Metamath Proof Explorer


Theorem pythagtriplem12

Description: Lemma for pythagtrip . Calculate the square of M . (Contributed by Scott Fenton, 17-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)

Ref Expression
Hypothesis pythagtriplem11.1 ⊢ M = C + B + C − B 2
Assertion pythagtriplem12 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → M 2 = C + A 2

Proof

Step Hyp Ref Expression
1 pythagtriplem11.1 ⊢ M = C + B + C − B 2
2 1 oveq1i ⊢ M 2 = C + B + C − B 2 2
3 nncn ⊢ C ∈ ℕ → C ∈ ℂ
4 nncn ⊢ B ∈ ℕ → B ∈ ℂ
5 addcl ⊢ C ∈ ℂ ∧ B ∈ ℂ → C + B ∈ ℂ
6 3 4 5 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℂ
7 6 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℂ
8 7 sqrtcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℂ
9 subcl ⊢ C ∈ ℂ ∧ B ∈ ℂ → C − B ∈ ℂ
10 3 4 9 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℂ
11 10 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℂ
12 11 sqrtcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℂ
13 8 12 addcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B + C − B ∈ ℂ
14 13 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B ∈ ℂ
15 2cn ⊢ 2 ∈ ℂ
16 2ne0 ⊢ 2 ≠ 0
17 sqdiv ⊢ C + B + C − B ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → C + B + C − B 2 2 = C + B + C − B 2 2 2
18 15 16 17 mp3an23 ⊢ C + B + C − B ∈ ℂ → C + B + C − B 2 2 = C + B + C − B 2 2 2
19 15 sqvali ⊢ 2 2 = 2 ⋅ 2
20 19 oveq2i ⊢ C + B + C − B 2 2 2 = C + B + C − B 2 2 ⋅ 2
21 18 20 eqtrdi ⊢ C + B + C − B ∈ ℂ → C + B + C − B 2 2 = C + B + C − B 2 2 ⋅ 2
22 14 21 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B 2 2 = C + B + C − B 2 2 ⋅ 2
23 8 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ∈ ℂ
24 12 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B ∈ ℂ
25 binom2 ⊢ C + B ∈ ℂ ∧ C − B ∈ ℂ → C + B + C − B 2 = C + B 2 + 2 ⁢ C + B ⁢ C − B + C − B 2
26 23 24 25 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B 2 = C + B 2 + 2 ⁢ C + B ⁢ C − B + C − B 2
27 nnre ⊢ C ∈ ℕ → C ∈ ℝ
28 nnre ⊢ B ∈ ℕ → B ∈ ℝ
29 readdcl ⊢ C ∈ ℝ ∧ B ∈ ℝ → C + B ∈ ℝ
30 27 28 29 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℝ
31 30 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℝ
32 31 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ∈ ℝ
33 27 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C ∈ ℝ
34 28 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℝ
35 nngt0 ⊢ C ∈ ℕ → 0 < C
36 35 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < C
37 nngt0 ⊢ B ∈ ℕ → 0 < B
38 37 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < B
39 33 34 36 38 addgt0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < C + B
40 39 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 < C + B
41 0re ⊢ 0 ∈ ℝ
42 ltle ⊢ 0 ∈ ℝ ∧ C + B ∈ ℝ → 0 < C + B → 0 ≤ C + B
43 41 42 mpan ⊢ C + B ∈ ℝ → 0 < C + B → 0 ≤ C + B
44 32 40 43 sylc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 ≤ C + B
45 resqrtth ⊢ C + B ∈ ℝ ∧ 0 ≤ C + B → C + B 2 = C + B
46 32 44 45 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 = C + B
47 46 oveq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 + 2 ⁢ C + B ⁢ C − B = C + B + 2 ⁢ C + B ⁢ C − B
48 resubcl ⊢ C ∈ ℝ ∧ B ∈ ℝ → C − B ∈ ℝ
49 27 28 48 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℝ
50 49 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℝ
51 50 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B ∈ ℝ
52 pythagtriplem10 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → 0 < C − B
53 52 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 < C − B
54 ltle ⊢ 0 ∈ ℝ ∧ C − B ∈ ℝ → 0 < C − B → 0 ≤ C − B
55 41 54 mpan ⊢ C − B ∈ ℝ → 0 < C − B → 0 ≤ C − B
56 51 53 55 sylc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 ≤ C − B
57 resqrtth ⊢ C − B ∈ ℝ ∧ 0 ≤ C − B → C − B 2 = C − B
58 51 56 57 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B 2 = C − B
59 47 58 oveq12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 + 2 ⁢ C + B ⁢ C − B + C − B 2 = C + B + 2 ⁢ C + B ⁢ C − B + C − B
60 7 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ∈ ℂ
61 8 12 mulcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ⁢ C − B ∈ ℂ
62 mulcl ⊢ 2 ∈ ℂ ∧ C + B ⁢ C − B ∈ ℂ → 2 ⁢ C + B ⁢ C − B ∈ ℂ
63 15 61 62 sylancr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 2 ⁢ C + B ⁢ C − B ∈ ℂ
64 63 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + B ⁢ C − B ∈ ℂ
65 11 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B ∈ ℂ
66 60 64 65 add32d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + 2 ⁢ C + B ⁢ C − B + C − B = C + B + C − B + 2 ⁢ C + B ⁢ C − B
67 3 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C ∈ ℂ
68 67 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C ∈ ℂ
69 nncn ⊢ A ∈ ℕ → A ∈ ℂ
70 69 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℂ
71 70 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A ∈ ℂ
72 adddi ⊢ 2 ∈ ℂ ∧ C ∈ ℂ ∧ A ∈ ℂ → 2 ⁢ C + A = 2 ⁢ C + 2 ⁢ A
73 15 68 71 72 mp3an2i ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + A = 2 ⁢ C + 2 ⁢ A
74 4 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℂ
75 74 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → B ∈ ℂ
76 68 75 68 ppncand ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B = C + C
77 68 2timesd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C = C + C
78 76 77 eqtr4d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B = 2 ⁢ C
79 oveq1 ⊢ A 2 + B 2 = C 2 → A 2 + B 2 - B 2 = C 2 − B 2
80 79 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 + B 2 - B 2 = C 2 − B 2
81 71 sqcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 ∈ ℂ
82 75 sqcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → B 2 ∈ ℂ
83 81 82 pncand ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 + B 2 - B 2 = A 2
84 subsq ⊢ C ∈ ℂ ∧ B ∈ ℂ → C 2 − B 2 = C + B ⁢ C − B
85 68 75 84 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C 2 − B 2 = C + B ⁢ C − B
86 80 83 85 3eqtr3rd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = A 2
87 86 fveq2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = A 2
88 32 44 51 56 sqrtmuld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = C + B ⁢ C − B
89 nnre ⊢ A ∈ ℕ → A ∈ ℝ
90 89 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℝ
91 90 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A ∈ ℝ
92 nnnn0 ⊢ A ∈ ℕ → A ∈ ℕ 0
93 92 nn0ge0d ⊢ A ∈ ℕ → 0 ≤ A
94 93 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 ≤ A
95 94 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 ≤ A
96 91 95 sqrtsqd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 = A
97 87 88 96 3eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = A
98 97 oveq2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + B ⁢ C − B = 2 ⁢ A
99 78 98 oveq12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B + 2 ⁢ C + B ⁢ C − B = 2 ⁢ C + 2 ⁢ A
100 73 99 eqtr4d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + A = C + B + C − B + 2 ⁢ C + B ⁢ C − B
101 66 100 eqtr4d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + 2 ⁢ C + B ⁢ C − B + C − B = 2 ⁢ C + A
102 26 59 101 3eqtrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B 2 = 2 ⁢ C + A
103 102 oveq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B 2 2 ⋅ 2 = 2 ⁢ C + A 2 ⋅ 2
104 addcl ⊢ C ∈ ℂ ∧ A ∈ ℂ → C + A ∈ ℂ
105 3 69 104 syl2anr ⊢ A ∈ ℕ ∧ C ∈ ℕ → C + A ∈ ℂ
106 105 3adant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + A ∈ ℂ
107 106 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + A ∈ ℂ
108 mulcl ⊢ 2 ∈ ℂ ∧ C + A ∈ ℂ → 2 ⁢ C + A ∈ ℂ
109 15 107 108 sylancr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + A ∈ ℂ
110 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
111 divdiv1 ⊢ 2 ⁢ C + A ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⁢ C + A 2 2 = 2 ⁢ C + A 2 ⋅ 2
112 110 110 111 mp3an23 ⊢ 2 ⁢ C + A ∈ ℂ → 2 ⁢ C + A 2 2 = 2 ⁢ C + A 2 ⋅ 2
113 109 112 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + A 2 2 = 2 ⁢ C + A 2 ⋅ 2
114 103 113 eqtr4d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B 2 2 ⋅ 2 = 2 ⁢ C + A 2 2
115 divcan3 ⊢ C + A ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⁢ C + A 2 = C + A
116 15 16 115 mp3an23 ⊢ C + A ∈ ℂ → 2 ⁢ C + A 2 = C + A
117 107 116 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + A 2 = C + A
118 117 oveq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + A 2 2 = C + A 2
119 22 114 118 3eqtrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B 2 2 = C + A 2
120 2 119 eqtrid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → M 2 = C + A 2