Metamath Proof Explorer


Theorem qtopss

Description: A surjective continuous function from J to K induces a topology J qTop F on the base set of K . This topology is in general finer than K . Together with qtopid , this implies that J qTop F is the finest topology making F continuous, i.e. the final topology with respect to the family { F } . (Contributed by Mario Carneiro, 24-Mar-2015)

Ref Expression
Assertion qtopss ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y → K ⊆ J qTop F

Proof

Step Hyp Ref Expression
1 toponss ⊢ K ∈ TopOn ⁡ Y ∧ x ∈ K → x ⊆ Y
2 1 3ad2antl2 ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → x ⊆ Y
3 cnima ⊢ F ∈ J Cn K ∧ x ∈ K → F -1 x ∈ J
4 3 3ad2antl1 ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → F -1 x ∈ J
5 simpl1 ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → F ∈ J Cn K
6 cntop1 ⊢ F ∈ J Cn K → J ∈ Top
7 5 6 syl ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → J ∈ Top
8 toptopon2 ⊢ J ∈ Top ↔ J ∈ TopOn ⁡ ⋃ J
9 7 8 sylib ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → J ∈ TopOn ⁡ ⋃ J
10 simpl2 ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → K ∈ TopOn ⁡ Y
11 cnf2 ⊢ J ∈ TopOn ⁡ ⋃ J ∧ K ∈ TopOn ⁡ Y ∧ F ∈ J Cn K → F : ⋃ J ⟶ Y
12 9 10 5 11 syl3anc ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → F : ⋃ J ⟶ Y
13 12 ffnd ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → F Fn ⋃ J
14 simpl3 ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → ran ⁡ F = Y
15 df-fo ⊢ F : ⋃ J ⟶ onto Y ↔ F Fn ⋃ J ∧ ran ⁡ F = Y
16 13 14 15 sylanbrc ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → F : ⋃ J ⟶ onto Y
17 elqtop3 ⊢ J ∈ TopOn ⁡ ⋃ J ∧ F : ⋃ J ⟶ onto Y → x ∈ J qTop F ↔ x ⊆ Y ∧ F -1 x ∈ J
18 9 16 17 syl2anc ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → x ∈ J qTop F ↔ x ⊆ Y ∧ F -1 x ∈ J
19 2 4 18 mpbir2and ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y ∧ x ∈ K → x ∈ J qTop F
20 19 ex ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y → x ∈ K → x ∈ J qTop F
21 20 ssrdv ⊢ F ∈ J Cn K ∧ K ∈ TopOn ⁡ Y ∧ ran ⁡ F = Y → K ⊆ J qTop F