Metamath Proof Explorer


Theorem pweqd

Description: Equality deduction for power class. (Contributed by NM, 27-Nov-2013)

Ref Expression
Hypothesis pweqd.1 φA=B
Assertion pweqd φ𝒫A=𝒫B

Proof

Step Hyp Ref Expression
1 pweqd.1 φA=B
2 pweq A=B𝒫A=𝒫B
3 1 2 syl φ𝒫A=𝒫B