Metamath Proof Explorer


Theorem recnprss

Description: Both RR and CC are subsets of CC . (Contributed by Mario Carneiro, 10-Feb-2015)

Ref Expression
Assertion recnprss ⊢ S ∈ ℝ ℂ → S ⊆ ℂ

Proof

Step Hyp Ref Expression
1 elpri ⊢ S ∈ ℝ ℂ → S = ℝ ∨ S = ℂ
2 ax-resscn ⊢ ℝ ⊆ ℂ
3 sseq1 ⊢ S = ℝ → S ⊆ ℂ ↔ ℝ ⊆ ℂ
4 2 3 mpbiri ⊢ S = ℝ → S ⊆ ℂ
5 eqimss ⊢ S = ℂ → S ⊆ ℂ
6 4 5 jaoi ⊢ S = ℝ ∨ S = ℂ → S ⊆ ℂ
7 1 6 syl ⊢ S ∈ ℝ ℂ → S ⊆ ℂ