Metamath Proof Explorer


Theorem pjoml3

Description: Variation of orthomodular law. (Contributed by NM, 24-Jun-2004) (New usage is discouraged.)

Ref Expression
Assertion pjoml3 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → B ⊆ A → A ∩ ⊥ ⁡ A ∨ ℋ B = B

Proof

Step Hyp Ref Expression
1 sseq2 ⊢ A = if A ∈ C ℋ A ℋ → B ⊆ A ↔ B ⊆ if A ∈ C ℋ A ℋ
2 id ⊢ A = if A ∈ C ℋ A ℋ → A = if A ∈ C ℋ A ℋ
3 fveq2 ⊢ A = if A ∈ C ℋ A ℋ → ⊥ ⁡ A = ⊥ ⁡ if A ∈ C ℋ A ℋ
4 3 oveq1d ⊢ A = if A ∈ C ℋ A ℋ → ⊥ ⁡ A ∨ ℋ B = ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B
5 2 4 ineq12d ⊢ A = if A ∈ C ℋ A ℋ → A ∩ ⊥ ⁡ A ∨ ℋ B = if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B
6 5 eqeq1d ⊢ A = if A ∈ C ℋ A ℋ → A ∩ ⊥ ⁡ A ∨ ℋ B = B ↔ if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B = B
7 1 6 imbi12d ⊢ A = if A ∈ C ℋ A ℋ → B ⊆ A → A ∩ ⊥ ⁡ A ∨ ℋ B = B ↔ B ⊆ if A ∈ C ℋ A ℋ → if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B = B
8 sseq1 ⊢ B = if B ∈ C ℋ B ℋ → B ⊆ if A ∈ C ℋ A ℋ ↔ if B ∈ C ℋ B ℋ ⊆ if A ∈ C ℋ A ℋ
9 oveq2 ⊢ B = if B ∈ C ℋ B ℋ → ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B = ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ if B ∈ C ℋ B ℋ
10 9 ineq2d ⊢ B = if B ∈ C ℋ B ℋ → if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B = if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ if B ∈ C ℋ B ℋ
11 id ⊢ B = if B ∈ C ℋ B ℋ → B = if B ∈ C ℋ B ℋ
12 10 11 eqeq12d ⊢ B = if B ∈ C ℋ B ℋ → if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B = B ↔ if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ if B ∈ C ℋ B ℋ = if B ∈ C ℋ B ℋ
13 8 12 imbi12d ⊢ B = if B ∈ C ℋ B ℋ → B ⊆ if A ∈ C ℋ A ℋ → if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ B = B ↔ if B ∈ C ℋ B ℋ ⊆ if A ∈ C ℋ A ℋ → if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ if B ∈ C ℋ B ℋ = if B ∈ C ℋ B ℋ
14 ifchhv ⊢ if A ∈ C ℋ A ℋ ∈ C ℋ
15 ifchhv ⊢ if B ∈ C ℋ B ℋ ∈ C ℋ
16 14 15 pjoml3i ⊢ if B ∈ C ℋ B ℋ ⊆ if A ∈ C ℋ A ℋ → if A ∈ C ℋ A ℋ ∩ ⊥ ⁡ if A ∈ C ℋ A ℋ ∨ ℋ if B ∈ C ℋ B ℋ = if B ∈ C ℋ B ℋ
17 7 13 16 dedth2h ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → B ⊆ A → A ∩ ⊥ ⁡ A ∨ ℋ B = B