Metamath Proof Explorer


Theorem preq2d

Description: Equality deduction for unordered pairs. (Contributed by NM, 19-Oct-2012)

Ref Expression
Hypothesis preq1d.1 φ A = B
Assertion preq2d φ C A = C B

Proof

Step Hyp Ref Expression
1 preq1d.1 φ A = B
2 preq2 A = B C A = C B
3 1 2 syl φ C A = C B