Metamath Proof Explorer


Theorem ply1opprmul

Description: Reversing multiplication in a ring reverses multiplication in the univariate polynomial ring. (Contributed by Stefan O'Rear, 27-Mar-2015)

Ref Expression
Hypotheses ply1opprmul.y ⊢ Y = Poly 1 ⁡ R
ply1opprmul.s ⊢ S = opp r ⁡ R
ply1opprmul.z ⊢ Z = Poly 1 ⁡ S
ply1opprmul.t ⊢ · ˙ = ⋅ Y
ply1opprmul.u ⊢ ∙ ˙ = ⋅ Z
ply1opprmul.b ⊢ B = Base Y
Assertion ply1opprmul ⊢ R ∈ Ring ∧ F ∈ B ∧ G ∈ B → F ∙ ˙ G = G · ˙ F

Proof

Step Hyp Ref Expression
1 ply1opprmul.y ⊢ Y = Poly 1 ⁡ R
2 ply1opprmul.s ⊢ S = opp r ⁡ R
3 ply1opprmul.z ⊢ Z = Poly 1 ⁡ S
4 ply1opprmul.t ⊢ · ˙ = ⋅ Y
5 ply1opprmul.u ⊢ ∙ ˙ = ⋅ Z
6 ply1opprmul.b ⊢ B = Base Y
7 id ⊢ R ∈ Ring → R ∈ Ring
8 1 6 ply1bascl ⊢ F ∈ B → F ∈ Base PwSer 1 ⁡ R
9 eqid ⊢ PwSer 1 ⁡ R = PwSer 1 ⁡ R
10 eqid ⊢ Base PwSer 1 ⁡ R = Base PwSer 1 ⁡ R
11 9 10 psr1bascl ⊢ F ∈ Base PwSer 1 ⁡ R → F ∈ Base 1 𝑜 mPwSer R
12 8 11 syl ⊢ F ∈ B → F ∈ Base 1 𝑜 mPwSer R
13 1 6 ply1bascl ⊢ G ∈ B → G ∈ Base PwSer 1 ⁡ R
14 9 10 psr1bascl ⊢ G ∈ Base PwSer 1 ⁡ R → G ∈ Base 1 𝑜 mPwSer R
15 13 14 syl ⊢ G ∈ B → G ∈ Base 1 𝑜 mPwSer R
16 eqid ⊢ 1 𝑜 mPwSer R = 1 𝑜 mPwSer R
17 eqid ⊢ 1 𝑜 mPwSer S = 1 𝑜 mPwSer S
18 eqid ⊢ 1 𝑜 mPoly R = 1 𝑜 mPoly R
19 1 18 4 ply1mulr ⊢ · ˙ = ⋅ 1 𝑜 mPoly R
20 18 16 19 mplmulr ⊢ · ˙ = ⋅ 1 𝑜 mPwSer R
21 eqid ⊢ 1 𝑜 mPoly S = 1 𝑜 mPoly S
22 3 21 5 ply1mulr ⊢ ∙ ˙ = ⋅ 1 𝑜 mPoly S
23 21 17 22 mplmulr ⊢ ∙ ˙ = ⋅ 1 𝑜 mPwSer S
24 eqid ⊢ Base 1 𝑜 mPwSer R = Base 1 𝑜 mPwSer R
25 16 2 17 20 23 24 psropprmul ⊢ R ∈ Ring ∧ F ∈ Base 1 𝑜 mPwSer R ∧ G ∈ Base 1 𝑜 mPwSer R → F ∙ ˙ G = G · ˙ F
26 7 12 15 25 syl3an ⊢ R ∈ Ring ∧ F ∈ B ∧ G ∈ B → F ∙ ˙ G = G · ˙ F