Metamath Proof Explorer


Theorem r1p0

Description: Polynomial remainder operation of a division of the zero polynomial. (Contributed by Thierry Arnoux, 2-Apr-2025)

Ref Expression
Hypotheses r1padd1.p ⊢ P = Poly 1 ⁡ R
r1padd1.u ⊢ U = Base P
r1padd1.n ⊢ N = Unic 1p ⁡ R
r1padd1.e ⊢ E = rem 1p ⁡ R
r1p0.r ⊢ φ → R ∈ Ring
r1p0.d ⊢ φ → D ∈ N
r1p0.0 ⊢ 0 ˙ = 0 P
Assertion r1p0 ⊢ φ → 0 ˙ E D = 0 ˙

Proof

Step Hyp Ref Expression
1 r1padd1.p ⊢ P = Poly 1 ⁡ R
2 r1padd1.u ⊢ U = Base P
3 r1padd1.n ⊢ N = Unic 1p ⁡ R
4 r1padd1.e ⊢ E = rem 1p ⁡ R
5 r1p0.r ⊢ φ → R ∈ Ring
6 r1p0.d ⊢ φ → D ∈ N
7 r1p0.0 ⊢ 0 ˙ = 0 P
8 1 ply1sca ⊢ R ∈ Ring → R = Scalar ⁡ P
9 5 8 syl ⊢ φ → R = Scalar ⁡ P
10 9 fveq2d ⊢ φ → 0 R = 0 Scalar ⁡ P
11 10 oveq1d ⊢ φ → 0 R ⋅ P 0 ˙ = 0 Scalar ⁡ P ⋅ P 0 ˙
12 1 ply1lmod ⊢ R ∈ Ring → P ∈ LMod
13 5 12 syl ⊢ φ → P ∈ LMod
14 1 ply1ring ⊢ R ∈ Ring → P ∈ Ring
15 2 7 ring0cl ⊢ P ∈ Ring → 0 ˙ ∈ U
16 5 14 15 3syl ⊢ φ → 0 ˙ ∈ U
17 eqid ⊢ Scalar ⁡ P = Scalar ⁡ P
18 eqid ⊢ ⋅ P = ⋅ P
19 eqid ⊢ 0 Scalar ⁡ P = 0 Scalar ⁡ P
20 2 17 18 19 7 lmod0vs ⊢ P ∈ LMod ∧ 0 ˙ ∈ U → 0 Scalar ⁡ P ⋅ P 0 ˙ = 0 ˙
21 13 16 20 syl2anc ⊢ φ → 0 Scalar ⁡ P ⋅ P 0 ˙ = 0 ˙
22 11 21 eqtrd ⊢ φ → 0 R ⋅ P 0 ˙ = 0 ˙
23 22 oveq1d ⊢ φ → 0 R ⋅ P 0 ˙ E D = 0 ˙ E D
24 eqid ⊢ Base R = Base R
25 eqid ⊢ 0 R = 0 R
26 24 25 ring0cl ⊢ R ∈ Ring → 0 R ∈ Base R
27 5 26 syl ⊢ φ → 0 R ∈ Base R
28 1 2 3 4 5 16 6 18 24 27 r1pvsca ⊢ φ → 0 R ⋅ P 0 ˙ E D = 0 R ⋅ P 0 ˙ E D
29 10 oveq1d ⊢ φ → 0 R ⋅ P 0 ˙ E D = 0 Scalar ⁡ P ⋅ P 0 ˙ E D
30 4 1 2 3 r1pcl ⊢ R ∈ Ring ∧ 0 ˙ ∈ U ∧ D ∈ N → 0 ˙ E D ∈ U
31 5 16 6 30 syl3anc ⊢ φ → 0 ˙ E D ∈ U
32 2 17 18 19 7 lmod0vs ⊢ P ∈ LMod ∧ 0 ˙ E D ∈ U → 0 Scalar ⁡ P ⋅ P 0 ˙ E D = 0 ˙
33 13 31 32 syl2anc ⊢ φ → 0 Scalar ⁡ P ⋅ P 0 ˙ E D = 0 ˙
34 28 29 33 3eqtrd ⊢ φ → 0 R ⋅ P 0 ˙ E D = 0 ˙
35 23 34 eqtr3d ⊢ φ → 0 ˙ E D = 0 ˙