Metamath Proof Explorer


Theorem prcssprc

Description: The superclass of a proper class is a proper class. (Contributed by AV, 27-Dec-2020)

Ref Expression
Assertion prcssprc ⊢ A ⊆ B ∧ A ∉ V → B ∉ V

Proof

Step Hyp Ref Expression
1 ssexg ⊢ A ⊆ B ∧ B ∈ V → A ∈ V
2 1 ex ⊢ A ⊆ B → B ∈ V → A ∈ V
3 2 nelcon3d ⊢ A ⊆ B → A ∉ V → B ∉ V
4 3 imp ⊢ A ⊆ B ∧ A ∉ V → B ∉ V