Metamath Proof Explorer


Theorem primefld1cl

Description: The prime field contains the unity element of the division ring. (Contributed by Thierry Arnoux, 22-Aug-2023)

Ref Expression
Hypothesis primefld1cl.1 ⊢ 1 ˙ = 1 R
Assertion primefld1cl ⊢ R ∈ DivRing → 1 ˙ ∈ ⋂ SubDRing ⁡ R

Proof

Step Hyp Ref Expression
1 primefld1cl.1 ⊢ 1 ˙ = 1 R
2 issdrg ⊢ s ∈ SubDRing ⁡ R ↔ R ∈ DivRing ∧ s ∈ SubRing ⁡ R ∧ R ↾ 𝑠 s ∈ DivRing
3 2 simp2bi ⊢ s ∈ SubDRing ⁡ R → s ∈ SubRing ⁡ R
4 3 a1i ⊢ R ∈ DivRing → s ∈ SubDRing ⁡ R → s ∈ SubRing ⁡ R
5 4 ssrdv ⊢ R ∈ DivRing → SubDRing ⁡ R ⊆ SubRing ⁡ R
6 eqid ⊢ Base R = Base R
7 6 sdrgid ⊢ R ∈ DivRing → Base R ∈ SubDRing ⁡ R
8 7 ne0d ⊢ R ∈ DivRing → SubDRing ⁡ R ≠ ∅
9 subrgint ⊢ SubDRing ⁡ R ⊆ SubRing ⁡ R ∧ SubDRing ⁡ R ≠ ∅ → ⋂ SubDRing ⁡ R ∈ SubRing ⁡ R
10 5 8 9 syl2anc ⊢ R ∈ DivRing → ⋂ SubDRing ⁡ R ∈ SubRing ⁡ R
11 1 subrg1cl ⊢ ⋂ SubDRing ⁡ R ∈ SubRing ⁡ R → 1 ˙ ∈ ⋂ SubDRing ⁡ R
12 10 11 syl ⊢ R ∈ DivRing → 1 ˙ ∈ ⋂ SubDRing ⁡ R