Metamath Proof Explorer


Theorem pntlemi

Description: Lemma for pnt . Eliminate some assumptions from pntlemj . (Contributed by Mario Carneiro, 13-Apr-2016)

Ref Expression
Hypotheses pntlem1.r ⊢ R = a ∈ ℝ + ⟼ ψ ⁡ a − a
pntlem1.a ⊢ φ → A ∈ ℝ +
pntlem1.b ⊢ φ → B ∈ ℝ +
pntlem1.l ⊢ φ → L ∈ 0 1
pntlem1.d ⊢ D = A + 1
pntlem1.f ⊢ F = 1 − 1 D ⁢ L 32 ⁢ B D 2
pntlem1.u ⊢ φ → U ∈ ℝ +
pntlem1.u2 ⊢ φ → U ≤ A
pntlem1.e ⊢ E = U D
pntlem1.k ⊢ K = e B E
pntlem1.y ⊢ φ → Y ∈ ℝ + ∧ 1 ≤ Y
pntlem1.x ⊢ φ → X ∈ ℝ + ∧ Y < X
pntlem1.c ⊢ φ → C ∈ ℝ +
pntlem1.w ⊢ W = Y + 4 L ⁢ E 2 + X ⁢ K 2 4 + e 32 ⁢ B U − E ⁢ L ⁢ E 2 ⁢ U ⋅ 3 + C
pntlem1.z ⊢ φ → Z ∈ W +∞
pntlem1.m ⊢ M = log ⁡ X log ⁡ K + 1
pntlem1.n ⊢ N = log ⁡ Z log ⁡ K 2
pntlem1.U ⊢ φ → ∀ z ∈ Y +∞ R ⁡ z z ≤ U
pntlem1.K ⊢ φ → ∀ y ∈ X +∞ ∃ z ∈ ℝ + y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E
pntlem1.o ⊢ O = Z K J + 1 + 1 … Z K J
Assertion pntlemi ⊢ φ ∧ J ∈ M ..^ N → U − E ⁢ L ⁢ E 8 ⁢ log ⁡ Z ≤ ∑ n ∈ O U n − R ⁡ Z n Z ⁢ log ⁡ n

Proof

Step Hyp Ref Expression
1 pntlem1.r ⊢ R = a ∈ ℝ + ⟼ ψ ⁡ a − a
2 pntlem1.a ⊢ φ → A ∈ ℝ +
3 pntlem1.b ⊢ φ → B ∈ ℝ +
4 pntlem1.l ⊢ φ → L ∈ 0 1
5 pntlem1.d ⊢ D = A + 1
6 pntlem1.f ⊢ F = 1 − 1 D ⁢ L 32 ⁢ B D 2
7 pntlem1.u ⊢ φ → U ∈ ℝ +
8 pntlem1.u2 ⊢ φ → U ≤ A
9 pntlem1.e ⊢ E = U D
10 pntlem1.k ⊢ K = e B E
11 pntlem1.y ⊢ φ → Y ∈ ℝ + ∧ 1 ≤ Y
12 pntlem1.x ⊢ φ → X ∈ ℝ + ∧ Y < X
13 pntlem1.c ⊢ φ → C ∈ ℝ +
14 pntlem1.w ⊢ W = Y + 4 L ⁢ E 2 + X ⁢ K 2 4 + e 32 ⁢ B U − E ⁢ L ⁢ E 2 ⁢ U ⋅ 3 + C
15 pntlem1.z ⊢ φ → Z ∈ W +∞
16 pntlem1.m ⊢ M = log ⁡ X log ⁡ K + 1
17 pntlem1.n ⊢ N = log ⁡ Z log ⁡ K 2
18 pntlem1.U ⊢ φ → ∀ z ∈ Y +∞ R ⁡ z z ≤ U
19 pntlem1.K ⊢ φ → ∀ y ∈ X +∞ ∃ z ∈ ℝ + y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E
20 pntlem1.o ⊢ O = Z K J + 1 + 1 … Z K J
21 breq2 ⊢ z = x → y < z ↔ y < x
22 oveq2 ⊢ z = x → 1 + L ⁢ E ⁢ z = 1 + L ⁢ E ⁢ x
23 22 breq1d ⊢ z = x → 1 + L ⁢ E ⁢ z < K ⁢ y ↔ 1 + L ⁢ E ⁢ x < K ⁢ y
24 21 23 anbi12d ⊢ z = x → y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ↔ y < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ y
25 id ⊢ z = x → z = x
26 25 22 oveq12d ⊢ z = x → z 1 + L ⁢ E ⁢ z = x 1 + L ⁢ E ⁢ x
27 26 raleqdv ⊢ z = x → ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E ↔ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
28 24 27 anbi12d ⊢ z = x → y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E ↔ y < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ y ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
29 28 cbvrexvw ⊢ ∃ z ∈ ℝ + y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E ↔ ∃ x ∈ ℝ + y < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ y ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
30 breq1 ⊢ y = K J → y < x ↔ K J < x
31 oveq2 ⊢ y = K J → K ⁢ y = K ⁢ K J
32 31 breq2d ⊢ y = K J → 1 + L ⁢ E ⁢ x < K ⁢ y ↔ 1 + L ⁢ E ⁢ x < K ⁢ K J
33 30 32 anbi12d ⊢ y = K J → y < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ y ↔ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J
34 33 anbi1d ⊢ y = K J → y < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ y ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E ↔ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
35 34 rexbidv ⊢ y = K J → ∃ x ∈ ℝ + y < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ y ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E ↔ ∃ x ∈ ℝ + K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
36 29 35 bitrid ⊢ y = K J → ∃ z ∈ ℝ + y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E ↔ ∃ x ∈ ℝ + K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
37 19 adantr ⊢ φ ∧ J ∈ M ..^ N → ∀ y ∈ X +∞ ∃ z ∈ ℝ + y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E
38 1 2 3 4 5 6 7 8 9 10 pntlemc ⊢ φ → E ∈ ℝ + ∧ K ∈ ℝ + ∧ E ∈ 0 1 ∧ 1 < K ∧ U − E ∈ ℝ +
39 38 simp2d ⊢ φ → K ∈ ℝ +
40 elfzoelz ⊢ J ∈ M ..^ N → J ∈ ℤ
41 rpexpcl ⊢ K ∈ ℝ + ∧ J ∈ ℤ → K J ∈ ℝ +
42 39 40 41 syl2an ⊢ φ ∧ J ∈ M ..^ N → K J ∈ ℝ +
43 42 rpred ⊢ φ ∧ J ∈ M ..^ N → K J ∈ ℝ
44 elfzofz ⊢ J ∈ M ..^ N → J ∈ M … N
45 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 pntlemh ⊢ φ ∧ J ∈ M … N → X < K J ∧ K J ≤ Z
46 44 45 sylan2 ⊢ φ ∧ J ∈ M ..^ N → X < K J ∧ K J ≤ Z
47 46 simpld ⊢ φ ∧ J ∈ M ..^ N → X < K J
48 12 simpld ⊢ φ → X ∈ ℝ +
49 48 adantr ⊢ φ ∧ J ∈ M ..^ N → X ∈ ℝ +
50 rpxr ⊢ X ∈ ℝ + → X ∈ ℝ *
51 elioopnf ⊢ X ∈ ℝ * → K J ∈ X +∞ ↔ K J ∈ ℝ ∧ X < K J
52 49 50 51 3syl ⊢ φ ∧ J ∈ M ..^ N → K J ∈ X +∞ ↔ K J ∈ ℝ ∧ X < K J
53 43 47 52 mpbir2and ⊢ φ ∧ J ∈ M ..^ N → K J ∈ X +∞
54 36 37 53 rspcdva ⊢ φ ∧ J ∈ M ..^ N → ∃ x ∈ ℝ + K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
55 2 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → A ∈ ℝ +
56 3 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → B ∈ ℝ +
57 4 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → L ∈ 0 1
58 7 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → U ∈ ℝ +
59 8 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → U ≤ A
60 11 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → Y ∈ ℝ + ∧ 1 ≤ Y
61 12 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → X ∈ ℝ + ∧ Y < X
62 13 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → C ∈ ℝ +
63 15 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → Z ∈ W +∞
64 18 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → ∀ z ∈ Y +∞ R ⁡ z z ≤ U
65 19 ad2antrr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → ∀ y ∈ X +∞ ∃ z ∈ ℝ + y < z ∧ 1 + L ⁢ E ⁢ z < K ⁢ y ∧ ∀ u ∈ z 1 + L ⁢ E ⁢ z R ⁡ u u ≤ E
66 simprl ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → x ∈ ℝ +
67 simprr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E
68 simplr ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → J ∈ M ..^ N
69 eqid ⊢ Z 1 + L ⁢ E ⁢ x + 1 … Z x = Z 1 + L ⁢ E ⁢ x + 1 … Z x
70 1 55 56 57 5 6 58 59 9 10 60 61 62 14 63 16 17 64 65 20 66 67 68 69 pntlemj ⊢ φ ∧ J ∈ M ..^ N ∧ x ∈ ℝ + ∧ K J < x ∧ 1 + L ⁢ E ⁢ x < K ⁢ K J ∧ ∀ u ∈ x 1 + L ⁢ E ⁢ x R ⁡ u u ≤ E → U − E ⁢ L ⁢ E 8 ⁢ log ⁡ Z ≤ ∑ n ∈ O U n − R ⁡ Z n Z ⁢ log ⁡ n
71 54 70 rexlimddv ⊢ φ ∧ J ∈ M ..^ N → U − E ⁢ L ⁢ E 8 ⁢ log ⁡ Z ≤ ∑ n ∈ O U n − R ⁡ Z n Z ⁢ log ⁡ n