Metamath Proof Explorer


Theorem reglogexp

Description: Power law for general log. (Contributed by Stefan O'Rear, 19-Sep-2014) (New usage is discouraged.) Use relogbzexp instead.

Ref Expression
Assertion reglogexp ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ A N log ⁡ C = N ⁢ log ⁡ A log ⁡ C

Proof

Step Hyp Ref Expression
1 relogexp ⊢ A ∈ ℝ + ∧ N ∈ ℤ → log ⁡ A N = N ⁢ log ⁡ A
2 1 3adant3 ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ A N = N ⁢ log ⁡ A
3 2 oveq1d ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ A N log ⁡ C = N ⁢ log ⁡ A log ⁡ C
4 zcn ⊢ N ∈ ℤ → N ∈ ℂ
5 4 3ad2ant2 ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → N ∈ ℂ
6 relogcl ⊢ A ∈ ℝ + → log ⁡ A ∈ ℝ
7 6 recnd ⊢ A ∈ ℝ + → log ⁡ A ∈ ℂ
8 7 3ad2ant1 ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ A ∈ ℂ
9 relogcl ⊢ C ∈ ℝ + → log ⁡ C ∈ ℝ
10 9 recnd ⊢ C ∈ ℝ + → log ⁡ C ∈ ℂ
11 10 adantr ⊢ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ C ∈ ℂ
12 11 3ad2ant3 ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ C ∈ ℂ
13 logne0 ⊢ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ C ≠ 0
14 13 3ad2ant3 ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ C ≠ 0
15 5 8 12 14 divassd ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → N ⁢ log ⁡ A log ⁡ C = N ⁢ log ⁡ A log ⁡ C
16 3 15 eqtrd ⊢ A ∈ ℝ + ∧ N ∈ ℤ ∧ C ∈ ℝ + ∧ C ≠ 1 → log ⁡ A N log ⁡ C = N ⁢ log ⁡ A log ⁡ C