Metamath Proof Explorer


Theorem pmtrsn

Description: The value of the transposition generator function for a singleton is empty, i.e. there is no transposition for a singleton. This also holds for A e/ _V , i.e. for the empty set { A } = (/) resulting in ( pmTrsp(/) ) = (/) . (Contributed by AV, 6-Aug-2019)

Ref Expression
Assertion pmtrsn ⊢ pmTrsp ⁡ A = ∅

Proof

Step Hyp Ref Expression
1 snex ⊢ A ∈ V
2 eqid ⊢ pmTrsp ⁡ A = pmTrsp ⁡ A
3 2 pmtrfval ⊢ A ∈ V → pmTrsp ⁡ A = p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z
4 1 3 ax-mp ⊢ pmTrsp ⁡ A = p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z
5 eqid ⊢ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z
6 5 dmmpt ⊢ dom ⁡ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 | z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z ∈ V
7 2on0 ⊢ 2 𝑜 ≠ ∅
8 ensymb ⊢ ∅ ≈ 2 𝑜 ↔ 2 𝑜 ≈ ∅
9 en0 ⊢ 2 𝑜 ≈ ∅ ↔ 2 𝑜 = ∅
10 8 9 bitri ⊢ ∅ ≈ 2 𝑜 ↔ 2 𝑜 = ∅
11 7 10 nemtbir ⊢ ¬ ∅ ≈ 2 𝑜
12 snnen2o ⊢ ¬ A ≈ 2 𝑜
13 0ex ⊢ ∅ ∈ V
14 breq1 ⊢ y = ∅ → y ≈ 2 𝑜 ↔ ∅ ≈ 2 𝑜
15 14 notbid ⊢ y = ∅ → ¬ y ≈ 2 𝑜 ↔ ¬ ∅ ≈ 2 𝑜
16 breq1 ⊢ y = A → y ≈ 2 𝑜 ↔ A ≈ 2 𝑜
17 16 notbid ⊢ y = A → ¬ y ≈ 2 𝑜 ↔ ¬ A ≈ 2 𝑜
18 13 1 15 17 ralpr ⊢ ∀ y ∈ ∅ A ¬ y ≈ 2 𝑜 ↔ ¬ ∅ ≈ 2 𝑜 ∧ ¬ A ≈ 2 𝑜
19 11 12 18 mpbir2an ⊢ ∀ y ∈ ∅ A ¬ y ≈ 2 𝑜
20 pwsn ⊢ 𝒫 A = ∅ A
21 20 raleqi ⊢ ∀ y ∈ 𝒫 A ¬ y ≈ 2 𝑜 ↔ ∀ y ∈ ∅ A ¬ y ≈ 2 𝑜
22 19 21 mpbir ⊢ ∀ y ∈ 𝒫 A ¬ y ≈ 2 𝑜
23 rabeq0 ⊢ y ∈ 𝒫 A | y ≈ 2 𝑜 = ∅ ↔ ∀ y ∈ 𝒫 A ¬ y ≈ 2 𝑜
24 22 23 mpbir ⊢ y ∈ 𝒫 A | y ≈ 2 𝑜 = ∅
25 24 rabeqi ⊢ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 | z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z ∈ V = p ∈ ∅ | z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z ∈ V
26 rab0 ⊢ p ∈ ∅ | z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z ∈ V = ∅
27 6 25 26 3eqtri ⊢ dom ⁡ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = ∅
28 mptrel ⊢ Rel ⁡ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z
29 reldm0 ⊢ Rel ⁡ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z → p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = ∅ ↔ dom ⁡ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = ∅
30 28 29 ax-mp ⊢ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = ∅ ↔ dom ⁡ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = ∅
31 27 30 mpbir ⊢ p ∈ y ∈ 𝒫 A | y ≈ 2 𝑜 ⟼ z ∈ A ⟼ if z ∈ p ⋃ p ∖ z z = ∅
32 4 31 eqtri ⊢ pmTrsp ⁡ A = ∅