Metamath Proof Explorer


Theorem relfull

Description: The set of full functors is a relation. (Contributed by Mario Carneiro, 26-Jan-2017)

Ref Expression
Assertion relfull ⊢ Rel ⁡ C Full D

Proof

Step Hyp Ref Expression
1 fullfunc ⊢ C Full D ⊆ C Func D
2 relfunc ⊢ Rel ⁡ C Func D
3 relss ⊢ C Full D ⊆ C Func D → Rel ⁡ C Func D → Rel ⁡ C Full D
4 1 2 3 mp2 ⊢ Rel ⁡ C Full D