Metamath Proof Explorer


Theorem pssnssi

Description: A proper subclass does not include the other class. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis pssnssi.1 ⊢ A ⊂ B
Assertion pssnssi ⊢ ¬ B ⊆ A

Proof

Step Hyp Ref Expression
1 pssnssi.1 ⊢ A ⊂ B
2 dfpss3 ⊢ A ⊂ B ↔ A ⊆ B ∧ ¬ B ⊆ A
3 1 2 mpbi ⊢ A ⊆ B ∧ ¬ B ⊆ A
4 3 simpri ⊢ ¬ B ⊆ A