Metamath Proof Explorer


Theorem ply1idvr1

Description: The identity of a polynomial ring expressed as power of the polynomial variable. (Contributed by AV, 14-Aug-2019) (Proof shortened by SN, 3-Jul-2025)

Ref Expression
Hypotheses ply1idvr1.p ⊢ P = Poly 1 ⁡ R
ply1idvr1.x ⊢ X = var 1 ⁡ R
ply1idvr1.n ⊢ N = mulGrp P
ply1idvr1.e ⊢ × ˙ = ⋅ N
Assertion ply1idvr1 ⊢ R ∈ Ring → 0 × ˙ X = 1 P

Proof

Step Hyp Ref Expression
1 ply1idvr1.p ⊢ P = Poly 1 ⁡ R
2 ply1idvr1.x ⊢ X = var 1 ⁡ R
3 ply1idvr1.n ⊢ N = mulGrp P
4 ply1idvr1.e ⊢ × ˙ = ⋅ N
5 eqid ⊢ Base P = Base P
6 2 1 5 vr1cl ⊢ R ∈ Ring → X ∈ Base P
7 3 5 mgpbas ⊢ Base P = Base N
8 eqid ⊢ 1 P = 1 P
9 3 8 ringidval ⊢ 1 P = 0 N
10 7 9 4 mulg0 ⊢ X ∈ Base P → 0 × ˙ X = 1 P
11 6 10 syl ⊢ R ∈ Ring → 0 × ˙ X = 1 P