Metamath Proof Explorer


Theorem releqi

Description: Equality inference for the relation predicate. (Contributed by NM, 8-Dec-2006)

Ref Expression
Hypothesis releqi.1 A = B
Assertion releqi Rel A Rel B

Proof

Step Hyp Ref Expression
1 releqi.1 A = B
2 releq A = B Rel A Rel B
3 1 2 ax-mp Rel A Rel B