Metamath Proof Explorer


Theorem r1ord3g

Description: Ordering relation for the cumulative hierarchy of sets. Part of Theorem 3.3(i) of BellMachover p. 478. (Contributed by NM, 22-Sep-2003)

Ref Expression
Assertion r1ord3g ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ⊆ B → R1 ⁡ A ⊆ R1 ⁡ B

Proof

Step Hyp Ref Expression
1 r1funlim ⊢ Fun ⁡ R1 ∧ Lim ⁡ dom ⁡ R1
2 1 simpri ⊢ Lim ⁡ dom ⁡ R1
3 limord ⊢ Lim ⁡ dom ⁡ R1 → Ord ⁡ dom ⁡ R1
4 ordsson ⊢ Ord ⁡ dom ⁡ R1 → dom ⁡ R1 ⊆ On
5 2 3 4 mp2b ⊢ dom ⁡ R1 ⊆ On
6 5 sseli ⊢ A ∈ dom ⁡ R1 → A ∈ On
7 5 sseli ⊢ B ∈ dom ⁡ R1 → B ∈ On
8 onsseleq ⊢ A ∈ On ∧ B ∈ On → A ⊆ B ↔ A ∈ B ∨ A = B
9 6 7 8 syl2an ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ⊆ B ↔ A ∈ B ∨ A = B
10 r1tr ⊢ Tr ⁡ R1 ⁡ B
11 r1ordg ⊢ B ∈ dom ⁡ R1 → A ∈ B → R1 ⁡ A ∈ R1 ⁡ B
12 11 adantl ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ∈ B → R1 ⁡ A ∈ R1 ⁡ B
13 trss ⊢ Tr ⁡ R1 ⁡ B → R1 ⁡ A ∈ R1 ⁡ B → R1 ⁡ A ⊆ R1 ⁡ B
14 10 12 13 mpsylsyld ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ∈ B → R1 ⁡ A ⊆ R1 ⁡ B
15 fveq2 ⊢ A = B → R1 ⁡ A = R1 ⁡ B
16 eqimss ⊢ R1 ⁡ A = R1 ⁡ B → R1 ⁡ A ⊆ R1 ⁡ B
17 15 16 syl ⊢ A = B → R1 ⁡ A ⊆ R1 ⁡ B
18 17 a1i ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A = B → R1 ⁡ A ⊆ R1 ⁡ B
19 14 18 jaod ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ∈ B ∨ A = B → R1 ⁡ A ⊆ R1 ⁡ B
20 9 19 sylbid ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ⊆ B → R1 ⁡ A ⊆ R1 ⁡ B