Metamath Proof Explorer


Theorem prdom2

Description: An unordered pair has at most two elements. (Contributed by FL, 22-Feb-2011)

Ref Expression
Assertion prdom2 ⊢ A ∈ C ∧ B ∈ D → A B ≼ 2 𝑜

Proof

Step Hyp Ref Expression
1 dfsn2 ⊢ A = A A
2 ensn1g ⊢ A ∈ C → A ≈ 1 𝑜
3 endom ⊢ A ≈ 1 𝑜 → A ≼ 1 𝑜
4 1sdom2 ⊢ 1 𝑜 ≺ 2 𝑜
5 domsdomtr ⊢ A ≼ 1 𝑜 ∧ 1 𝑜 ≺ 2 𝑜 → A ≺ 2 𝑜
6 sdomdom ⊢ A ≺ 2 𝑜 → A ≼ 2 𝑜
7 5 6 syl ⊢ A ≼ 1 𝑜 ∧ 1 𝑜 ≺ 2 𝑜 → A ≼ 2 𝑜
8 3 4 7 sylancl ⊢ A ≈ 1 𝑜 → A ≼ 2 𝑜
9 2 8 syl ⊢ A ∈ C → A ≼ 2 𝑜
10 1 9 eqbrtrrid ⊢ A ∈ C → A A ≼ 2 𝑜
11 preq2 ⊢ B = A → A B = A A
12 11 breq1d ⊢ B = A → A B ≼ 2 𝑜 ↔ A A ≼ 2 𝑜
13 10 12 imbitrrid ⊢ B = A → A ∈ C → A B ≼ 2 𝑜
14 13 eqcoms ⊢ A = B → A ∈ C → A B ≼ 2 𝑜
15 14 adantrd ⊢ A = B → A ∈ C ∧ B ∈ D → A B ≼ 2 𝑜
16 pr2ne ⊢ A ∈ C ∧ B ∈ D → A B ≈ 2 𝑜 ↔ A ≠ B
17 16 biimprd ⊢ A ∈ C ∧ B ∈ D → A ≠ B → A B ≈ 2 𝑜
18 endom ⊢ A B ≈ 2 𝑜 → A B ≼ 2 𝑜
19 17 18 syl6com ⊢ A ≠ B → A ∈ C ∧ B ∈ D → A B ≼ 2 𝑜
20 15 19 pm2.61ine ⊢ A ∈ C ∧ B ∈ D → A B ≼ 2 𝑜