Metamath Proof Explorer


Theorem psseq12i

Description: An equality inference for the proper subclass relationship. (Contributed by NM, 9-Jun-2004)

Ref Expression
Hypotheses psseq1i.1 ⊢ A = B
psseq12i.2 ⊢ C = D
Assertion psseq12i ⊢ A ⊂ C ↔ B ⊂ D

Proof

Step Hyp Ref Expression
1 psseq1i.1 ⊢ A = B
2 psseq12i.2 ⊢ C = D
3 1 psseq1i ⊢ A ⊂ C ↔ B ⊂ C
4 2 psseq2i ⊢ B ⊂ C ↔ B ⊂ D
5 3 4 bitri ⊢ A ⊂ C ↔ B ⊂ D