Metamath Proof Explorer


Theorem pythagtriplem14

Description: Lemma for pythagtrip . Calculate the square of N . (Contributed by Scott Fenton, 17-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)

Ref Expression
Hypothesis pythagtriplem13.1 ⊢ N = C + B − C − B 2
Assertion pythagtriplem14 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → N 2 = C − A 2

Proof

Step Hyp Ref Expression
1 pythagtriplem13.1 ⊢ N = C + B − C − B 2
2 1 oveq1i ⊢ N 2 = C + B − C − B 2 2
3 nncn ⊢ C ∈ ℕ → C ∈ ℂ
4 nncn ⊢ B ∈ ℕ → B ∈ ℂ
5 addcl ⊢ C ∈ ℂ ∧ B ∈ ℂ → C + B ∈ ℂ
6 3 4 5 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℂ
7 6 sqrtcld ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℂ
8 subcl ⊢ C ∈ ℂ ∧ B ∈ ℂ → C − B ∈ ℂ
9 3 4 8 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℂ
10 9 sqrtcld ⊢ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℂ
11 7 10 subcld ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B − C − B ∈ ℂ
12 11 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B − C − B ∈ ℂ
13 12 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B ∈ ℂ
14 2cn ⊢ 2 ∈ ℂ
15 2ne0 ⊢ 2 ≠ 0
16 sqdiv ⊢ C + B − C − B ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → C + B − C − B 2 2 = C + B − C − B 2 2 2
17 14 15 16 mp3an23 ⊢ C + B − C − B ∈ ℂ → C + B − C − B 2 2 = C + B − C − B 2 2 2
18 13 17 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 = C + B − C − B 2 2 2
19 14 sqvali ⊢ 2 2 = 2 ⋅ 2
20 19 oveq2i ⊢ C + B − C − B 2 2 2 = C + B − C − B 2 2 ⋅ 2
21 13 sqcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 ∈ ℂ
22 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
23 divdiv1 ⊢ C + B − C − B 2 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → C + B − C − B 2 2 2 = C + B − C − B 2 2 ⋅ 2
24 22 22 23 mp3an23 ⊢ C + B − C − B 2 ∈ ℂ → C + B − C − B 2 2 2 = C + B − C − B 2 2 ⋅ 2
25 21 24 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 2 = C + B − C − B 2 2 ⋅ 2
26 simp12 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → B ∈ ℕ
27 simp13 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C ∈ ℕ
28 26 27 7 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ∈ ℂ
29 26 27 10 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B ∈ ℂ
30 binom2sub ⊢ C + B ∈ ℂ ∧ C − B ∈ ℂ → C + B − C − B 2 = C + B 2 - 2 ⁢ C + B ⁢ C − B + C − B 2
31 28 29 30 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 = C + B 2 - 2 ⁢ C + B ⁢ C − B + C − B 2
32 nnre ⊢ C ∈ ℕ → C ∈ ℝ
33 nnre ⊢ B ∈ ℕ → B ∈ ℝ
34 readdcl ⊢ C ∈ ℝ ∧ B ∈ ℝ → C + B ∈ ℝ
35 32 33 34 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℝ
36 35 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℝ
37 36 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ∈ ℝ
38 37 recnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ∈ ℂ
39 resubcl ⊢ C ∈ ℝ ∧ B ∈ ℝ → C − B ∈ ℝ
40 32 33 39 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℝ
41 40 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℝ
42 41 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B ∈ ℝ
43 42 recnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B ∈ ℂ
44 7 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ∈ ℂ
45 10 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C − B ∈ ℂ
46 44 45 mulcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B ⁢ C − B ∈ ℂ
47 mulcl ⊢ 2 ∈ ℂ ∧ C + B ⁢ C − B ∈ ℂ → 2 ⁢ C + B ⁢ C − B ∈ ℂ
48 14 46 47 sylancr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 2 ⁢ C + B ⁢ C − B ∈ ℂ
49 48 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + B ⁢ C − B ∈ ℂ
50 38 43 49 addsubd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B - 2 ⁢ C + B ⁢ C − B = C + B - 2 ⁢ C + B ⁢ C − B + C - B
51 27 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C ∈ ℂ
52 simp11 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A ∈ ℕ
53 52 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A ∈ ℂ
54 subdi ⊢ 2 ∈ ℂ ∧ C ∈ ℂ ∧ A ∈ ℂ → 2 ⁢ C − A = 2 ⁢ C − 2 ⁢ A
55 14 51 53 54 mp3an2i ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C − A = 2 ⁢ C − 2 ⁢ A
56 ppncan ⊢ C ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ → C + B + C − B = C + C
57 56 3anidm13 ⊢ C ∈ ℂ ∧ B ∈ ℂ → C + B + C − B = C + C
58 2times ⊢ C ∈ ℂ → 2 ⁢ C = C + C
59 58 adantr ⊢ C ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ C = C + C
60 57 59 eqtr4d ⊢ C ∈ ℂ ∧ B ∈ ℂ → C + B + C − B = 2 ⁢ C
61 3 4 60 syl2anr ⊢ B ∈ ℕ ∧ C ∈ ℕ → C + B + C − B = 2 ⁢ C
62 61 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C + B + C − B = 2 ⁢ C
63 62 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B = 2 ⁢ C
64 26 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → B ∈ ℂ
65 subsq ⊢ C ∈ ℂ ∧ B ∈ ℂ → C 2 − B 2 = C + B ⁢ C − B
66 51 64 65 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C 2 − B 2 = C + B ⁢ C − B
67 oveq1 ⊢ A 2 + B 2 = C 2 → A 2 + B 2 - B 2 = C 2 − B 2
68 67 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 + B 2 - B 2 = C 2 − B 2
69 nncn ⊢ A ∈ ℕ → A ∈ ℂ
70 69 sqcld ⊢ A ∈ ℕ → A 2 ∈ ℂ
71 70 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 ∈ ℂ
72 4 sqcld ⊢ B ∈ ℕ → B 2 ∈ ℂ
73 72 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B 2 ∈ ℂ
74 71 73 pncand ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 - B 2 = A 2
75 74 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 + B 2 - B 2 = A 2
76 68 75 eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C 2 − B 2 = A 2
77 66 76 eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = A 2
78 77 fveq2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = A 2
79 32 adantl ⊢ B ∈ ℕ ∧ C ∈ ℕ → C ∈ ℝ
80 33 adantr ⊢ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℝ
81 nngt0 ⊢ C ∈ ℕ → 0 < C
82 81 adantl ⊢ B ∈ ℕ ∧ C ∈ ℕ → 0 < C
83 nngt0 ⊢ B ∈ ℕ → 0 < B
84 83 adantr ⊢ B ∈ ℕ ∧ C ∈ ℕ → 0 < B
85 79 80 82 84 addgt0d ⊢ B ∈ ℕ ∧ C ∈ ℕ → 0 < C + B
86 0re ⊢ 0 ∈ ℝ
87 ltle ⊢ 0 ∈ ℝ ∧ C + B ∈ ℝ → 0 < C + B → 0 ≤ C + B
88 86 87 mpan ⊢ C + B ∈ ℝ → 0 < C + B → 0 ≤ C + B
89 35 85 88 sylc ⊢ B ∈ ℕ ∧ C ∈ ℕ → 0 ≤ C + B
90 89 3adant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 ≤ C + B
91 90 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 ≤ C + B
92 pythagtriplem10 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → 0 < C − B
93 92 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 < C − B
94 ltle ⊢ 0 ∈ ℝ ∧ C − B ∈ ℝ → 0 < C − B → 0 ≤ C − B
95 86 94 mpan ⊢ C − B ∈ ℝ → 0 < C − B → 0 ≤ C − B
96 42 93 95 sylc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 ≤ C − B
97 37 91 42 96 sqrtmuld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = C + B ⁢ C − B
98 78 97 eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 = C + B ⁢ C − B
99 nnre ⊢ A ∈ ℕ → A ∈ ℝ
100 99 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℝ
101 100 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A ∈ ℝ
102 nnnn0 ⊢ A ∈ ℕ → A ∈ ℕ 0
103 102 nn0ge0d ⊢ A ∈ ℕ → 0 ≤ A
104 103 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 ≤ A
105 104 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 0 ≤ A
106 101 105 sqrtsqd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A 2 = A
107 98 106 eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B ⁢ C − B = A
108 107 oveq2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C + B ⁢ C − B = 2 ⁢ A
109 63 108 oveq12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B + C − B - 2 ⁢ C + B ⁢ C − B = 2 ⁢ C − 2 ⁢ A
110 55 109 eqtr4d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C − A = C + B + C − B - 2 ⁢ C + B ⁢ C − B
111 resqrtth ⊢ C + B ∈ ℝ ∧ 0 ≤ C + B → C + B 2 = C + B
112 37 91 111 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 = C + B
113 112 oveq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 − 2 ⁢ C + B ⁢ C − B = C + B - 2 ⁢ C + B ⁢ C − B
114 resqrtth ⊢ C − B ∈ ℝ ∧ 0 ≤ C − B → C − B 2 = C − B
115 42 96 114 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − B 2 = C − B
116 113 115 oveq12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 - 2 ⁢ C + B ⁢ C − B + C − B 2 = C + B - 2 ⁢ C + B ⁢ C − B + C - B
117 50 110 116 3eqtr4rd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B 2 - 2 ⁢ C + B ⁢ C − B + C − B 2 = 2 ⁢ C − A
118 31 117 eqtrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 = 2 ⁢ C − A
119 118 oveq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 = 2 ⁢ C − A 2
120 subcl ⊢ C ∈ ℂ ∧ A ∈ ℂ → C − A ∈ ℂ
121 3 69 120 syl2anr ⊢ A ∈ ℕ ∧ C ∈ ℕ → C − A ∈ ℂ
122 121 3adant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C − A ∈ ℂ
123 122 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C − A ∈ ℂ
124 divcan3 ⊢ C − A ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⁢ C − A 2 = C − A
125 14 15 124 mp3an23 ⊢ C − A ∈ ℂ → 2 ⁢ C − A 2 = C − A
126 123 125 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → 2 ⁢ C − A 2 = C − A
127 119 126 eqtrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 = C − A
128 127 oveq1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 2 = C − A 2
129 25 128 eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 ⋅ 2 = C − A 2
130 20 129 eqtrid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 2 = C − A 2
131 18 130 eqtrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → C + B − C − B 2 2 = C − A 2
132 2 131 eqtrid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → N 2 = C − A 2