Metamath Proof Explorer


Theorem pythagtrip

Description: Parameterize the Pythagorean triples. If A , B , and C are naturals, then they obey the Pythagorean triple formula iff they are parameterized by three naturals. This proof follows the Isabelle proof at http://afp.sourceforge.net/entries/Fermat3_4.shtml . This is Metamath 100 proof #23. (Contributed by Scott Fenton, 19-Apr-2014)

Ref Expression
Assertion pythagtrip ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 = C 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2

Proof

Step Hyp Ref Expression
1 divgcdodd ⊢ A ∈ ℕ ∧ B ∈ ℕ → ¬ 2 ∥ A A gcd B ∨ ¬ 2 ∥ B A gcd B
2 1 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → ¬ 2 ∥ A A gcd B ∨ ¬ 2 ∥ B A gcd B
3 2 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ¬ 2 ∥ A A gcd B ∨ ¬ 2 ∥ B A gcd B
4 pythagtriplem19 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
5 4 3expia ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
6 simp12 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ B A gcd B → B ∈ ℕ
7 simp11 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ B A gcd B → A ∈ ℕ
8 simp13 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ B A gcd B → C ∈ ℕ
9 nnsqcl ⊢ A ∈ ℕ → A 2 ∈ ℕ
10 9 nncnd ⊢ A ∈ ℕ → A 2 ∈ ℂ
11 10 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 ∈ ℂ
12 nnsqcl ⊢ B ∈ ℕ → B 2 ∈ ℕ
13 12 nncnd ⊢ B ∈ ℕ → B 2 ∈ ℂ
14 13 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B 2 ∈ ℂ
15 11 14 addcomd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 = B 2 + A 2
16 15 eqeq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 = C 2 ↔ B 2 + A 2 = C 2
17 16 biimpa ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → B 2 + A 2 = C 2
18 17 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ B A gcd B → B 2 + A 2 = C 2
19 nnz ⊢ A ∈ ℕ → A ∈ ℤ
20 19 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℤ
21 nnz ⊢ B ∈ ℕ → B ∈ ℤ
22 21 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℤ
23 22 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → B ∈ ℤ
24 gcdcom ⊢ A ∈ ℤ ∧ B ∈ ℤ → A gcd B = B gcd A
25 20 23 24 syl2an2r ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A gcd B = B gcd A
26 25 oveq2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → B A gcd B = B B gcd A
27 26 breq2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → 2 ∥ B A gcd B ↔ 2 ∥ B B gcd A
28 27 notbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ¬ 2 ∥ B A gcd B ↔ ¬ 2 ∥ B B gcd A
29 28 biimp3a ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ B A gcd B → ¬ 2 ∥ B B gcd A
30 pythagtriplem19 ⊢ B ∈ ℕ ∧ A ∈ ℕ ∧ C ∈ ℕ ∧ B 2 + A 2 = C 2 ∧ ¬ 2 ∥ B B gcd A → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
31 6 7 8 18 29 30 syl311anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ B A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
32 31 3expia ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ¬ 2 ∥ B A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
33 5 32 orim12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ¬ 2 ∥ A A gcd B ∨ ¬ 2 ∥ B A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
34 3 33 mpd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
35 ovex ⊢ k ⁢ m 2 − n 2 ∈ V
36 ovex ⊢ k ⁢ 2 ⁢ m ⁢ n ∈ V
37 preq12bg ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ k ⁢ m 2 − n 2 ∈ V ∧ k ⁢ 2 ⁢ m ⁢ n ∈ V → A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2
38 35 36 37 mpanr12 ⊢ A ∈ ℕ ∧ B ∈ ℕ → A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2
39 38 anbi1d ⊢ A ∈ ℕ ∧ B ∈ ℕ → A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2
40 39 rexbidv ⊢ A ∈ ℕ ∧ B ∈ ℕ → ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2
41 40 2rexbidv ⊢ A ∈ ℕ ∧ B ∈ ℕ → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2
42 andir ⊢ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2
43 df-3an ⊢ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
44 df-3an ⊢ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2
45 43 44 orbi12i ⊢ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2
46 3ancoma ⊢ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
47 46 orbi2i ⊢ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
48 42 45 47 3bitr2i ⊢ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
49 48 rexbii ⊢ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
50 49 2rexbii ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
51 r19.43 ⊢ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
52 51 2rexbii ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
53 r19.43 ⊢ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
54 53 rexbii ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
55 r19.43 ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
56 54 55 bitri ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
57 52 56 bitri ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
58 50 57 bitri ⊢ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∨ A = k ⁢ 2 ⁢ m ⁢ n ∧ B = k ⁢ m 2 − n 2 ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
59 41 58 bitrdi ⊢ A ∈ ℕ ∧ B ∈ ℕ → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
60 59 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
61 60 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ∨ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ B = k ⁢ m 2 − n 2 ∧ A = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
62 34 61 mpbird ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
63 62 ex ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 = C 2 → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
64 pythagtriplem2 ⊢ A ∈ ℕ ∧ B ∈ ℕ → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 → A 2 + B 2 = C 2
65 64 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 → A 2 + B 2 = C 2
66 63 65 impbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 = C 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A B = k ⁢ m 2 − n 2 k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2