Metamath Proof Explorer


Theorem qrngdiv

Description: The division operation in the field of rationals. (Contributed by Mario Carneiro, 8-Sep-2014)

Ref Expression
Hypothesis qrng.q ⊢ Q = ℂ fld ↾ 𝑠 ℚ
Assertion qrngdiv ⊢ X ∈ ℚ ∧ Y ∈ ℚ ∧ Y ≠ 0 → X / r ⁡ Q Y = X Y

Proof

Step Hyp Ref Expression
1 qrng.q ⊢ Q = ℂ fld ↾ 𝑠 ℚ
2 qsubdrg ⊢ ℚ ∈ SubRing ⁡ ℂ fld ∧ ℂ fld ↾ 𝑠 ℚ ∈ DivRing
3 2 simpli ⊢ ℚ ∈ SubRing ⁡ ℂ fld
4 simp1 ⊢ X ∈ ℚ ∧ Y ∈ ℚ ∧ Y ≠ 0 → X ∈ ℚ
5 3simpc ⊢ X ∈ ℚ ∧ Y ∈ ℚ ∧ Y ≠ 0 → Y ∈ ℚ ∧ Y ≠ 0
6 eldifsn ⊢ Y ∈ ℚ ∖ 0 ↔ Y ∈ ℚ ∧ Y ≠ 0
7 5 6 sylibr ⊢ X ∈ ℚ ∧ Y ∈ ℚ ∧ Y ≠ 0 → Y ∈ ℚ ∖ 0
8 cnflddiv ⊢ ÷ = / r ⁡ ℂ fld
9 1 qrngbas ⊢ ℚ = Base Q
10 1 qrng0 ⊢ 0 = 0 Q
11 1 qdrng ⊢ Q ∈ DivRing
12 9 10 11 drngui ⊢ ℚ ∖ 0 = Unit ⁡ Q
13 eqid ⊢ / r ⁡ Q = / r ⁡ Q
14 1 8 12 13 subrgdv ⊢ ℚ ∈ SubRing ⁡ ℂ fld ∧ X ∈ ℚ ∧ Y ∈ ℚ ∖ 0 → X Y = X / r ⁡ Q Y
15 3 4 7 14 mp3an2i ⊢ X ∈ ℚ ∧ Y ∈ ℚ ∧ Y ≠ 0 → X Y = X / r ⁡ Q Y
16 15 eqcomd ⊢ X ∈ ℚ ∧ Y ∈ ℚ ∧ Y ≠ 0 → X / r ⁡ Q Y = X Y