Metamath Proof Explorer


Theorem pmat1ovscd

Description: Entries of the identity polynomial matrix over a ring represented with "lifted scalars", deduction form. (Contributed by AV, 16-Nov-2019)

Ref Expression
Hypotheses pmat0opsc.p ⊢ P = Poly 1 ⁡ R
pmat0opsc.c ⊢ C = N Mat P
pmat0opsc.a ⊢ A = algSc ⁡ P
pmat0opsc.z ⊢ 0 ˙ = 0 R
pmat1opsc.o ⊢ 1 ˙ = 1 R
pmat1ovscd.n ⊢ φ → N ∈ Fin
pmat1ovscd.r ⊢ φ → R ∈ Ring
pmat1ovscd.i ⊢ φ → I ∈ N
pmat1ovscd.j ⊢ φ → J ∈ N
pmat1ovscd.u ⊢ U = 1 C
Assertion pmat1ovscd ⊢ φ → I U J = if I = J A ⁡ 1 ˙ A ⁡ 0 ˙

Proof

Step Hyp Ref Expression
1 pmat0opsc.p ⊢ P = Poly 1 ⁡ R
2 pmat0opsc.c ⊢ C = N Mat P
3 pmat0opsc.a ⊢ A = algSc ⁡ P
4 pmat0opsc.z ⊢ 0 ˙ = 0 R
5 pmat1opsc.o ⊢ 1 ˙ = 1 R
6 pmat1ovscd.n ⊢ φ → N ∈ Fin
7 pmat1ovscd.r ⊢ φ → R ∈ Ring
8 pmat1ovscd.i ⊢ φ → I ∈ N
9 pmat1ovscd.j ⊢ φ → J ∈ N
10 pmat1ovscd.u ⊢ U = 1 C
11 eqid ⊢ 0 P = 0 P
12 eqid ⊢ 1 P = 1 P
13 1 2 11 12 6 7 8 9 10 pmat1ovd ⊢ φ → I U J = if I = J 1 P 0 P
14 1 3 5 12 ply1scl1 ⊢ R ∈ Ring → A ⁡ 1 ˙ = 1 P
15 7 14 syl ⊢ φ → A ⁡ 1 ˙ = 1 P
16 15 eqcomd ⊢ φ → 1 P = A ⁡ 1 ˙
17 1 3 4 11 ply1scl0 ⊢ R ∈ Ring → A ⁡ 0 ˙ = 0 P
18 7 17 syl ⊢ φ → A ⁡ 0 ˙ = 0 P
19 18 eqcomd ⊢ φ → 0 P = A ⁡ 0 ˙
20 16 19 ifeq12d ⊢ φ → if I = J 1 P 0 P = if I = J A ⁡ 1 ˙ A ⁡ 0 ˙
21 13 20 eqtrd ⊢ φ → I U J = if I = J A ⁡ 1 ˙ A ⁡ 0 ˙