Metamath Proof Explorer


Theorem pjeq

Description: Equality with a projection. (Contributed by NM, 20-Jan-2007) (Revised by Mario Carneiro, 15-May-2014) (New usage is discouraged.)

Ref Expression
Assertion pjeq H C A proj H A = B B H x H A = B + x

Proof

Step Hyp Ref Expression
1 pjhth H C H + H =
2 1 eleq2d H C A H + H A
3 2 biimpar H C A A H + H
4 pjpreeq H C A H + H proj H A = B B H x H A = B + x
5 3 4 syldan H C A proj H A = B B H x H A = B + x