Metamath Proof Explorer


Theorem ply1asclunit

Description: A nonzero scalar polynomial over a field F is a unit. (Contributed by Thierry Arnoux, 22-Mar-2025)

Ref Expression
Hypotheses ply1asclunit.1 ⊢ P = Poly 1 ⁡ F
ply1asclunit.2 ⊢ A = algSc ⁡ P
ply1asclunit.3 ⊢ B = Base F
ply1asclunit.4 ⊢ 0 ˙ = 0 F
ply1asclunit.5 ⊢ φ → F ∈ Field
ply1asclunit.6 ⊢ φ → Y ∈ B
ply1asclunit.7 ⊢ φ → Y ≠ 0 ˙
Assertion ply1asclunit ⊢ φ → A ⁡ Y ∈ Unit ⁡ P

Proof

Step Hyp Ref Expression
1 ply1asclunit.1 ⊢ P = Poly 1 ⁡ F
2 ply1asclunit.2 ⊢ A = algSc ⁡ P
3 ply1asclunit.3 ⊢ B = Base F
4 ply1asclunit.4 ⊢ 0 ˙ = 0 F
5 ply1asclunit.5 ⊢ φ → F ∈ Field
6 ply1asclunit.6 ⊢ φ → Y ∈ B
7 ply1asclunit.7 ⊢ φ → Y ≠ 0 ˙
8 5 fldcrngd ⊢ φ → F ∈ CRing
9 1 ply1assa ⊢ F ∈ CRing → P ∈ AssAlg
10 eqid ⊢ Scalar ⁡ P = Scalar ⁡ P
11 2 10 asclrhm ⊢ P ∈ AssAlg → A ∈ Scalar ⁡ P RingHom P
12 8 9 11 3syl ⊢ φ → A ∈ Scalar ⁡ P RingHom P
13 1 ply1sca ⊢ F ∈ Field → F = Scalar ⁡ P
14 5 13 syl ⊢ φ → F = Scalar ⁡ P
15 14 oveq1d ⊢ φ → F RingHom P = Scalar ⁡ P RingHom P
16 12 15 eleqtrrd ⊢ φ → A ∈ F RingHom P
17 5 flddrngd ⊢ φ → F ∈ DivRing
18 eqid ⊢ Unit ⁡ F = Unit ⁡ F
19 3 18 4 drngunit ⊢ F ∈ DivRing → Y ∈ Unit ⁡ F ↔ Y ∈ B ∧ Y ≠ 0 ˙
20 19 biimpar ⊢ F ∈ DivRing ∧ Y ∈ B ∧ Y ≠ 0 ˙ → Y ∈ Unit ⁡ F
21 17 6 7 20 syl12anc ⊢ φ → Y ∈ Unit ⁡ F
22 elrhmunit ⊢ A ∈ F RingHom P ∧ Y ∈ Unit ⁡ F → A ⁡ Y ∈ Unit ⁡ P
23 16 21 22 syl2anc ⊢ φ → A ⁡ Y ∈ Unit ⁡ P