Metamath Proof Explorer


Theorem pserdvlem1

Description: Lemma for pserdv . (Contributed by Mario Carneiro, 7-May-2015)

Ref Expression
Hypotheses pserf.g ⊢ G = x ∈ ℂ ⟼ n ∈ ℕ 0 ⟼ A ⁡ n ⁢ x n
pserf.f ⊢ F = y ∈ S ⟼ ∑ j ∈ ℕ 0 G ⁡ y ⁡ j
pserf.a ⊢ φ → A : ℕ 0 ⟶ ℂ
pserf.r ⊢ R = sup r ∈ ℝ | seq 0 + G ⁡ r ∈ dom ⁡ ⇝ ℝ * <
psercn.s ⊢ S = abs -1 0 R
psercn.m ⊢ M = if R ∈ ℝ a + R 2 a + 1
Assertion pserdvlem1 ⊢ φ ∧ a ∈ S → a + M 2 ∈ ℝ + ∧ a < a + M 2 ∧ a + M 2 < R

Proof

Step Hyp Ref Expression
1 pserf.g ⊢ G = x ∈ ℂ ⟼ n ∈ ℕ 0 ⟼ A ⁡ n ⁢ x n
2 pserf.f ⊢ F = y ∈ S ⟼ ∑ j ∈ ℕ 0 G ⁡ y ⁡ j
3 pserf.a ⊢ φ → A : ℕ 0 ⟶ ℂ
4 pserf.r ⊢ R = sup r ∈ ℝ | seq 0 + G ⁡ r ∈ dom ⁡ ⇝ ℝ * <
5 psercn.s ⊢ S = abs -1 0 R
6 psercn.m ⊢ M = if R ∈ ℝ a + R 2 a + 1
7 cnvimass ⊢ abs -1 0 R ⊆ dom ⁡ abs
8 absf ⊢ abs : ℂ ⟶ ℝ
9 8 fdmi ⊢ dom ⁡ abs = ℂ
10 7 9 sseqtri ⊢ abs -1 0 R ⊆ ℂ
11 5 10 eqsstri ⊢ S ⊆ ℂ
12 11 a1i ⊢ φ → S ⊆ ℂ
13 12 sselda ⊢ φ ∧ a ∈ S → a ∈ ℂ
14 13 abscld ⊢ φ ∧ a ∈ S → a ∈ ℝ
15 1 2 3 4 5 6 psercnlem1 ⊢ φ ∧ a ∈ S → M ∈ ℝ + ∧ a < M ∧ M < R
16 15 simp1d ⊢ φ ∧ a ∈ S → M ∈ ℝ +
17 16 rpred ⊢ φ ∧ a ∈ S → M ∈ ℝ
18 14 17 readdcld ⊢ φ ∧ a ∈ S → a + M ∈ ℝ
19 0red ⊢ φ ∧ a ∈ S → 0 ∈ ℝ
20 13 absge0d ⊢ φ ∧ a ∈ S → 0 ≤ a
21 14 16 ltaddrpd ⊢ φ ∧ a ∈ S → a < a + M
22 19 14 18 20 21 lelttrd ⊢ φ ∧ a ∈ S → 0 < a + M
23 18 22 elrpd ⊢ φ ∧ a ∈ S → a + M ∈ ℝ +
24 23 rphalfcld ⊢ φ ∧ a ∈ S → a + M 2 ∈ ℝ +
25 15 simp2d ⊢ φ ∧ a ∈ S → a < M
26 avglt1 ⊢ a ∈ ℝ ∧ M ∈ ℝ → a < M ↔ a < a + M 2
27 14 17 26 syl2anc ⊢ φ ∧ a ∈ S → a < M ↔ a < a + M 2
28 25 27 mpbid ⊢ φ ∧ a ∈ S → a < a + M 2
29 18 rehalfcld ⊢ φ ∧ a ∈ S → a + M 2 ∈ ℝ
30 29 rexrd ⊢ φ ∧ a ∈ S → a + M 2 ∈ ℝ *
31 17 rexrd ⊢ φ ∧ a ∈ S → M ∈ ℝ *
32 iccssxr ⊢ 0 +∞ ⊆ ℝ *
33 1 3 4 radcnvcl ⊢ φ → R ∈ 0 +∞
34 32 33 sselid ⊢ φ → R ∈ ℝ *
35 34 adantr ⊢ φ ∧ a ∈ S → R ∈ ℝ *
36 avglt2 ⊢ a ∈ ℝ ∧ M ∈ ℝ → a < M ↔ a + M 2 < M
37 14 17 36 syl2anc ⊢ φ ∧ a ∈ S → a < M ↔ a + M 2 < M
38 25 37 mpbid ⊢ φ ∧ a ∈ S → a + M 2 < M
39 15 simp3d ⊢ φ ∧ a ∈ S → M < R
40 30 31 35 38 39 xrlttrd ⊢ φ ∧ a ∈ S → a + M 2 < R
41 24 28 40 3jca ⊢ φ ∧ a ∈ S → a + M 2 ∈ ℝ + ∧ a < a + M 2 ∧ a + M 2 < R