡 ℝ
90 iccntr ⊢ 0 ∈ ℝ ∧ π 3 ∈ ℝ → int ⁡ topGen ⁡ ran ⁡ . ⁡ 0 π 3 = 0 π 3
91 18 24 90 sylancr ⊢ ⊤ → int ⁡ topGen ⁡ ran ⁡ . ⁡ 0 π 3 = 0 π 3
92 61 65 68 87 88 89 69 91 dvmptres2 ⊢ ⊤ → dx ∈ 0 π 3 e i ⁢ x d ℝ x = x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i
93 92 dmeqd ⊢ ⊤ → dom ⁡ dx ∈ 0 π 3 e i ⁢ x d ℝ x = dom ⁡ x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i
94 ovex ⊢ e i ⁢ x ⁢ i ∈ V
95 eqid ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i = x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i
96 94 95 dmmpti ⊢ dom ⁡ x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i = 0 π 3
97 93 96 eqtrdi ⊢ ⊤ → dom ⁡ dx ∈ 0 π 3 e i ⁢ x d ℝ x = 0 π 3
98 1re ⊢ 1 ∈ ℝ
99 98 a1i ⊢ ⊤ → 1 ∈ ℝ
100 92 fveq1d ⊢ ⊤ → dx ∈ 0 π 3 e i ⁢ x d ℝ x ⁡ y = x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i ⁡ y
101 oveq2 ⊢ x = y → i ⁢ x = i ⁢ y
102 101 fveq2d ⊢ x = y → e i ⁢ x = e i ⁢ y
103 102 oveq1d ⊢ x = y → e i ⁢ x ⁢ i = e i ⁢ y ⁢ i
104 103 95 94 fvmpt3i ⊢ y ∈ 0 π 3 → x ∈ 0 π 3 ⟼ e i ⁢ x ⁢ i ⁡ y = e i ⁢ y ⁢ i
105 100 104 sylan9eq ⊢ ⊤ ∧ y ∈ 0 π 3 → dx ∈ 0 π 3 e i ⁢ x d ℝ x ⁡ y = e i ⁢ y ⁢ i
106 105 fveq2d ⊢ ⊤ ∧ y ∈ 0 π 3 → dx ∈ 0 π 3 e i ⁢ x d ℝ x ⁡ y = e i ⁢ y ⁢ i
107 ioossre ⊢ 0 π 3 ⊆ ℝ
108 107 a1i ⊢ ⊤ → 0 π 3 ⊆ ℝ
109 108 sselda ⊢ ⊤ ∧ y ∈ 0 π 3 → y ∈ ℝ
110 109 recnd ⊢ ⊤ ∧ y ∈ 0 π 3 → y ∈ ℂ
111 mulcl ⊢ i ∈ ℂ ∧ y ∈ ℂ → i ⁢ y ∈ ℂ
112 34 110 111 sylancr ⊢ ⊤ ∧ y ∈ 0 π 3 → i ⁢ y ∈ ℂ
113 efcl ⊢ i ⁢ y ∈ ℂ → e i ⁢ y ∈ ℂ
114 112 113 syl ⊢ ⊤ ∧ y ∈ 0 π 3 → e i ⁢ y ∈ ℂ
115 absmul ⊢ e i ⁢ y ∈ ℂ ∧ i ∈ ℂ → e i ⁢ y ⁢ i = e i ⁢ y ⁢ i
116 114 34 115 sylancl ⊢ ⊤ ∧ y ∈ 0 π 3 → e i ⁢ y ⁢ i = e i ⁢ y ⁢ i
117 absefi ⊢ y ∈ ℝ → e i ⁢ y = 1
118 109 117 syl ⊢ ⊤ ∧ y ∈ 0 π 3 → e i ⁢ y = 1
119 absi ⊢ i = 1
120 119 a1i ⊢ ⊤ ∧ y ∈ 0 π 3 → i = 1
121 118 120 oveq12d ⊢ ⊤ ∧ y ∈ 0 π 3 → e i ⁢ y ⁢ i = 1 ⋅ 1
122 41 mulridi ⊢ 1 ⋅ 1 = 1
123 121 122 eqtrdi ⊢ ⊤ ∧ y ∈ 0 π 3 → e i ⁢ y ⁢ i = 1
124 106 116 123 3eqtrd ⊢ ⊤ ∧ y ∈ 0 π 3 → dx ∈ 0 π 3 e i ⁢ x d ℝ x ⁡ y = 1
125 1le1 ⊢ 1 ≤ 1
126 124 125 eqbrtrdi ⊢ ⊤ ∧ y ∈ 0 π 3 → dx ∈ 0 π 3 e i ⁢ x d ℝ x ⁡ y ≤ 1
127 19 24 59 97 99 126 dvlip ⊢ ⊤ ∧ 0 ∈ 0 π 3 ∧ π 3 ∈ 0 π 3 → x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 − x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 ≤ 1 ⁢ 0 − π 3
128 3 17 127 mp2an ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 − x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 ≤ 1 ⁢ 0 − π 3
129 oveq2 ⊢ x = 0 → i ⁢ x = i ⋅ 0
130 it0e0 ⊢ i ⋅ 0 = 0
131 129 130 eqtrdi ⊢ x = 0 → i ⁢ x = 0
132 131 fveq2d ⊢ x = 0 → e i ⁢ x = e 0
133 ef0 ⊢ e 0 = 1
134 132 133 eqtrdi ⊢ x = 0 → e i ⁢ x = 1
135 eqid ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x = x ∈ 0 π 3 ⟼ e i ⁢ x
136 fvex ⊢ e i ⁢ x ∈ V
137 134 135 136 fvmpt3i ⊢ 0 ∈ 0 π 3 → x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 = 1
138 14 137 ax-mp ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 = 1
139 oveq2 ⊢ x = π 3 → i ⁢ x = i ⁢ π 3
140 139 fveq2d ⊢ x = π 3 → e i ⁢ x = e i ⁢ π 3
141 140 135 136 fvmpt3i ⊢ π 3 ∈ 0 π 3 → x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 = e i ⁢ π 3
142 16 141 ax-mp ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 = e i ⁢ π 3
143 138 142 oveq12i ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 − x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 = 1 − e i ⁢ π 3
144 23 recni ⊢ π 3 ∈ ℂ
145 34 144 mulcli ⊢ i ⁢ π 3 ∈ ℂ
146 efcl ⊢ i ⁢ π 3 ∈ ℂ → e i ⁢ π 3 ∈ ℂ
147 145 146 ax-mp ⊢ e i ⁢ π 3 ∈ ℂ
148 negicn ⊢ − i ∈ ℂ
149 148 144 mulcli ⊢ − i ⁢ π 3 ∈ ℂ
150 efcl ⊢ − i ⁢ π 3 ∈ ℂ → e − i ⁢ π 3 ∈ ℂ
151 149 150 ax-mp ⊢ e − i ⁢ π 3 ∈ ℂ
152 cosval ⊢ π 3 ∈ ℂ → cos ⁡ π 3 = e i ⁢ π 3 + e − i ⁢ π 3 2
153 144 152 ax-mp ⊢ cos ⁡ π 3 = e i ⁢ π 3 + e − i ⁢ π 3 2
154 sincos3rdpi ⊢ sin ⁡ π 3 = 3 2 ∧ cos ⁡ π 3 = 1 2
155 154 simpri ⊢ cos ⁡ π 3 = 1 2
156 153 155 eqtr3i ⊢ e i ⁢ π 3 + e − i ⁢ π 3 2 = 1 2
157 147 151 addcli ⊢ e i ⁢ π 3 + e − i ⁢ π 3 ∈ ℂ
158 2cn ⊢ 2 ∈ ℂ
159 2ne0 ⊢ 2 ≠ 0
160 157 41 158 159 div11i ⊢ e i ⁢ π 3 + e − i ⁢ π 3 2 = 1 2 ↔ e i ⁢ π 3 + e − i ⁢ π 3 = 1
161 156 160 mpbi ⊢ e i ⁢ π 3 + e − i ⁢ π 3 = 1
162 41 147 151 161 subaddrii ⊢ 1 − e i ⁢ π 3 = e − i ⁢ π 3
163 mulneg12 ⊢ i ∈ ℂ ∧ π 3 ∈ ℂ → − i ⁢ π 3 = i ⁢ − π 3
164 34 144 163 mp2an ⊢ − i ⁢ π 3 = i ⁢ − π 3
165 164 fveq2i ⊢ e − i ⁢ π 3 = e i ⁢ − π 3
166 143 162 165 3eqtri ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 − x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 = e i ⁢ − π 3
167 166 fveq2i ⊢ x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ 0 − x ∈ 0 π 3 ⟼ e i ⁢ x ⁡ π 3 = e i ⁢ − π 3
168 144 absnegi ⊢ − π 3 = π 3
169 df-neg ⊢ − π 3 = 0 − π 3
170 169 fveq2i ⊢ − π 3 = 0 − π 3
171 168 170 eqtr3i ⊢ π 3 = 0 − π 3
172 rprege0 ⊢ π 3 ∈ ℝ + → π 3 ∈ ℝ ∧ 0 ≤ π 3
173 absid ⊢ π 3 ∈ ℝ ∧ 0 ≤ π 3 → π 3 = π 3
174 8 172 173 mp2b ⊢ π 3 = π 3
175 171 174 eqtr3i ⊢ 0 − π 3 = π 3
176 175 oveq2i ⊢ 1 ⁢ 0 − π 3 = 1 ⁢ π 3
177 128 167 176 3brtr3i ⊢ e i ⁢ − π 3 ≤ 1 ⁢ π 3
178 23 renegcli ⊢ − π 3 ∈ ℝ
179 absefi ⊢ − π 3 ∈ ℝ → e i ⁢ − π 3 = 1
180 178 179 ax-mp ⊢ e i ⁢ − π 3 = 1
181 144 mullidi ⊢ 1 ⁢ π 3 = π 3
182 177 180 181 3brtr3i ⊢ 1 ≤ π 3
183 3pos ⊢ 0 < 3
184 21 183 pm3.2i ⊢ 3 ∈ ℝ ∧ 0 < 3
185 lemuldiv ⊢ 1 ∈ ℝ ∧ π ∈ ℝ ∧ 3 ∈ ℝ ∧ 0 < 3 → 1 ⋅ 3 ≤ π ↔ 1 ≤ π 3
186 98 20 184 185 mp3an ⊢ 1 ⋅ 3 ≤ π ↔ 1 ≤ π 3
187 182 186 mpbir ⊢ 1 ⋅ 3 ≤ π
188 2 187 eqbrtrri ⊢ 3 ≤ π