Metamath Proof Explorer


Theorem pythagtriplem19

Description: Lemma for pythagtrip . Introduce k and remove the relative primality requirement. (Contributed by Scott Fenton, 18-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)

Ref Expression
Assertion pythagtriplem19 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2

Proof

Step Hyp Ref Expression
1 gcdnncl ⊢ A ∈ ℕ ∧ B ∈ ℕ → A gcd B ∈ ℕ
2 1 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∈ ℕ
3 2 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A gcd B ∈ ℕ
4 nnz ⊢ A ∈ ℕ → A ∈ ℤ
5 nnz ⊢ B ∈ ℕ → B ∈ ℤ
6 gcddvds ⊢ A ∈ ℤ ∧ B ∈ ℤ → A gcd B ∥ A ∧ A gcd B ∥ B
7 4 5 6 syl2an ⊢ A ∈ ℕ ∧ B ∈ ℕ → A gcd B ∥ A ∧ A gcd B ∥ B
8 7 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ A ∧ A gcd B ∥ B
9 8 simpld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ A
10 2 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∈ ℤ
11 2 nnne0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ≠ 0
12 4 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℤ
13 dvdsval2 ⊢ A gcd B ∈ ℤ ∧ A gcd B ≠ 0 ∧ A ∈ ℤ → A gcd B ∥ A ↔ A A gcd B ∈ ℤ
14 10 11 12 13 syl3anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ A ↔ A A gcd B ∈ ℤ
15 9 14 mpbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A A gcd B ∈ ℤ
16 nnre ⊢ A ∈ ℕ → A ∈ ℝ
17 16 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℝ
18 2 nnred ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∈ ℝ
19 nngt0 ⊢ A ∈ ℕ → 0 < A
20 19 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < A
21 2 nngt0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < A gcd B
22 17 18 20 21 divgt0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < A A gcd B
23 elnnz ⊢ A A gcd B ∈ ℕ ↔ A A gcd B ∈ ℤ ∧ 0 < A A gcd B
24 15 22 23 sylanbrc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A A gcd B ∈ ℕ
25 24 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A A gcd B ∈ ℕ
26 8 simprd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ B
27 5 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℤ
28 dvdsval2 ⊢ A gcd B ∈ ℤ ∧ A gcd B ≠ 0 ∧ B ∈ ℤ → A gcd B ∥ B ↔ B A gcd B ∈ ℤ
29 10 11 27 28 syl3anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ B ↔ B A gcd B ∈ ℤ
30 26 29 mpbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B A gcd B ∈ ℤ
31 nnre ⊢ B ∈ ℕ → B ∈ ℝ
32 31 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℝ
33 nngt0 ⊢ B ∈ ℕ → 0 < B
34 33 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < B
35 32 18 34 21 divgt0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < B A gcd B
36 elnnz ⊢ B A gcd B ∈ ℕ ↔ B A gcd B ∈ ℤ ∧ 0 < B A gcd B
37 30 35 36 sylanbrc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B A gcd B ∈ ℕ
38 37 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → B A gcd B ∈ ℕ
39 dvdssq ⊢ A gcd B ∈ ℤ ∧ A ∈ ℤ → A gcd B ∥ A ↔ A gcd B 2 ∥ A 2
40 10 12 39 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ A ↔ A gcd B 2 ∥ A 2
41 dvdssq ⊢ A gcd B ∈ ℤ ∧ B ∈ ℤ → A gcd B ∥ B ↔ A gcd B 2 ∥ B 2
42 10 27 41 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ B ↔ A gcd B 2 ∥ B 2
43 40 42 anbi12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ A ∧ A gcd B ∥ B ↔ A gcd B 2 ∥ A 2 ∧ A gcd B 2 ∥ B 2
44 8 43 mpbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ∥ A 2 ∧ A gcd B 2 ∥ B 2
45 2 nnsqcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ∈ ℕ
46 45 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ∈ ℤ
47 nnsqcl ⊢ A ∈ ℕ → A 2 ∈ ℕ
48 47 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 ∈ ℕ
49 48 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 ∈ ℤ
50 nnsqcl ⊢ B ∈ ℕ → B 2 ∈ ℕ
51 50 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B 2 ∈ ℕ
52 51 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B 2 ∈ ℤ
53 dvds2add ⊢ A gcd B 2 ∈ ℤ ∧ A 2 ∈ ℤ ∧ B 2 ∈ ℤ → A gcd B 2 ∥ A 2 ∧ A gcd B 2 ∥ B 2 → A gcd B 2 ∥ A 2 + B 2
54 46 49 52 53 syl3anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ∥ A 2 ∧ A gcd B 2 ∥ B 2 → A gcd B 2 ∥ A 2 + B 2
55 44 54 mpd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ∥ A 2 + B 2
56 55 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A gcd B 2 ∥ A 2 + B 2
57 simpr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A 2 + B 2 = C 2
58 56 57 breqtrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A gcd B 2 ∥ C 2
59 nnz ⊢ C ∈ ℕ → C ∈ ℤ
60 59 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C ∈ ℤ
61 dvdssq ⊢ A gcd B ∈ ℤ ∧ C ∈ ℤ → A gcd B ∥ C ↔ A gcd B 2 ∥ C 2
62 10 60 61 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ C ↔ A gcd B 2 ∥ C 2
63 62 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A gcd B ∥ C ↔ A gcd B 2 ∥ C 2
64 58 63 mpbird ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A gcd B ∥ C
65 dvdsval2 ⊢ A gcd B ∈ ℤ ∧ A gcd B ≠ 0 ∧ C ∈ ℤ → A gcd B ∥ C ↔ C A gcd B ∈ ℤ
66 10 11 60 65 syl3anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∥ C ↔ C A gcd B ∈ ℤ
67 66 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → A gcd B ∥ C ↔ C A gcd B ∈ ℤ
68 64 67 mpbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → C A gcd B ∈ ℤ
69 nnre ⊢ C ∈ ℕ → C ∈ ℝ
70 69 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C ∈ ℝ
71 nngt0 ⊢ C ∈ ℕ → 0 < C
72 71 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < C
73 70 18 72 21 divgt0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → 0 < C A gcd B
74 73 adantr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → 0 < C A gcd B
75 elnnz ⊢ C A gcd B ∈ ℕ ↔ C A gcd B ∈ ℤ ∧ 0 < C A gcd B
76 68 74 75 sylanbrc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 → C A gcd B ∈ ℕ
77 76 3adant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → C A gcd B ∈ ℕ
78 48 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 ∈ ℂ
79 51 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B 2 ∈ ℂ
80 45 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ∈ ℂ
81 45 nnne0d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B 2 ≠ 0
82 78 79 80 81 divdird ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A 2 + B 2 A gcd B 2 = A 2 A gcd B 2 + B 2 A gcd B 2
83 82 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A 2 + B 2 A gcd B 2 = A 2 A gcd B 2 + B 2 A gcd B 2
84 nncn ⊢ C ∈ ℕ → C ∈ ℂ
85 84 3ad2ant3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C ∈ ℂ
86 2 nncnd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ∈ ℂ
87 85 86 11 sqdivd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C A gcd B 2 = C 2 A gcd B 2
88 87 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → C A gcd B 2 = C 2 A gcd B 2
89 oveq1 ⊢ A 2 + B 2 = C 2 → A 2 + B 2 A gcd B 2 = C 2 A gcd B 2
90 89 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A 2 + B 2 A gcd B 2 = C 2 A gcd B 2
91 88 90 eqtr4d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → C A gcd B 2 = A 2 + B 2 A gcd B 2
92 nncn ⊢ A ∈ ℕ → A ∈ ℂ
93 92 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A ∈ ℂ
94 93 86 11 sqdivd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A A gcd B 2 = A 2 A gcd B 2
95 nncn ⊢ B ∈ ℕ → B ∈ ℂ
96 95 3ad2ant2 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B ∈ ℂ
97 96 86 11 sqdivd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B A gcd B 2 = B 2 A gcd B 2
98 94 97 oveq12d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A A gcd B 2 + B A gcd B 2 = A 2 A gcd B 2 + B 2 A gcd B 2
99 98 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A A gcd B 2 + B A gcd B 2 = A 2 A gcd B 2 + B 2 A gcd B 2
100 83 91 99 3eqtr4rd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A A gcd B 2 + B A gcd B 2 = C A gcd B 2
101 gcddiv ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ A gcd B ∈ ℕ ∧ A gcd B ∥ A ∧ A gcd B ∥ B → A gcd B A gcd B = A A gcd B gcd B A gcd B
102 12 27 2 8 101 syl31anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B A gcd B = A A gcd B gcd B A gcd B
103 86 11 dividd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B A gcd B = 1
104 102 103 eqtr3d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A A gcd B gcd B A gcd B = 1
105 104 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A A gcd B gcd B A gcd B = 1
106 simp3 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ¬ 2 ∥ A A gcd B
107 pythagtriplem18 ⊢ A A gcd B ∈ ℕ ∧ B A gcd B ∈ ℕ ∧ C A gcd B ∈ ℕ ∧ A A gcd B 2 + B A gcd B 2 = C A gcd B 2 ∧ A A gcd B gcd B A gcd B = 1 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2
108 25 38 77 100 105 106 107 syl312anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2
109 93 86 11 divcan2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ⁢ A A gcd B = A
110 109 eqcomd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A = A gcd B ⁢ A A gcd B
111 96 86 11 divcan2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ⁢ B A gcd B = B
112 111 eqcomd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → B = A gcd B ⁢ B A gcd B
113 85 86 11 divcan2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A gcd B ⁢ C A gcd B = C
114 113 eqcomd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → C = A gcd B ⁢ C A gcd B
115 110 112 114 3jca ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ → A = A gcd B ⁢ A A gcd B ∧ B = A gcd B ⁢ B A gcd B ∧ C = A gcd B ⁢ C A gcd B
116 115 3ad2ant1 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A = A gcd B ⁢ A A gcd B ∧ B = A gcd B ⁢ B A gcd B ∧ C = A gcd B ⁢ C A gcd B
117 oveq2 ⊢ A A gcd B = m 2 − n 2 → A gcd B ⁢ A A gcd B = A gcd B ⁢ m 2 − n 2
118 117 eqeq2d ⊢ A A gcd B = m 2 − n 2 → A = A gcd B ⁢ A A gcd B ↔ A = A gcd B ⁢ m 2 − n 2
119 118 3ad2ant1 ⊢ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → A = A gcd B ⁢ A A gcd B ↔ A = A gcd B ⁢ m 2 − n 2
120 oveq2 ⊢ B A gcd B = 2 ⁢ m ⁢ n → A gcd B ⁢ B A gcd B = A gcd B ⁢ 2 ⁢ m ⁢ n
121 120 eqeq2d ⊢ B A gcd B = 2 ⁢ m ⁢ n → B = A gcd B ⁢ B A gcd B ↔ B = A gcd B ⁢ 2 ⁢ m ⁢ n
122 121 3ad2ant2 ⊢ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → B = A gcd B ⁢ B A gcd B ↔ B = A gcd B ⁢ 2 ⁢ m ⁢ n
123 oveq2 ⊢ C A gcd B = m 2 + n 2 → A gcd B ⁢ C A gcd B = A gcd B ⁢ m 2 + n 2
124 123 eqeq2d ⊢ C A gcd B = m 2 + n 2 → C = A gcd B ⁢ C A gcd B ↔ C = A gcd B ⁢ m 2 + n 2
125 124 3ad2ant3 ⊢ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → C = A gcd B ⁢ C A gcd B ↔ C = A gcd B ⁢ m 2 + n 2
126 119 122 125 3anbi123d ⊢ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → A = A gcd B ⁢ A A gcd B ∧ B = A gcd B ⁢ B A gcd B ∧ C = A gcd B ⁢ C A gcd B ↔ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
127 116 126 syl5ibcom ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
128 127 reximdv ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ m ∈ ℕ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → ∃ m ∈ ℕ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
129 128 reximdv ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ A A gcd B = m 2 − n 2 ∧ B A gcd B = 2 ⁢ m ⁢ n ∧ C A gcd B = m 2 + n 2 → ∃ n ∈ ℕ ∃ m ∈ ℕ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
130 108 129 mpd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
131 oveq1 ⊢ k = A gcd B → k ⁢ m 2 − n 2 = A gcd B ⁢ m 2 − n 2
132 131 eqeq2d ⊢ k = A gcd B → A = k ⁢ m 2 − n 2 ↔ A = A gcd B ⁢ m 2 − n 2
133 oveq1 ⊢ k = A gcd B → k ⁢ 2 ⁢ m ⁢ n = A gcd B ⁢ 2 ⁢ m ⁢ n
134 133 eqeq2d ⊢ k = A gcd B → B = k ⁢ 2 ⁢ m ⁢ n ↔ B = A gcd B ⁢ 2 ⁢ m ⁢ n
135 oveq1 ⊢ k = A gcd B → k ⁢ m 2 + n 2 = A gcd B ⁢ m 2 + n 2
136 135 eqeq2d ⊢ k = A gcd B → C = k ⁢ m 2 + n 2 ↔ C = A gcd B ⁢ m 2 + n 2
137 132 134 136 3anbi123d ⊢ k = A gcd B → A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
138 137 2rexbidv ⊢ k = A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2
139 138 rspcev ⊢ A gcd B ∈ ℕ ∧ ∃ n ∈ ℕ ∃ m ∈ ℕ A = A gcd B ⁢ m 2 − n 2 ∧ B = A gcd B ⁢ 2 ⁢ m ⁢ n ∧ C = A gcd B ⁢ m 2 + n 2 → ∃ k ∈ ℕ ∃ n ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
140 3 130 139 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ k ∈ ℕ ∃ n ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
141 rexcom ⊢ ∃ k ∈ ℕ ∃ n ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ k ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
142 rexcom ⊢ ∃ k ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
143 142 rexbii ⊢ ∃ n ∈ ℕ ∃ k ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
144 141 143 bitri ⊢ ∃ k ∈ ℕ ∃ n ∈ ℕ ∃ m ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2 ↔ ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2
145 140 144 sylib ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ ¬ 2 ∥ A A gcd B → ∃ n ∈ ℕ ∃ m ∈ ℕ ∃ k ∈ ℕ A = k ⁢ m 2 − n 2 ∧ B = k ⁢ 2 ⁢ m ⁢ n ∧ C = k ⁢ m 2 + n 2