Metamath Proof Explorer


Theorem psgnprfval

Description: The permutation sign function for a pair. (Contributed by AV, 10-Dec-2018)

Ref Expression
Hypotheses psgnprfval.0 ⊢ D = 1 2
psgnprfval.g ⊢ G = SymGrp ⁡ D
psgnprfval.b ⊢ B = Base G
psgnprfval.t ⊢ T = ran ⁡ pmTrsp ⁡ D
psgnprfval.n ⊢ N = pmSgn ⁡ D
Assertion psgnprfval ⊢ X ∈ B → N ⁡ X = ι s | ∃ w ∈ Word T X = ∑ G w ∧ s = − 1 w

Proof

Step Hyp Ref Expression
1 psgnprfval.0 ⊢ D = 1 2
2 psgnprfval.g ⊢ G = SymGrp ⁡ D
3 psgnprfval.b ⊢ B = Base G
4 psgnprfval.t ⊢ T = ran ⁡ pmTrsp ⁡ D
5 psgnprfval.n ⊢ N = pmSgn ⁡ D
6 id ⊢ X ∈ B → X ∈ B
7 elpri ⊢ X ∈ 1 1 2 2 1 2 2 1 → X = 1 1 2 2 ∨ X = 1 2 2 1
8 prfi ⊢ 1 1 2 2 ∈ Fin
9 eleq1 ⊢ X = 1 1 2 2 → X ∈ Fin ↔ 1 1 2 2 ∈ Fin
10 8 9 mpbiri ⊢ X = 1 1 2 2 → X ∈ Fin
11 prfi ⊢ 1 2 2 1 ∈ Fin
12 eleq1 ⊢ X = 1 2 2 1 → X ∈ Fin ↔ 1 2 2 1 ∈ Fin
13 11 12 mpbiri ⊢ X = 1 2 2 1 → X ∈ Fin
14 10 13 jaoi ⊢ X = 1 1 2 2 ∨ X = 1 2 2 1 → X ∈ Fin
15 diffi ⊢ X ∈ Fin → X ∖ I ∈ Fin
16 dmfi ⊢ X ∖ I ∈ Fin → dom ⁡ X ∖ I ∈ Fin
17 7 14 15 16 4syl ⊢ X ∈ 1 1 2 2 1 2 2 1 → dom ⁡ X ∖ I ∈ Fin
18 1ex ⊢ 1 ∈ V
19 2nn ⊢ 2 ∈ ℕ
20 2 3 1 symg2bas ⊢ 1 ∈ V ∧ 2 ∈ ℕ → B = 1 1 2 2 1 2 2 1
21 18 19 20 mp2an ⊢ B = 1 1 2 2 1 2 2 1
22 17 21 eleq2s ⊢ X ∈ B → dom ⁡ X ∖ I ∈ Fin
23 2 5 3 psgneldm ⊢ X ∈ dom ⁡ N ↔ X ∈ B ∧ dom ⁡ X ∖ I ∈ Fin
24 6 22 23 sylanbrc ⊢ X ∈ B → X ∈ dom ⁡ N
25 2 4 5 psgnval ⊢ X ∈ dom ⁡ N → N ⁡ X = ι s | ∃ w ∈ Word T X = ∑ G w ∧ s = − 1 w
26 24 25 syl ⊢ X ∈ B → N ⁡ X = ι s | ∃ w ∈ Word T X = ∑ G w ∧ s = − 1 w
27 6 26 syl ⊢ X ∈ B → N ⁡ X = ι s | ∃ w ∈ Word T X = ∑ G w ∧ s = − 1 w