Metamath Proof Explorer


Theorem quart1cl

Description: Closure lemmas for quart . (Contributed by Mario Carneiro, 7-May-2015)

Ref Expression
Hypotheses quart1.a ⊢ φ → A ∈ ℂ
quart1.b ⊢ φ → B ∈ ℂ
quart1.c ⊢ φ → C ∈ ℂ
quart1.d ⊢ φ → D ∈ ℂ
quart1.p ⊢ φ → P = B − 3 8 ⁢ A 2
quart1.q ⊢ φ → Q = C - A ⁢ B 2 + A 3 8
quart1.r ⊢ φ → R = D − C ⁢ A 4 + A 2 ⁢ B 16 - 3 256 ⁢ A 4
Assertion quart1cl ⊢ φ → P ∈ ℂ ∧ Q ∈ ℂ ∧ R ∈ ℂ

Proof

Step Hyp Ref Expression
1 quart1.a ⊢ φ → A ∈ ℂ
2 quart1.b ⊢ φ → B ∈ ℂ
3 quart1.c ⊢ φ → C ∈ ℂ
4 quart1.d ⊢ φ → D ∈ ℂ
5 quart1.p ⊢ φ → P = B − 3 8 ⁢ A 2
6 quart1.q ⊢ φ → Q = C - A ⁢ B 2 + A 3 8
7 quart1.r ⊢ φ → R = D − C ⁢ A 4 + A 2 ⁢ B 16 - 3 256 ⁢ A 4
8 3cn ⊢ 3 ∈ ℂ
9 8cn ⊢ 8 ∈ ℂ
10 8nn ⊢ 8 ∈ ℕ
11 10 nnne0i ⊢ 8 ≠ 0
12 8 9 11 divcli ⊢ 3 8 ∈ ℂ
13 1 sqcld ⊢ φ → A 2 ∈ ℂ
14 mulcl ⊢ 3 8 ∈ ℂ ∧ A 2 ∈ ℂ → 3 8 ⁢ A 2 ∈ ℂ
15 12 13 14 sylancr ⊢ φ → 3 8 ⁢ A 2 ∈ ℂ
16 2 15 subcld ⊢ φ → B − 3 8 ⁢ A 2 ∈ ℂ
17 5 16 eqeltrd ⊢ φ → P ∈ ℂ
18 1 2 mulcld ⊢ φ → A ⁢ B ∈ ℂ
19 18 halfcld ⊢ φ → A ⁢ B 2 ∈ ℂ
20 3 19 subcld ⊢ φ → C − A ⁢ B 2 ∈ ℂ
21 3nn0 ⊢ 3 ∈ ℕ 0
22 expcl ⊢ A ∈ ℂ ∧ 3 ∈ ℕ 0 → A 3 ∈ ℂ
23 1 21 22 sylancl ⊢ φ → A 3 ∈ ℂ
24 9 a1i ⊢ φ → 8 ∈ ℂ
25 11 a1i ⊢ φ → 8 ≠ 0
26 23 24 25 divcld ⊢ φ → A 3 8 ∈ ℂ
27 20 26 addcld ⊢ φ → C - A ⁢ B 2 + A 3 8 ∈ ℂ
28 6 27 eqeltrd ⊢ φ → Q ∈ ℂ
29 3 1 mulcld ⊢ φ → C ⁢ A ∈ ℂ
30 4cn ⊢ 4 ∈ ℂ
31 30 a1i ⊢ φ → 4 ∈ ℂ
32 4ne0 ⊢ 4 ≠ 0
33 32 a1i ⊢ φ → 4 ≠ 0
34 29 31 33 divcld ⊢ φ → C ⁢ A 4 ∈ ℂ
35 4 34 subcld ⊢ φ → D − C ⁢ A 4 ∈ ℂ
36 13 2 mulcld ⊢ φ → A 2 ⁢ B ∈ ℂ
37 1nn0 ⊢ 1 ∈ ℕ 0
38 6nn ⊢ 6 ∈ ℕ
39 37 38 decnncl ⊢ 16 ∈ ℕ
40 39 nncni ⊢ 16 ∈ ℂ
41 40 a1i ⊢ φ → 16 ∈ ℂ
42 39 nnne0i ⊢ 16 ≠ 0
43 42 a1i ⊢ φ → 16 ≠ 0
44 36 41 43 divcld ⊢ φ → A 2 ⁢ B 16 ∈ ℂ
45 25nn0 ⊢ 25 ∈ ℕ 0
46 45 38 decnncl ⊢ 256 ∈ ℕ
47 46 nncni ⊢ 256 ∈ ℂ
48 46 nnne0i ⊢ 256 ≠ 0
49 8 47 48 divcli ⊢ 3 256 ∈ ℂ
50 4nn0 ⊢ 4 ∈ ℕ 0
51 expcl ⊢ A ∈ ℂ ∧ 4 ∈ ℕ 0 → A 4 ∈ ℂ
52 1 50 51 sylancl ⊢ φ → A 4 ∈ ℂ
53 mulcl ⊢ 3 256 ∈ ℂ ∧ A 4 ∈ ℂ → 3 256 ⁢ A 4 ∈ ℂ
54 49 52 53 sylancr ⊢ φ → 3 256 ⁢ A 4 ∈ ℂ
55 44 54 subcld ⊢ φ → A 2 ⁢ B 16 − 3 256 ⁢ A 4 ∈ ℂ
56 35 55 addcld ⊢ φ → D − C ⁢ A 4 + A 2 ⁢ B 16 - 3 256 ⁢ A 4 ∈ ℂ
57 7 56 eqeltrd ⊢ φ → R ∈ ℂ
58 17 28 57 3jca ⊢ φ → P ∈ ℂ ∧ Q ∈ ℂ ∧ R ∈ ℂ