Metamath Proof Explorer


Theorem plydivlem3

Description: Lemma for plydivex . Base case of induction. (Contributed by Mario Carneiro, 24-Jul-2014)

Ref Expression
Hypotheses plydiv.pl ⊢ φ ∧ x ∈ S ∧ y ∈ S → x + y ∈ S
plydiv.tm ⊢ φ ∧ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
plydiv.rc ⊢ φ ∧ x ∈ S ∧ x ≠ 0 → 1 x ∈ S
plydiv.m1 ⊢ φ → − 1 ∈ S
plydiv.f ⊢ φ → F ∈ Poly ⁡ S
plydiv.g ⊢ φ → G ∈ Poly ⁡ S
plydiv.z ⊢ φ → G ≠ 0 𝑝
plydiv.r ⊢ R = F − f G × f q
plydiv.0 ⊢ φ → F = 0 𝑝 ∨ deg ⁡ F − deg ⁡ G < 0
Assertion plydivlem3 ⊢ φ → ∃ q ∈ Poly ⁡ S R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G

Proof

Step Hyp Ref Expression
1 plydiv.pl ⊢ φ ∧ x ∈ S ∧ y ∈ S → x + y ∈ S
2 plydiv.tm ⊢ φ ∧ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
3 plydiv.rc ⊢ φ ∧ x ∈ S ∧ x ≠ 0 → 1 x ∈ S
4 plydiv.m1 ⊢ φ → − 1 ∈ S
5 plydiv.f ⊢ φ → F ∈ Poly ⁡ S
6 plydiv.g ⊢ φ → G ∈ Poly ⁡ S
7 plydiv.z ⊢ φ → G ≠ 0 𝑝
8 plydiv.r ⊢ R = F − f G × f q
9 plydiv.0 ⊢ φ → F = 0 𝑝 ∨ deg ⁡ F − deg ⁡ G < 0
10 plybss ⊢ F ∈ Poly ⁡ S → S ⊆ ℂ
11 ply0 ⊢ S ⊆ ℂ → 0 𝑝 ∈ Poly ⁡ S
12 5 10 11 3syl ⊢ φ → 0 𝑝 ∈ Poly ⁡ S
13 cnex ⊢ ℂ ∈ V
14 13 a1i ⊢ φ → ℂ ∈ V
15 plyf ⊢ F ∈ Poly ⁡ S → F : ℂ ⟶ ℂ
16 ffn ⊢ F : ℂ ⟶ ℂ → F Fn ℂ
17 5 15 16 3syl ⊢ φ → F Fn ℂ
18 plyf ⊢ G ∈ Poly ⁡ S → G : ℂ ⟶ ℂ
19 ffn ⊢ G : ℂ ⟶ ℂ → G Fn ℂ
20 6 18 19 3syl ⊢ φ → G Fn ℂ
21 plyf ⊢ 0 𝑝 ∈ Poly ⁡ S → 0 𝑝 : ℂ ⟶ ℂ
22 ffn ⊢ 0 𝑝 : ℂ ⟶ ℂ → 0 𝑝 Fn ℂ
23 12 21 22 3syl ⊢ φ → 0 𝑝 Fn ℂ
24 inidm ⊢ ℂ ∩ ℂ = ℂ
25 20 23 14 14 24 offn ⊢ φ → G × f 0 𝑝 Fn ℂ
26 eqidd ⊢ φ ∧ z ∈ ℂ → F ⁡ z = F ⁡ z
27 eqidd ⊢ φ ∧ z ∈ ℂ → G ⁡ z = G ⁡ z
28 0pval ⊢ z ∈ ℂ → 0 𝑝 ⁡ z = 0
29 28 adantl ⊢ φ ∧ z ∈ ℂ → 0 𝑝 ⁡ z = 0
30 20 23 14 14 24 27 29 ofval ⊢ φ ∧ z ∈ ℂ → G × f 0 𝑝 ⁡ z = G ⁡ z ⋅ 0
31 6 18 syl ⊢ φ → G : ℂ ⟶ ℂ
32 31 ffvelcdmda ⊢ φ ∧ z ∈ ℂ → G ⁡ z ∈ ℂ
33 32 mul01d ⊢ φ ∧ z ∈ ℂ → G ⁡ z ⋅ 0 = 0
34 30 33 eqtrd ⊢ φ ∧ z ∈ ℂ → G × f 0 𝑝 ⁡ z = 0
35 5 15 syl ⊢ φ → F : ℂ ⟶ ℂ
36 35 ffvelcdmda ⊢ φ ∧ z ∈ ℂ → F ⁡ z ∈ ℂ
37 36 subid1d ⊢ φ ∧ z ∈ ℂ → F ⁡ z − 0 = F ⁡ z
38 14 17 25 17 26 34 37 offveq ⊢ φ → F − f G × f 0 𝑝 = F
39 38 eqeq1d ⊢ φ → F − f G × f 0 𝑝 = 0 𝑝 ↔ F = 0 𝑝
40 38 fveq2d ⊢ φ → deg ⁡ F − f G × f 0 𝑝 = deg ⁡ F
41 dgrcl ⊢ G ∈ Poly ⁡ S → deg ⁡ G ∈ ℕ 0
42 6 41 syl ⊢ φ → deg ⁡ G ∈ ℕ 0
43 42 nn0red ⊢ φ → deg ⁡ G ∈ ℝ
44 43 recnd ⊢ φ → deg ⁡ G ∈ ℂ
45 44 addlidd ⊢ φ → 0 + deg ⁡ G = deg ⁡ G
46 45 eqcomd ⊢ φ → deg ⁡ G = 0 + deg ⁡ G
47 40 46 breq12d ⊢ φ → deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G ↔ deg ⁡ F < 0 + deg ⁡ G
48 dgrcl ⊢ F ∈ Poly ⁡ S → deg ⁡ F ∈ ℕ 0
49 5 48 syl ⊢ φ → deg ⁡ F ∈ ℕ 0
50 49 nn0red ⊢ φ → deg ⁡ F ∈ ℝ
51 0red ⊢ φ → 0 ∈ ℝ
52 50 43 51 ltsubaddd ⊢ φ → deg ⁡ F − deg ⁡ G < 0 ↔ deg ⁡ F < 0 + deg ⁡ G
53 47 52 bitr4d ⊢ φ → deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G ↔ deg ⁡ F − deg ⁡ G < 0
54 39 53 orbi12d ⊢ φ → F − f G × f 0 𝑝 = 0 𝑝 ∨ deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G ↔ F = 0 𝑝 ∨ deg ⁡ F − deg ⁡ G < 0
55 9 54 mpbird ⊢ φ → F − f G × f 0 𝑝 = 0 𝑝 ∨ deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G
56 oveq2 ⊢ q = 0 𝑝 → G × f q = G × f 0 𝑝
57 56 oveq2d ⊢ q = 0 𝑝 → F − f G × f q = F − f G × f 0 𝑝
58 8 57 eqtrid ⊢ q = 0 𝑝 → R = F − f G × f 0 𝑝
59 58 eqeq1d ⊢ q = 0 𝑝 → R = 0 𝑝 ↔ F − f G × f 0 𝑝 = 0 𝑝
60 58 fveq2d ⊢ q = 0 𝑝 → deg ⁡ R = deg ⁡ F − f G × f 0 𝑝
61 60 breq1d ⊢ q = 0 𝑝 → deg ⁡ R < deg ⁡ G ↔ deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G
62 59 61 orbi12d ⊢ q = 0 𝑝 → R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G ↔ F − f G × f 0 𝑝 = 0 𝑝 ∨ deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G
63 62 rspcev ⊢ 0 𝑝 ∈ Poly ⁡ S ∧ F − f G × f 0 𝑝 = 0 𝑝 ∨ deg ⁡ F − f G × f 0 𝑝 < deg ⁡ G → ∃ q ∈ Poly ⁡ S R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G
64 12 55 63 syl2anc ⊢ φ → ∃ q ∈ Poly ⁡ S R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G