Metamath Proof Explorer


Theorem reclt0

Description: The reciprocal of a negative number is negative. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypotheses reclt0.1 ⊢ φ → A ∈ ℝ
reclt0.2 ⊢ φ → A ≠ 0
Assertion reclt0 ⊢ φ → A < 0 ↔ 1 A < 0

Proof

Step Hyp Ref Expression
1 reclt0.1 ⊢ φ → A ∈ ℝ
2 reclt0.2 ⊢ φ → A ≠ 0
3 1 adantr ⊢ φ ∧ A < 0 → A ∈ ℝ
4 simpr ⊢ φ ∧ A < 0 → A < 0
5 3 4 reclt0d ⊢ φ ∧ A < 0 → 1 A < 0
6 5 ex ⊢ φ → A < 0 → 1 A < 0
7 0red ⊢ φ ∧ ¬ A < 0 → 0 ∈ ℝ
8 1 adantr ⊢ φ ∧ ¬ A < 0 → A ∈ ℝ
9 2 necomd ⊢ φ → 0 ≠ A
10 9 adantr ⊢ φ ∧ ¬ A < 0 → 0 ≠ A
11 simpr ⊢ φ ∧ ¬ A < 0 → ¬ A < 0
12 7 8 10 11 lttri5d ⊢ φ ∧ ¬ A < 0 → 0 < A
13 0red ⊢ φ ∧ 0 < A → 0 ∈ ℝ
14 1 2 rereccld ⊢ φ → 1 A ∈ ℝ
15 14 adantr ⊢ φ ∧ 0 < A → 1 A ∈ ℝ
16 1 adantr ⊢ φ ∧ 0 < A → A ∈ ℝ
17 simpr ⊢ φ ∧ 0 < A → 0 < A
18 16 17 recgt0d ⊢ φ ∧ 0 < A → 0 < 1 A
19 13 15 18 ltled ⊢ φ ∧ 0 < A → 0 ≤ 1 A
20 13 15 lenltd ⊢ φ ∧ 0 < A → 0 ≤ 1 A ↔ ¬ 1 A < 0
21 19 20 mpbid ⊢ φ ∧ 0 < A → ¬ 1 A < 0
22 12 21 syldan ⊢ φ ∧ ¬ A < 0 → ¬ 1 A < 0
23 22 ex ⊢ φ → ¬ A < 0 → ¬ 1 A < 0
24 23 con4d ⊢ φ → 1 A < 0 → A < 0
25 24 imp ⊢ φ ∧ 1 A < 0 → A < 0
26 25 ex ⊢ φ → 1 A < 0 → A < 0
27 6 26 impbid ⊢ φ → A < 0 ↔ 1 A < 0