Metamath Proof Explorer


Theorem prodeq2sdv

Description: Equality deduction for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypothesis prodeq2sdv.1 φ B = C
Assertion prodeq2sdv φ k A B = k A C

Proof

Step Hyp Ref Expression
1 prodeq2sdv.1 φ B = C
2 1 adantr φ k A B = C
3 2 prodeq2dv φ k A B = k A C