Metamath Proof Explorer


Theorem quart1

Description: Depress a quartic equation. (Contributed by Mario Carneiro, 6-May-2015)

Ref Expression
Hypotheses quart1.a ⊢ φ → A ∈ ℂ
quart1.b ⊢ φ → B ∈ ℂ
quart1.c ⊢ φ → C ∈ ℂ
quart1.d ⊢ φ → D ∈ ℂ
quart1.p ⊢ φ → P = B − 3 8 ⁢ A 2
quart1.q ⊢ φ → Q = C - A ⁢ B 2 + A 3 8
quart1.r ⊢ φ → R = D − C ⁢ A 4 + A 2 ⁢ B 16 - 3 256 ⁢ A 4
quart1.x ⊢ φ → X ∈ ℂ
quart1.y ⊢ φ → Y = X + A 4
Assertion quart1 ⊢ φ → X 4 + A ⁢ X 3 + B ⁢ X 2 + C ⁢ X + D = Y 4 + P ⁢ Y 2 + Q ⁢ Y + R

Proof

Step Hyp Ref Expression
1 quart1.a ⊢ φ → A ∈ ℂ
2 quart1.b ⊢ φ → B ∈ ℂ
3 quart1.c ⊢ φ → C ∈ ℂ
4 quart1.d ⊢ φ → D ∈ ℂ
5 quart1.p ⊢ φ → P = B − 3 8 ⁢ A 2
6 quart1.q ⊢ φ → Q = C - A ⁢ B 2 + A 3 8
7 quart1.r ⊢ φ → R = D − C ⁢ A 4 + A 2 ⁢ B 16 - 3 256 ⁢ A 4
8 quart1.x ⊢ φ → X ∈ ℂ
9 quart1.y ⊢ φ → Y = X + A 4
10 9 oveq1d ⊢ φ → Y 4 = X + A 4 4
11 4cn ⊢ 4 ∈ ℂ
12 11 a1i ⊢ φ → 4 ∈ ℂ
13 4ne0 ⊢ 4 ≠ 0
14 13 a1i ⊢ φ → 4 ≠ 0
15 1 12 14 divcld ⊢ φ → A 4 ∈ ℂ
16 binom4 ⊢ X ∈ ℂ ∧ A 4 ∈ ℂ → X + A 4 4 = X 4 + 4 ⁢ X 3 ⁢ A 4 + 6 ⁢ X 2 ⁢ A 4 2 + 4 ⁢ X ⁢ A 4 3 + A 4 4
17 8 15 16 syl2anc ⊢ φ → X + A 4 4 = X 4 + 4 ⁢ X 3 ⁢ A 4 + 6 ⁢ X 2 ⁢ A 4 2 + 4 ⁢ X ⁢ A 4 3 + A 4 4
18 3nn0 ⊢ 3 ∈ ℕ 0
19 expcl ⊢ X ∈ ℂ ∧ 3 ∈ ℕ 0 → X 3 ∈ ℂ
20 8 18 19 sylancl ⊢ φ → X 3 ∈ ℂ
21 12 20 15 mul12d ⊢ φ → 4 ⁢ X 3 ⁢ A 4 = X 3 ⁢ 4 ⁢ A 4
22 1 12 14 divcan2d ⊢ φ → 4 ⁢ A 4 = A
23 22 oveq2d ⊢ φ → X 3 ⁢ 4 ⁢ A 4 = X 3 ⁢ A
24 20 1 mulcomd ⊢ φ → X 3 ⁢ A = A ⁢ X 3
25 21 23 24 3eqtrd ⊢ φ → 4 ⁢ X 3 ⁢ A 4 = A ⁢ X 3
26 25 oveq2d ⊢ φ → X 4 + 4 ⁢ X 3 ⁢ A 4 = X 4 + A ⁢ X 3
27 6nn ⊢ 6 ∈ ℕ
28 27 nncni ⊢ 6 ∈ ℂ
29 28 a1i ⊢ φ → 6 ∈ ℂ
30 15 sqcld ⊢ φ → A 4 2 ∈ ℂ
31 8 sqcld ⊢ φ → X 2 ∈ ℂ
32 29 30 31 mulassd ⊢ φ → 6 ⁢ A 4 2 ⁢ X 2 = 6 ⁢ A 4 2 ⁢ X 2
33 2t3e6 ⊢ 2 ⋅ 3 = 6
34 8cn ⊢ 8 ∈ ℂ
35 2cn ⊢ 2 ∈ ℂ
36 8t2e16 ⊢ 8 ⋅ 2 = 16
37 34 35 36 mulcomli ⊢ 2 ⋅ 8 = 16
38 33 37 oveq12i ⊢ 2 ⋅ 3 2 ⋅ 8 = 6 16
39 3cn ⊢ 3 ∈ ℂ
40 8nn ⊢ 8 ∈ ℕ
41 40 nnne0i ⊢ 8 ≠ 0
42 34 41 pm3.2i ⊢ 8 ∈ ℂ ∧ 8 ≠ 0
43 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
44 divcan5 ⊢ 3 ∈ ℂ ∧ 8 ∈ ℂ ∧ 8 ≠ 0 ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⋅ 3 2 ⋅ 8 = 3 8
45 39 42 43 44 mp3an ⊢ 2 ⋅ 3 2 ⋅ 8 = 3 8
46 38 45 eqtr3i ⊢ 6 16 = 3 8
47 46 oveq2i ⊢ A 2 ⁢ 6 16 = A 2 ⁢ 3 8
48 1 sqcld ⊢ φ → A 2 ∈ ℂ
49 1nn0 ⊢ 1 ∈ ℕ 0
50 49 27 decnncl ⊢ 16 ∈ ℕ
51 50 nncni ⊢ 16 ∈ ℂ
52 51 a1i ⊢ φ → 16 ∈ ℂ
53 50 nnne0i ⊢ 16 ≠ 0
54 53 a1i ⊢ φ → 16 ≠ 0
55 48 29 52 54 div12d ⊢ φ → A 2 ⁢ 6 16 = 6 ⁢ A 2 16
56 47 55 eqtr3id ⊢ φ → A 2 ⁢ 3 8 = 6 ⁢ A 2 16
57 39 34 41 divcli ⊢ 3 8 ∈ ℂ
58 mulcom ⊢ 3 8 ∈ ℂ ∧ A 2 ∈ ℂ → 3 8 ⁢ A 2 = A 2 ⁢ 3 8
59 57 48 58 sylancr ⊢ φ → 3 8 ⁢ A 2 = A 2 ⁢ 3 8
60 1 12 14 sqdivd ⊢ φ → A 4 2 = A 2 4 2
61 11 sqvali ⊢ 4 2 = 4 ⋅ 4
62 4t4e16 ⊢ 4 ⋅ 4 = 16
63 61 62 eqtri ⊢ 4 2 = 16
64 63 oveq2i ⊢ A 2 4 2 = A 2 16
65 60 64 eqtrdi ⊢ φ → A 4 2 = A 2 16
66 65 oveq2d ⊢ φ → 6 ⁢ A 4 2 = 6 ⁢ A 2 16
67 56 59 66 3eqtr4d ⊢ φ → 3 8 ⁢ A 2 = 6 ⁢ A 4 2
68 67 oveq1d ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 = 6 ⁢ A 4 2 ⁢ X 2
69 31 30 mulcomd ⊢ φ → X 2 ⁢ A 4 2 = A 4 2 ⁢ X 2
70 69 oveq2d ⊢ φ → 6 ⁢ X 2 ⁢ A 4 2 = 6 ⁢ A 4 2 ⁢ X 2
71 32 68 70 3eqtr4rd ⊢ φ → 6 ⁢ X 2 ⁢ A 4 2 = 3 8 ⁢ A 2 ⁢ X 2
72 expcl ⊢ A 4 ∈ ℂ ∧ 3 ∈ ℕ 0 → A 4 3 ∈ ℂ
73 15 18 72 sylancl ⊢ φ → A 4 3 ∈ ℂ
74 12 8 73 mul12d ⊢ φ → 4 ⁢ X ⁢ A 4 3 = X ⁢ 4 ⁢ A 4 3
75 12 73 mulcld ⊢ φ → 4 ⁢ A 4 3 ∈ ℂ
76 8 75 mulcomd ⊢ φ → X ⁢ 4 ⁢ A 4 3 = 4 ⁢ A 4 3 ⁢ X
77 df-3 ⊢ 3 = 2 + 1
78 77 oveq2i ⊢ 4 3 = 4 2 + 1
79 2nn0 ⊢ 2 ∈ ℕ 0
80 expp1 ⊢ 4 ∈ ℂ ∧ 2 ∈ ℕ 0 → 4 2 + 1 = 4 2 ⋅ 4
81 11 79 80 mp2an ⊢ 4 2 + 1 = 4 2 ⋅ 4
82 63 oveq1i ⊢ 4 2 ⋅ 4 = 16 ⋅ 4
83 78 81 82 3eqtri ⊢ 4 3 = 16 ⋅ 4
84 83 oveq2i ⊢ A 3 4 3 = A 3 16 ⋅ 4
85 18 a1i ⊢ φ → 3 ∈ ℕ 0
86 1 12 14 85 expdivd ⊢ φ → A 4 3 = A 3 4 3
87 expcl ⊢ A ∈ ℂ ∧ 3 ∈ ℕ 0 → A 3 ∈ ℂ
88 1 18 87 sylancl ⊢ φ → A 3 ∈ ℂ
89 88 52 12 54 14 divdiv1d ⊢ φ → A 3 16 4 = A 3 16 ⋅ 4
90 84 86 89 3eqtr4a ⊢ φ → A 4 3 = A 3 16 4
91 90 oveq2d ⊢ φ → 4 ⁢ A 4 3 = 4 ⁢ A 3 16 4
92 36 oveq2i ⊢ A 3 8 ⋅ 2 = A 3 16
93 34 a1i ⊢ φ → 8 ∈ ℂ
94 35 a1i ⊢ φ → 2 ∈ ℂ
95 41 a1i ⊢ φ → 8 ≠ 0
96 2ne0 ⊢ 2 ≠ 0
97 96 a1i ⊢ φ → 2 ≠ 0
98 88 93 94 95 97 divdiv1d ⊢ φ → A 3 8 2 = A 3 8 ⋅ 2
99 88 52 54 divcld ⊢ φ → A 3 16 ∈ ℂ
100 99 12 14 divcan2d ⊢ φ → 4 ⁢ A 3 16 4 = A 3 16
101 92 98 100 3eqtr4a ⊢ φ → A 3 8 2 = 4 ⁢ A 3 16 4
102 91 101 eqtr4d ⊢ φ → 4 ⁢ A 4 3 = A 3 8 2
103 102 oveq1d ⊢ φ → 4 ⁢ A 4 3 ⁢ X = A 3 8 2 ⁢ X
104 74 76 103 3eqtrd ⊢ φ → 4 ⁢ X ⁢ A 4 3 = A 3 8 2 ⁢ X
105 4nn0 ⊢ 4 ∈ ℕ 0
106 105 a1i ⊢ φ → 4 ∈ ℕ 0
107 1 12 14 106 expdivd ⊢ φ → A 4 4 = A 4 4 4
108 expmul ⊢ 2 ∈ ℂ ∧ 2 ∈ ℕ 0 ∧ 4 ∈ ℕ 0 → 2 2 ⋅ 4 = 2 2 4
109 35 79 105 108 mp3an ⊢ 2 2 ⋅ 4 = 2 2 4
110 2t4e8 ⊢ 2 ⋅ 4 = 8
111 110 oveq2i ⊢ 2 2 ⋅ 4 = 2 8
112 109 111 eqtr3i ⊢ 2 2 4 = 2 8
113 sq2 ⊢ 2 2 = 4
114 113 oveq1i ⊢ 2 2 4 = 4 4
115 112 114 eqtr3i ⊢ 2 8 = 4 4
116 2exp8 ⊢ 2 8 = 256
117 115 116 eqtr3i ⊢ 4 4 = 256
118 117 oveq2i ⊢ A 4 4 4 = A 4 256
119 107 118 eqtrdi ⊢ φ → A 4 4 = A 4 256
120 104 119 oveq12d ⊢ φ → 4 ⁢ X ⁢ A 4 3 + A 4 4 = A 3 8 2 ⁢ X + A 4 256
121 71 120 oveq12d ⊢ φ → 6 ⁢ X 2 ⁢ A 4 2 + 4 ⁢ X ⁢ A 4 3 + A 4 4 = 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256
122 26 121 oveq12d ⊢ φ → X 4 + 4 ⁢ X 3 ⁢ A 4 + 6 ⁢ X 2 ⁢ A 4 2 + 4 ⁢ X ⁢ A 4 3 + A 4 4 = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256
123 10 17 122 3eqtrd ⊢ φ → Y 4 = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256
124 123 oveq1d ⊢ φ → Y 4 + P ⁢ Y 2 = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2
125 expcl ⊢ X ∈ ℂ ∧ 4 ∈ ℕ 0 → X 4 ∈ ℂ
126 8 105 125 sylancl ⊢ φ → X 4 ∈ ℂ
127 1 20 mulcld ⊢ φ → A ⁢ X 3 ∈ ℂ
128 126 127 addcld ⊢ φ → X 4 + A ⁢ X 3 ∈ ℂ
129 mulcl ⊢ 3 8 ∈ ℂ ∧ A 2 ∈ ℂ → 3 8 ⁢ A 2 ∈ ℂ
130 57 48 129 sylancr ⊢ φ → 3 8 ⁢ A 2 ∈ ℂ
131 130 31 mulcld ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 ∈ ℂ
132 88 93 95 divcld ⊢ φ → A 3 8 ∈ ℂ
133 132 halfcld ⊢ φ → A 3 8 2 ∈ ℂ
134 133 8 mulcld ⊢ φ → A 3 8 2 ⁢ X ∈ ℂ
135 expcl ⊢ A ∈ ℂ ∧ 4 ∈ ℕ 0 → A 4 ∈ ℂ
136 1 105 135 sylancl ⊢ φ → A 4 ∈ ℂ
137 5nn0 ⊢ 5 ∈ ℕ 0
138 79 137 deccl ⊢ 25 ∈ ℕ 0
139 138 27 decnncl ⊢ 256 ∈ ℕ
140 139 nncni ⊢ 256 ∈ ℂ
141 140 a1i ⊢ φ → 256 ∈ ℂ
142 139 nnne0i ⊢ 256 ≠ 0
143 142 a1i ⊢ φ → 256 ≠ 0
144 136 141 143 divcld ⊢ φ → A 4 256 ∈ ℂ
145 134 144 addcld ⊢ φ → A 3 8 2 ⁢ X + A 4 256 ∈ ℂ
146 131 145 addcld ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 ∈ ℂ
147 1 2 3 4 5 6 7 quart1cl ⊢ φ → P ∈ ℂ ∧ Q ∈ ℂ ∧ R ∈ ℂ
148 147 simp1d ⊢ φ → P ∈ ℂ
149 8 15 addcld ⊢ φ → X + A 4 ∈ ℂ
150 9 149 eqeltrd ⊢ φ → Y ∈ ℂ
151 150 sqcld ⊢ φ → Y 2 ∈ ℂ
152 148 151 mulcld ⊢ φ → P ⁢ Y 2 ∈ ℂ
153 128 146 152 addassd ⊢ φ → X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2
154 124 153 eqtrd ⊢ φ → Y 4 + P ⁢ Y 2 = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2
155 154 oveq1d ⊢ φ → Y 4 + P ⁢ Y 2 + Q ⁢ Y + R = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 + Q ⁢ Y + R
156 146 152 addcld ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 ∈ ℂ
157 147 simp2d ⊢ φ → Q ∈ ℂ
158 157 150 mulcld ⊢ φ → Q ⁢ Y ∈ ℂ
159 147 simp3d ⊢ φ → R ∈ ℂ
160 158 159 addcld ⊢ φ → Q ⁢ Y + R ∈ ℂ
161 128 156 160 addassd ⊢ φ → X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 + Q ⁢ Y + R = X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 + Q ⁢ Y + R
162 9 oveq1d ⊢ φ → Y 2 = X + A 4 2
163 binom2 ⊢ X ∈ ℂ ∧ A 4 ∈ ℂ → X + A 4 2 = X 2 + 2 ⁢ X ⁢ A 4 + A 4 2
164 8 15 163 syl2anc ⊢ φ → X + A 4 2 = X 2 + 2 ⁢ X ⁢ A 4 + A 4 2
165 8 15 mulcld ⊢ φ → X ⁢ A 4 ∈ ℂ
166 mulcl ⊢ 2 ∈ ℂ ∧ X ⁢ A 4 ∈ ℂ → 2 ⁢ X ⁢ A 4 ∈ ℂ
167 35 165 166 sylancr ⊢ φ → 2 ⁢ X ⁢ A 4 ∈ ℂ
168 31 167 30 addassd ⊢ φ → X 2 + 2 ⁢ X ⁢ A 4 + A 4 2 = X 2 + 2 ⁢ X ⁢ A 4 + A 4 2
169 162 164 168 3eqtrd ⊢ φ → Y 2 = X 2 + 2 ⁢ X ⁢ A 4 + A 4 2
170 169 oveq2d ⊢ φ → P ⁢ Y 2 = P ⁢ X 2 + 2 ⁢ X ⁢ A 4 + A 4 2
171 167 30 addcld ⊢ φ → 2 ⁢ X ⁢ A 4 + A 4 2 ∈ ℂ
172 148 31 171 adddid ⊢ φ → P ⁢ X 2 + 2 ⁢ X ⁢ A 4 + A 4 2 = P ⁢ X 2 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2
173 170 172 eqtrd ⊢ φ → P ⁢ Y 2 = P ⁢ X 2 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2
174 173 oveq2d ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 = 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ X 2 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2
175 148 31 mulcld ⊢ φ → P ⁢ X 2 ∈ ℂ
176 148 171 mulcld ⊢ φ → P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 ∈ ℂ
177 131 145 175 176 add4d ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ X 2 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 = 3 8 ⁢ A 2 ⁢ X 2 + P ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2
178 130 148 31 adddird ⊢ φ → 3 8 ⁢ A 2 + P ⁢ X 2 = 3 8 ⁢ A 2 ⁢ X 2 + P ⁢ X 2
179 5 oveq2d ⊢ φ → 3 8 ⁢ A 2 + P = 3 8 ⁢ A 2 + B - 3 8 ⁢ A 2
180 130 2 pncan3d ⊢ φ → 3 8 ⁢ A 2 + B - 3 8 ⁢ A 2 = B
181 179 180 eqtrd ⊢ φ → 3 8 ⁢ A 2 + P = B
182 181 oveq1d ⊢ φ → 3 8 ⁢ A 2 + P ⁢ X 2 = B ⁢ X 2
183 178 182 eqtr3d ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + P ⁢ X 2 = B ⁢ X 2
184 183 oveq1d ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + P ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 = B ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2
185 174 177 184 3eqtrd ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 = B ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2
186 185 oveq1d ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 + Q ⁢ Y + R = B ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 + Q ⁢ Y + R
187 2 31 mulcld ⊢ φ → B ⁢ X 2 ∈ ℂ
188 145 176 addcld ⊢ φ → A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 ∈ ℂ
189 187 188 160 addassd ⊢ φ → B ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 + Q ⁢ Y + R = B ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 + Q ⁢ Y + R
190 1 2 mulcld ⊢ φ → A ⁢ B ∈ ℂ
191 190 halfcld ⊢ φ → A ⁢ B 2 ∈ ℂ
192 191 132 subcld ⊢ φ → A ⁢ B 2 − A 3 8 ∈ ℂ
193 192 8 mulcld ⊢ φ → A ⁢ B 2 − A 3 8 ⁢ X ∈ ℂ
194 148 30 mulcld ⊢ φ → P ⁢ A 4 2 ∈ ℂ
195 144 194 addcld ⊢ φ → A 4 256 + P ⁢ A 4 2 ∈ ℂ
196 157 8 mulcld ⊢ φ → Q ⁢ X ∈ ℂ
197 157 15 mulcld ⊢ φ → Q ⁢ A 4 ∈ ℂ
198 197 159 addcld ⊢ φ → Q ⁢ A 4 + R ∈ ℂ
199 193 195 196 198 add4d ⊢ φ → A ⁢ B 2 − A 3 8 ⁢ X + A 4 256 + P ⁢ A 4 2 + Q ⁢ X + Q ⁢ A 4 + R = A ⁢ B 2 − A 3 8 ⁢ X + Q ⁢ X + A 4 256 + P ⁢ A 4 2 + Q ⁢ A 4 + R
200 148 167 30 adddid ⊢ φ → P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 = P ⁢ 2 ⁢ X ⁢ A 4 + P ⁢ A 4 2
201 200 oveq2d ⊢ φ → A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 = A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + P ⁢ A 4 2
202 148 167 mulcld ⊢ φ → P ⁢ 2 ⁢ X ⁢ A 4 ∈ ℂ
203 134 144 202 194 add4d ⊢ φ → A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + P ⁢ A 4 2 = A 3 8 2 ⁢ X + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 256 + P ⁢ A 4 2
204 1 94 94 97 97 divdiv1d ⊢ φ → A 2 2 = A 2 ⋅ 2
205 2t2e4 ⊢ 2 ⋅ 2 = 4
206 205 oveq2i ⊢ A 2 ⋅ 2 = A 4
207 204 206 eqtrdi ⊢ φ → A 2 2 = A 4
208 207 oveq2d ⊢ φ → 2 ⁢ A 2 2 = 2 ⁢ A 4
209 1 halfcld ⊢ φ → A 2 ∈ ℂ
210 209 94 97 divcan2d ⊢ φ → 2 ⁢ A 2 2 = A 2
211 208 210 eqtr3d ⊢ φ → 2 ⁢ A 4 = A 2
212 211 oveq2d ⊢ φ → X ⁢ 2 ⁢ A 4 = X ⁢ A 2
213 8 209 mulcomd ⊢ φ → X ⁢ A 2 = A 2 ⁢ X
214 212 213 eqtrd ⊢ φ → X ⁢ 2 ⁢ A 4 = A 2 ⁢ X
215 214 oveq2d ⊢ φ → P ⁢ X ⁢ 2 ⁢ A 4 = P ⁢ A 2 ⁢ X
216 94 8 15 mul12d ⊢ φ → 2 ⁢ X ⁢ A 4 = X ⁢ 2 ⁢ A 4
217 216 oveq2d ⊢ φ → P ⁢ 2 ⁢ X ⁢ A 4 = P ⁢ X ⁢ 2 ⁢ A 4
218 148 209 8 mulassd ⊢ φ → P ⁢ A 2 ⁢ X = P ⁢ A 2 ⁢ X
219 215 217 218 3eqtr4d ⊢ φ → P ⁢ 2 ⁢ X ⁢ A 4 = P ⁢ A 2 ⁢ X
220 219 oveq2d ⊢ φ → A 3 8 2 ⁢ X + P ⁢ 2 ⁢ X ⁢ A 4 = A 3 8 2 ⁢ X + P ⁢ A 2 ⁢ X
221 148 209 mulcld ⊢ φ → P ⁢ A 2 ∈ ℂ
222 133 221 8 adddird ⊢ φ → A 3 8 2 + P ⁢ A 2 ⁢ X = A 3 8 2 ⁢ X + P ⁢ A 2 ⁢ X
223 5 oveq1d ⊢ φ → P ⁢ A 2 = B − 3 8 ⁢ A 2 ⁢ A 2
224 2 130 209 subdird ⊢ φ → B − 3 8 ⁢ A 2 ⁢ A 2 = B ⁢ A 2 − 3 8 ⁢ A 2 ⁢ A 2
225 2 1 94 97 divassd ⊢ φ → B ⁢ A 2 = B ⁢ A 2
226 2 1 mulcomd ⊢ φ → B ⁢ A = A ⁢ B
227 226 oveq1d ⊢ φ → B ⁢ A 2 = A ⁢ B 2
228 225 227 eqtr3d ⊢ φ → B ⁢ A 2 = A ⁢ B 2
229 77 oveq2i ⊢ A 3 = A 2 + 1
230 expp1 ⊢ A ∈ ℂ ∧ 2 ∈ ℕ 0 → A 2 + 1 = A 2 ⁢ A
231 1 79 230 sylancl ⊢ φ → A 2 + 1 = A 2 ⁢ A
232 229 231 eqtrid ⊢ φ → A 3 = A 2 ⁢ A
233 232 oveq2d ⊢ φ → 3 8 ⁢ A 3 = 3 8 ⁢ A 2 ⁢ A
234 39 a1i ⊢ φ → 3 ∈ ℂ
235 234 88 93 95 div23d ⊢ φ → 3 ⁢ A 3 8 = 3 8 ⁢ A 3
236 57 a1i ⊢ φ → 3 8 ∈ ℂ
237 236 48 1 mulassd ⊢ φ → 3 8 ⁢ A 2 ⁢ A = 3 8 ⁢ A 2 ⁢ A
238 233 235 237 3eqtr4rd ⊢ φ → 3 8 ⁢ A 2 ⁢ A = 3 ⁢ A 3 8
239 234 88 93 95 divassd ⊢ φ → 3 ⁢ A 3 8 = 3 ⁢ A 3 8
240 238 239 eqtrd ⊢ φ → 3 8 ⁢ A 2 ⁢ A = 3 ⁢ A 3 8
241 240 oveq1d ⊢ φ → 3 8 ⁢ A 2 ⁢ A 2 = 3 ⁢ A 3 8 2
242 130 1 94 97 divassd ⊢ φ → 3 8 ⁢ A 2 ⁢ A 2 = 3 8 ⁢ A 2 ⁢ A 2
243 234 132 94 97 divassd ⊢ φ → 3 ⁢ A 3 8 2 = 3 ⁢ A 3 8 2
244 241 242 243 3eqtr3d ⊢ φ → 3 8 ⁢ A 2 ⁢ A 2 = 3 ⁢ A 3 8 2
245 228 244 oveq12d ⊢ φ → B ⁢ A 2 − 3 8 ⁢ A 2 ⁢ A 2 = A ⁢ B 2 − 3 ⁢ A 3 8 2
246 223 224 245 3eqtrd ⊢ φ → P ⁢ A 2 = A ⁢ B 2 − 3 ⁢ A 3 8 2
247 246 oveq2d ⊢ φ → A 3 8 2 + P ⁢ A 2 = A 3 8 2 + A ⁢ B 2 - 3 ⁢ A 3 8 2
248 mulcl ⊢ 3 ∈ ℂ ∧ A 3 8 2 ∈ ℂ → 3 ⁢ A 3 8 2 ∈ ℂ
249 39 133 248 sylancr ⊢ φ → 3 ⁢ A 3 8 2 ∈ ℂ
250 133 191 249 addsub12d ⊢ φ → A 3 8 2 + A ⁢ B 2 - 3 ⁢ A 3 8 2 = A ⁢ B 2 + A 3 8 2 - 3 ⁢ A 3 8 2
251 191 249 133 subsub2d ⊢ φ → A ⁢ B 2 − 3 ⁢ A 3 8 2 − A 3 8 2 = A ⁢ B 2 + A 3 8 2 - 3 ⁢ A 3 8 2
252 133 mullidd ⊢ φ → 1 ⁢ A 3 8 2 = A 3 8 2
253 252 oveq2d ⊢ φ → 3 ⁢ A 3 8 2 − 1 ⁢ A 3 8 2 = 3 ⁢ A 3 8 2 − A 3 8 2
254 3m1e2 ⊢ 3 − 1 = 2
255 254 oveq1i ⊢ 3 − 1 ⁢ A 3 8 2 = 2 ⁢ A 3 8 2
256 1cnd ⊢ φ → 1 ∈ ℂ
257 234 256 133 subdird ⊢ φ → 3 − 1 ⁢ A 3 8 2 = 3 ⁢ A 3 8 2 − 1 ⁢ A 3 8 2
258 132 94 97 divcan2d ⊢ φ → 2 ⁢ A 3 8 2 = A 3 8
259 255 257 258 3eqtr3a ⊢ φ → 3 ⁢ A 3 8 2 − 1 ⁢ A 3 8 2 = A 3 8
260 253 259 eqtr3d ⊢ φ → 3 ⁢ A 3 8 2 − A 3 8 2 = A 3 8
261 260 oveq2d ⊢ φ → A ⁢ B 2 − 3 ⁢ A 3 8 2 − A 3 8 2 = A ⁢ B 2 − A 3 8
262 250 251 261 3eqtr2d ⊢ φ → A 3 8 2 + A ⁢ B 2 - 3 ⁢ A 3 8 2 = A ⁢ B 2 − A 3 8
263 247 262 eqtrd ⊢ φ → A 3 8 2 + P ⁢ A 2 = A ⁢ B 2 − A 3 8
264 263 oveq1d ⊢ φ → A 3 8 2 + P ⁢ A 2 ⁢ X = A ⁢ B 2 − A 3 8 ⁢ X
265 220 222 264 3eqtr2d ⊢ φ → A 3 8 2 ⁢ X + P ⁢ 2 ⁢ X ⁢ A 4 = A ⁢ B 2 − A 3 8 ⁢ X
266 265 oveq1d ⊢ φ → A 3 8 2 ⁢ X + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 256 + P ⁢ A 4 2 = A ⁢ B 2 − A 3 8 ⁢ X + A 4 256 + P ⁢ A 4 2
267 201 203 266 3eqtrd ⊢ φ → A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 = A ⁢ B 2 − A 3 8 ⁢ X + A 4 256 + P ⁢ A 4 2
268 9 oveq2d ⊢ φ → Q ⁢ Y = Q ⁢ X + A 4
269 157 8 15 adddid ⊢ φ → Q ⁢ X + A 4 = Q ⁢ X + Q ⁢ A 4
270 268 269 eqtrd ⊢ φ → Q ⁢ Y = Q ⁢ X + Q ⁢ A 4
271 270 oveq1d ⊢ φ → Q ⁢ Y + R = Q ⁢ X + Q ⁢ A 4 + R
272 196 197 159 addassd ⊢ φ → Q ⁢ X + Q ⁢ A 4 + R = Q ⁢ X + Q ⁢ A 4 + R
273 271 272 eqtrd ⊢ φ → Q ⁢ Y + R = Q ⁢ X + Q ⁢ A 4 + R
274 267 273 oveq12d ⊢ φ → A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 + Q ⁢ Y + R = A ⁢ B 2 − A 3 8 ⁢ X + A 4 256 + P ⁢ A 4 2 + Q ⁢ X + Q ⁢ A 4 + R
275 192 157 addcomd ⊢ φ → A ⁢ B 2 - A 3 8 + Q = Q + A ⁢ B 2 - A 3 8
276 6 oveq1d ⊢ φ → Q + A ⁢ B 2 - A 3 8 = C − A ⁢ B 2 + A 3 8 + A ⁢ B 2 − A 3 8
277 3 191 subcld ⊢ φ → C − A ⁢ B 2 ∈ ℂ
278 277 132 191 ppncand ⊢ φ → C − A ⁢ B 2 + A 3 8 + A ⁢ B 2 − A 3 8 = C - A ⁢ B 2 + A ⁢ B 2
279 3 191 npcand ⊢ φ → C - A ⁢ B 2 + A ⁢ B 2 = C
280 278 279 eqtrd ⊢ φ → C − A ⁢ B 2 + A 3 8 + A ⁢ B 2 − A 3 8 = C
281 275 276 280 3eqtrd ⊢ φ → A ⁢ B 2 - A 3 8 + Q = C
282 281 oveq1d ⊢ φ → A ⁢ B 2 - A 3 8 + Q ⁢ X = C ⁢ X
283 192 157 8 adddird ⊢ φ → A ⁢ B 2 - A 3 8 + Q ⁢ X = A ⁢ B 2 − A 3 8 ⁢ X + Q ⁢ X
284 282 283 eqtr3d ⊢ φ → C ⁢ X = A ⁢ B 2 − A 3 8 ⁢ X + Q ⁢ X
285 1 2 3 4 5 6 7 8 9 quart1lem ⊢ φ → D = A 4 256 + P ⁢ A 4 2 + Q ⁢ A 4 + R
286 284 285 oveq12d ⊢ φ → C ⁢ X + D = A ⁢ B 2 − A 3 8 ⁢ X + Q ⁢ X + A 4 256 + P ⁢ A 4 2 + Q ⁢ A 4 + R
287 199 274 286 3eqtr4d ⊢ φ → A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 + Q ⁢ Y + R = C ⁢ X + D
288 287 oveq2d ⊢ φ → B ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ 2 ⁢ X ⁢ A 4 + A 4 2 + Q ⁢ Y + R = B ⁢ X 2 + C ⁢ X + D
289 186 189 288 3eqtrd ⊢ φ → 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 + Q ⁢ Y + R = B ⁢ X 2 + C ⁢ X + D
290 289 oveq2d ⊢ φ → X 4 + A ⁢ X 3 + 3 8 ⁢ A 2 ⁢ X 2 + A 3 8 2 ⁢ X + A 4 256 + P ⁢ Y 2 + Q ⁢ Y + R = X 4 + A ⁢ X 3 + B ⁢ X 2 + C ⁢ X + D
291 155 161 290 3eqtrrd ⊢ φ → X 4 + A ⁢ X 3 + B ⁢ X 2 + C ⁢ X + D = Y 4 + P ⁢ Y 2 + Q ⁢ Y + R