Metamath Proof Explorer


Theorem qusrhm

Description: If S is a two-sided ideal in R , then the "natural map" from elements to their cosets is a ring homomorphism from R to R / S . (Contributed by Mario Carneiro, 15-Jun-2015)

Ref Expression
Hypotheses qusring.u ⊢ U = R / 𝑠 R ~ QG S
qusring.i ⊢ I = 2Ideal ⁡ R
qusrhm.x ⊢ X = Base R
qusrhm.f ⊢ F = x ∈ X ⟼ x R ~ QG S
Assertion qusrhm ⊢ R ∈ Ring ∧ S ∈ I → F ∈ R RingHom U

Proof

Step Hyp Ref Expression
1 qusring.u ⊢ U = R / 𝑠 R ~ QG S
2 qusring.i ⊢ I = 2Ideal ⁡ R
3 qusrhm.x ⊢ X = Base R
4 qusrhm.f ⊢ F = x ∈ X ⟼ x R ~ QG S
5 eqid ⊢ 1 R = 1 R
6 eqid ⊢ 1 U = 1 U
7 eqid ⊢ ⋅ R = ⋅ R
8 eqid ⊢ ⋅ U = ⋅ U
9 simpl ⊢ R ∈ Ring ∧ S ∈ I → R ∈ Ring
10 1 2 qusring ⊢ R ∈ Ring ∧ S ∈ I → U ∈ Ring
11 eqid ⊢ LIdeal ⁡ R = LIdeal ⁡ R
12 eqid ⊢ opp r ⁡ R = opp r ⁡ R
13 eqid ⊢ LIdeal ⁡ opp r ⁡ R = LIdeal ⁡ opp r ⁡ R
14 11 12 13 2 2idlval ⊢ I = LIdeal ⁡ R ∩ LIdeal ⁡ opp r ⁡ R
15 14 elin2 ⊢ S ∈ I ↔ S ∈ LIdeal ⁡ R ∧ S ∈ LIdeal ⁡ opp r ⁡ R
16 15 simplbi ⊢ S ∈ I → S ∈ LIdeal ⁡ R
17 11 lidlsubg ⊢ R ∈ Ring ∧ S ∈ LIdeal ⁡ R → S ∈ SubGrp ⁡ R
18 16 17 sylan2 ⊢ R ∈ Ring ∧ S ∈ I → S ∈ SubGrp ⁡ R
19 eqid ⊢ R ~ QG S = R ~ QG S
20 3 19 eqger ⊢ S ∈ SubGrp ⁡ R → R ~ QG S Er X
21 18 20 syl ⊢ R ∈ Ring ∧ S ∈ I → R ~ QG S Er X
22 3 fvexi ⊢ X ∈ V
23 22 a1i ⊢ R ∈ Ring ∧ S ∈ I → X ∈ V
24 21 23 4 divsfval ⊢ R ∈ Ring ∧ S ∈ I → F ⁡ 1 R = 1 R R ~ QG S
25 1 2 5 qus1 ⊢ R ∈ Ring ∧ S ∈ I → U ∈ Ring ∧ 1 R R ~ QG S = 1 U
26 25 simprd ⊢ R ∈ Ring ∧ S ∈ I → 1 R R ~ QG S = 1 U
27 24 26 eqtrd ⊢ R ∈ Ring ∧ S ∈ I → F ⁡ 1 R = 1 U
28 1 a1i ⊢ R ∈ Ring ∧ S ∈ I → U = R / 𝑠 R ~ QG S
29 3 a1i ⊢ R ∈ Ring ∧ S ∈ I → X = Base R
30 3 19 2 7 2idlcpbl ⊢ R ∈ Ring ∧ S ∈ I → a R ~ QG S c ∧ b R ~ QG S d → a ⋅ R b R ~ QG S c ⋅ R d
31 3 7 ringcl ⊢ R ∈ Ring ∧ y ∈ X ∧ z ∈ X → y ⋅ R z ∈ X
32 31 3expb ⊢ R ∈ Ring ∧ y ∈ X ∧ z ∈ X → y ⋅ R z ∈ X
33 32 adantlr ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → y ⋅ R z ∈ X
34 33 caovclg ⊢ R ∈ Ring ∧ S ∈ I ∧ c ∈ X ∧ d ∈ X → c ⋅ R d ∈ X
35 28 29 21 9 30 34 7 8 qusmulval ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → y R ~ QG S ⋅ U z R ~ QG S = y ⋅ R z R ~ QG S
36 35 3expb ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → y R ~ QG S ⋅ U z R ~ QG S = y ⋅ R z R ~ QG S
37 21 adantr ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → R ~ QG S Er X
38 22 a1i ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → X ∈ V
39 37 38 4 divsfval ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → F ⁡ y = y R ~ QG S
40 37 38 4 divsfval ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → F ⁡ z = z R ~ QG S
41 39 40 oveq12d ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → F ⁡ y ⋅ U F ⁡ z = y R ~ QG S ⋅ U z R ~ QG S
42 37 38 4 divsfval ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → F ⁡ y ⋅ R z = y ⋅ R z R ~ QG S
43 36 41 42 3eqtr4rd ⊢ R ∈ Ring ∧ S ∈ I ∧ y ∈ X ∧ z ∈ X → F ⁡ y ⋅ R z = F ⁡ y ⋅ U F ⁡ z
44 ringabl ⊢ R ∈ Ring → R ∈ Abel
45 44 adantr ⊢ R ∈ Ring ∧ S ∈ I → R ∈ Abel
46 ablnsg ⊢ R ∈ Abel → NrmSGrp ⁡ R = SubGrp ⁡ R
47 45 46 syl ⊢ R ∈ Ring ∧ S ∈ I → NrmSGrp ⁡ R = SubGrp ⁡ R
48 18 47 eleqtrrd ⊢ R ∈ Ring ∧ S ∈ I → S ∈ NrmSGrp ⁡ R
49 3 1 4 qusghm ⊢ S ∈ NrmSGrp ⁡ R → F ∈ R GrpHom U
50 48 49 syl ⊢ R ∈ Ring ∧ S ∈ I → F ∈ R GrpHom U
51 3 5 6 7 8 9 10 27 43 50 isrhm2d ⊢ R ∈ Ring ∧ S ∈ I → F ∈ R RingHom U